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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 1 potx

Friction and Lubrication in Mechanical Design Episode 2 Part 1 potx

... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0. 025 1 0.036 1 0 .2 19 8 0 .2 19 8 0 .2 19 8 ... 0.0 31 I 0.0 31 1 0 .26 49 0 .26 49 3. 72 4 .25 7.44 8.50 14 .88 17 .00 3.54 7.09 14 .17 2. 853 5.705 0 .1 17 0 .23 4 0.0933 0 .15 34 0 .18 67 0.3069 0.3734 0. 613 7 0.779 1. 557 3 .11 5 0.089 ... 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . 18 . 19 . 20 . 21 . 22 . Badgley, R. H., and Booker, J. F., “Rigid-Body Rotor Dynamics: Dynamic Unbalance and Lubrication Temperature...
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Friction and Lubrication in Mechanical Design Episode 2 Part 1 docx

Friction and Lubrication in Mechanical Design Episode 2 Part 1 docx

... 95 -1 02. Vol. 19 9(C2), pp. 10 3 -1 11 . 29 8-307. Vol. 2, pp. 52- 58. 19 68, pp. 23 3 -23 9. Design of Fluid Film Bearings 24 7 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . 18 . 19 . ... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0. 025 1 0.036 1 0 .2 19 8 0 .2 19 8 0 .2 19 8 ... 0.0 31 I 0.0 31 1 0 .26 49 0 .26 49 3. 72 4 .25 7.44 8.50 14 .88 17 .00 3.54 7.09 14 .17 2. 853 5.705 0 .1 17 0 .23 4 0.0933 0 .15 34 0 .18 67 0.3069 0.3734 0. 613 7 0.779 1. 557 3 .11 5 0.089...
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 docx

Friction and Lubrication in Mechanical Design Episode 2 Part 2 docx

... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 94,703, 189,406 ,28 4,109, and 378,8 12 N/m; the slide/roll ratios were 0,0.08,0.154,0 .22 2,0.345; the rolling speeds varied from 0.3 to 2. 76 m/s, and the sliding speeds were in the range 0 ... coefficient of friction in pure rolling conditions and in the isothermal, the nonlinear, and the thermal regimes. The coefficient of friction always decreases with increasing rolling speed. The rate...
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 doc

Friction and Lubrication in Mechanical Design Episode 2 Part 2 doc

... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 7 .2 Material Properties Steel 43 7800 473 20 3.4 Copper 40 1 8930 386 103 Chromium 94 7135 450 25 0 Tin 67 728 0 22 2 46 10W30 0.145 888 1880 - Rolling/ Sliding Contacts 25 7 ... be within 15%. Ku et al. [21 ] conducted sliding-rolling disk scuffing tests over a wide range of sliding and sum velocities, using a straight mineral oil and three aviation gas turbine synthetic...
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Friction and Lubrication in Mechanical Design Episode 2 Part 3 docx

Friction and Lubrication in Mechanical Design Episode 2 Part 3 docx

... 0. 03 pm (12pin.), W = 37 8,812N/m (21 601bf /in. ), 10W30 oil, U1 = 3 .2 m/sec ( 126 in. /sec), R = 0. 0 23 4 m (0. 92 in. ). Figure 7 .38 shows calculated coefficient of friction versus sliding/ ... and Es for AT, K1, c1, p1, El and K2, c2, p2, E2 in Eqs. (7 .27 ) and (7 .28 ), where f is replaced byf,, L is replaced by L = 32 J'm. 2. U1 + U2 3. Mean rolling ... Drozdov. 30 4 Chapter 7 19. 20 . 21 . 22 . 23 . stokes), substitute ml, Tl and m2, T2 into Eq. (7. 32 ) , respec- tively, and solve these two linear equations simultaneously to get a and 6....
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx

... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... Dry 32 1 Dry 44 0 c Dry 0. 54 0.09 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0 .20 0.78 0 .20 0 .23 0. 54 0.13 0 .20 0. 72 0 .20 0.18 ... 0. 54 0.16 Brass vs. steel 1 045 Dry 0 .20 0.66 A 0 .20 0 .20 B 0 .20 0. 12 41 40 LL Dry 0 .20 0.73 A 0 .20 0 .22 B 0 .20 0 . 24 521 00 Dry 0 .20 0.80 A 0 .20 0 .26 B 0. 54 0 .20 ...
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx

... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0 .20 0.78 0 .20 0 .23 0. 54 0.13 0 .20 0. 72 0 .20 0.18 0. 54 0.16 Brass vs. steel 1 045 ... Polyethylene 0. 54 0.89 0. 54 0. 14 0. 54 0. 14 0 .20 0.83 0. 54 0. 14 0. 54 0. 14 0 .20 0.93 0. 54 0.15 0. 54 0. 14 0 .20 1.33 0 .20 0.16 0 .20 0.19 0 .20 0.99 0 .20 0.15 0 .20 0.15 Dry 0 .20 1.16...
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Friction and Lubrication in Mechanical Design Episode 2 Part 5 doc

