... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0. 025 1 0.036 1 0 .2 19 8 0 .2 19 8 0 .2 19 8 ... 0.0 31 I 0.0 31 1 0 .26 49 0 .26 49 3. 72 4 .25 7.44 8.50 14 .88 17 .00 3.54 7.09 14 .17 2. 853 5.705 0 .1 17 0 .23 4 0.0933 0 .15 34 0 .18...
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... 95 -1 02. Vol. 19 9(C2), pp. 10 3 -1 11 . 29 8-307. Vol. 2, pp. 52- 58. 19 68, pp. 23 3 -23 9. Design of Fluid Film Bearings 24 7 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . 18 . 19 . ... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0....
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 docx
... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 94,703, 189,406 ,28 4,109, and 378,8 12 N/m; the slide/roll ratios were 0,0.08,0.154,0 .22 2,0.345; the rolling speeds varied from 0.3 to 2. 76 m/s, and the sliding spee...
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 doc
... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 7 .2 Material Properties Steel 43 7800 473 20 3.4 Copper 40 1 8930 386 103 Chromium 94 7135 450 25 0 Tin 67 728 0 22 2 46 10W30 0.145 888 1880 - Rolling/ Sli...
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Friction and Lubrication in Mechanical Design Episode 2 Part 3 docx
... 0. 03 pm (12pin.), W = 37 8,812N/m (21 601bf /in. ), 10W30 oil, U1 = 3 .2 m/sec ( 126 in. /sec), R = 0. 0 23 4 m (0. 92 in. ). Figure 7 .38 shows calculated coefficient of friction versus sliding/ ... and Es for AT, K1, c1, p1, El and K2, c2, p2, E2 in Eqs. (7 .27 ) and (7 .28 ), where f is replaced byf,, L is replaced by L = 32 J'm. 2....
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx
... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... Dry 32 1 Dry 44 0 c Dry 0. 54 0.09 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0...
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx
... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0 .20 0.78 0 .20 0 .23 0. 54 0.13 0 .20 0....
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Friction and Lubrication in Mechanical Design Episode 2 Part 5 doc
... radial roller bearings. As outlined by Jones [39], the centrifugal Wear 33 7 13. 14. 15. 16. 17. 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. Blok, ... 20 0 SINK TEMPERATURE 4oo 120 0 - f 1400- 1600- v) 1800- W a 5 20 00- w (3 22 00 - 24 00 - 26 00 - 28 00 - 3000 Figure 9 .2 Design chart for ge...
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Friction and Lubrication in Mechanical Design Episode 2 Part 7 ppsx
... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under the fretting contact ... Torque =22 .6‘( 1 -cos (2* pi’ft)) /2 N-m =20 0’(1 -ws(P*pi’ft))l2 Ib -in 0 0 0.1 0 .2 0.3 0.4 0.5 0.6 0 .7 0.8 0.9 1 Time (sec) Figure 9.41 Fretting wear p...
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Friction and Lubrication in Mechanical Design Episode 2 Part 8 ppsx
... 17. 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. 35. Kannel, J. W., Bell, J. C., and Allen, C. M., “Methods for Determining Pressure Distributions in Lubricated ... “Fretting Corrosion of Mild Steel in Air and in Nitrogen,” J. Appl. Mech., 1954, Vol. 21 , p. 395. 183 , pp. 723 - 729 . pp. 20 3 -22 4. 1949, V...
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Friction and Lubrication in Mechanical Design Episode 2 Part 9 pps
... conditions are given in Table 11 .2. Figure 11,s Contact model. 4 52 Chapter II 8. 9. 10. 1 I. 12. 13. 14. 15. 16. 17. 18. 19. 20 . 21 22 . 23 . 24 . 25 . Symmons, G., and McNulty, ... constant 4 32 Chapter 11 Table 1 1 .2 Roughness Conditions Surface finishing rms roughness 0 Slope of the roughness process (clin.) profile 1 Fine grinding 2...
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Friction and Lubrication in Mechanical Design Episode 2 Part 9 pptx
... Surface finishing rms roughness 0 Slope of the roughness process (clin.) profile 1 Fine grinding 2. 74 2 Rough grinding 21 .5 3 Lapping 3. 92 4 Polishing 1.70 5 Shot peening 45 .9 0.01471 ... stiffness, and damping coefficient of the vibrating system by summing the inertia, damp- ing, and restoring forces at each increment of the friction- induced cycle. In 197...
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Friction and Lubrication in Mechanical Design Episode 2 Part 10 pps
... machine tools with TIN. The process starts by placing parts in a chamber and heating to 100 0°C. In a few hours, the parts reach a uniform temperature. Gaseous chemicals are introduced into ... generated in a contact pro- blem such as a semi-infinite cylinder rolling and sliding over a semi-infinite planar surface. As discussed in Chapter 5, Rashid and Seireg [l llob...
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Friction and Lubrication in Mechanical Design Episode 2 Part 10 ppsx
... (aerospace), piston rings, valves Bearings and seals, piston rings, cylinders liners, and crosshead pins in internal combustion engines and compressors, cannon and gun tubes, metalworking tools, tape-path ... generated in a contact pro- blem such as a semi-infinite cylinder rolling and sliding over a semi-infinite planar surface. As discussed in Chapter 5, Rashid an...
Ngày tải lên: 05/08/2014, 09:20