Friction and Lubrication in Mechanical Design Episode 2 Part 5 doc

... radial roller bearings. As outlined by Jones [39], the centrifugal Wear 33 7 13. 14. 15. 16. 17. 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. Blok, ... 20 0 SINK TEMPERATURE 4oo 120 0 - f 1400- 1600- v) 1800- W a 5 20 00- w (3 22 00 - 24 00 - 26 00 - 28 00 - 3000 Figure 9 .2 Design chart for gear lubrication. 9.1 .5 Most ... inclusions in the surface region. 9 .2 ROLLING ELEMENT BEARINGS Rolling element bearings represents some of the most critical components in rotating machinery. Because of the ever-increasing...
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Friction and Lubrication in Mechanical Design Episode 2 Part 6 pot

Friction and Lubrication in Mechanical Design Episode 2 Part 6 pot

... in. 2. 565 8 in. 2. 563 7 in. 2. 5 62 0 in. 0.5 766 in. 0 .65 9 in. 12 0.1719 in. 0.3 0.0 021 in. 0.0038 in. Brass Mild steel 8-10 pin rms (10.99947 cm) (4.99 922 8 cm) (2. 6 924 cm) ... (2. 6 924 cm) (9.44 62 cm) (6. 5171 32 cm) (6. 51 1798 cm) (6. 50478 cm) (1. 464 564 cm) (1 .67 3 86 cm) (0.4 36 62 6 cm) (0.005334 cm) (0.00 965 3 cm) Load Figure 9.1 2 Diagrammatic representation ... condition (2) = 0 .25 (2) = 0.50 (2) = 0.75 I. Uniform thickness and external loading 73,4 56. 4 70,378.9 50,5 06. 1 2. Uniform thickness and internal loading 27 2 ,28 3.7 137,739.3 67 ,039.4...
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Friction and Lubrication in Mechanical Design Episode 2 Part 6 doc

Friction and Lubrication in Mechanical Design Episode 2 Part 6 doc

... Outer and inner race material Surface finish for rollers and races 4.3305 in. 1. 96 82 in. 1. 06 in. 3.719 in. 2. 565 8 in. 2. 563 7 in. 2. 5 62 0 in. 0.5 766 in. 0 .65 9 in. 12 0.1719 in. ... 0.0 021 in. 0.0038 in. Brass Mild steel 8-10 pin rms (10.99947 cm) (4.99 922 8 cm) (2. 6 924 cm) (9.44 62 cm) (6. 5171 32 cm) (6. 51 1798 cm) (6. 50478 cm) (1. 464 564 cm) (1 .67 3 86 ... loading 27 2 ,28 3.7 137,739.3 67 ,039.4 3. Uniform thickness and equal load sharing 13 1, 164 .9 54,8 46. 1 19 ,6 16. 8 4. Uniform thickness and optimal load sharing 50 ,28 3.1 33,954 .6 16, 393.5...
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Friction and Lubrication in Mechanical Design Episode 2 Part 7 pdf

Friction and Lubrication in Mechanical Design Episode 2 Part 7 pdf

... smaller increases in the mineral content ratio resulted from the lower compressive loads. This result is interesting in view of the finding of Radin et al. [88] that increased calcification and ... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under the fretting contact ... Equations (9.36) and (9. 37) in the wedging condition are plotted in normal- ized form as shown in Figs 9.31 and 9. 32, respectively. The change of the c value with increasing ramp angle...
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Friction and Lubrication in Mechanical Design Episode 2 Part 7 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 7 ppsx

... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under the fretting contact ... Torque =22 .6‘( 1 -cos (2* pi’ft)) /2 N-m =20 0’(1 -ws(P*pi’ft))l2 Ib -in 0 0 0.1 0 .2 0.3 0.4 0.5 0.6 0 .7 0.8 0.9 1 Time (sec) Figure 9.41 Fretting wear prediction using Eq. ... lower compressive loads. This result is interesting in view of the finding of Radin et al. [88] that increased calcification and stiffening of the rabbit joints occurred as a result of repeated...
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Friction and Lubrication in Mechanical Design Episode 2 Part 8 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 8 ppsx

... 17. 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. 35. Kannel, J. W., Bell, J. C., and Allen, C. M., “Methods for Determining Pressure Distributions in Lubricated ... “Fretting Corrosion of Mild Steel in Air and in Nitrogen,” J. Appl. Mech., 1954, Vol. 21 , p. 395. 183 , pp. 723 - 729 . pp. 20 3 -22 4. 1949, Vol. 71, pp. 25 9 -26 8. pp. 22 2 -23 5. ... July 8- 10, 1 985 , Tokyo, Japan, pp. 635-640. Sato, J., “Damage Formation During Fretting Fatigue,” Wear, 1 988 , Vol. 125 , Vol. 24 , pp. 981 - 988 . 18 -21 , 1 980 . 5 38- 546. pp. 163-174. Friction...
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Friction and Lubrication in Mechanical Design Episode 2 Part 10 ppsx

Friction and Lubrication in Mechanical Design Episode 2 Part 10 ppsx

... (aerospace), piston rings, valves Bearings and seals, piston rings, cylinders liners, and crosshead pins in internal combustion engines and compressors, cannon and gun tubes, metalworking tools, tape-path ... generated in a contact pro- blem such as a semi-infinite cylinder rolling and sliding over a semi-infinite planar surface. As discussed in Chapter 5, Rashid and Seireg [l llobtained the ... Thermal shock parameter Specific heat 1.0 104 > 1 .2 > 110 0.03 3. 52 1 .22 0 .2 20 3.0 x 108 0.853 1.8 104 1.1 x 10- 6 kg/mm2 GPa GPa Dimensionless mls glcm3 GPa...
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