Engineering Tribology Episode 2 Part 7 potx

... 16 and 18 [43]. 0 .2 0.5 1 2 5 10 20 0.001 0.0 02 0.005 0.01 0. 02 0.05 0.1 0 .2 0.5 1 Speed [m/s] Separation [nm] Stearic acid/ hexadecane (saturated) Pure hexadecane FIGURE 8. 32 Effect of dissolved ... 0.1 1 10 100 29 0 300 310 320 330 340 350 10 5 /Transition temperature [K −1 ] Concentration [% wt] 50 20 5 2 0.5 0 .2 Capric acid Myristic acid Oleic acid Stearic acid FIGUR...

Ngày tải lên: 05/08/2014, 09:19

... during or 5. 029 2 meters. 2. A unit of area, equal to its test or during its operation. { pərfo ˙ rиməns 30 .25 square yards, or 27 2 .25 square feet, or karиikиtərisиtik } 25 .29 28 526 4 square meters. ... quarts, or 1/4 bushel, or 5 37. 605 cubic inches, orknown as letters patent. { patиənt } path computation [ CONT SYS ] The calculations 0.00880 976 7541 72 cubic meter. 2. A u...

Ngày tải lên: 21/07/2014, 15:20

... Experimental 72 - 2 72 . 4 Results 72 - 3 72 . 5 Conclusions 72 - 7 Acknowledgment 72 - 7 72 . 1 Introduction A major problem in injection molding is removal of the part from the ... 1 975 (Table 66.1). The failure to put 72 -1 72 Nonmetallic Fatty Chemicals as Internal Mold Release Agents in Polymers 72 . 1 Introduction 72 - 1...

Ngày tải lên: 21/07/2014, 15:20

... on new product Fig. 3. 42 Floppy disk component parts. Concluding remarks 29 7 //SYS21///INTEGRAS/B&H/PRS/FINALS_ 07- 05-03/ 075 0654 376 -CH003.3D – 29 8 – [24 9–300/ 52] 8.5 .20 03 8:59PM development ... competitive. Fig. 3. 37 Example format of an assembly structure diagram. 29 2 Costing designs //SYS21///INTEGRAS/B&H/PRS/FINALS_ 07- 05-03/ 075 0654 376 -CH003.3D – 29 5 – [...

Ngày tải lên: 21/07/2014, 16:21

Ngày tải lên: 21/07/2014, 17:20

... 0.6 0.4 42 0.8 0.431 1.0 0. 422  1 .2 0.414 1.4 0.406 1.6 0.399 1.8 0.393 2 .0 0.3 87 2 .2 0.381 2 .4 0. 376  2 .6 0. 371  2 .8 0.366 3.0 1 .2 1.4 1.6 1.8 2 .0 2 .2 2 .4 2 .6 2 .8 3.0 3 .2 3.4 3.6 3.8 4.0 X B K h 1 h 0 Pad ... h 0 2 [] 6Uη 2B π sec ¯ θ 3 1 2 (θ+ sinθcosθ) − (sinθcos 2 θ + 2sinθ) + C= L...

Ngày tải lên: 05/08/2014, 09:19

... Journal of Tribology, Vol. 111, 1989, Part 1, pp. 22 0 -22 7, Part 2, pp. 22 8 -23 7. 58 Y. Mitsuya, Stokes Roughness Effects on Hydrodynamic Lubrication, Part 2 - Effects under Slip Flow Boundary Conditions, ... + G ∂ 2 M v ∂x* 2 + ( ( R L 2 ∂ 2 M v ∂y* 2 (5.4) where parameters ‘F’ and ‘G’ for journal bearings are as follows: ∂h* ∂x* + ( ( R L 2 [( ( 2 ∂h* ∂y*...

Ngày tải lên: 05/08/2014, 09:19

... = 0 .2 [m] and the radial clearance of the bearing is c = 0.0004 [m], then from equation (5. 87) the value of flow ‘Q’ is: Q = 0.5 × 6.8 × 0 .2 × 10 × 0.0004 = 2. 72 × 10 -3 [m 3 /s] = 2. 72 [litres/s] TEAM ... eccentricity ratio of 0 .7, is shown in Figures 5 . 27 and 5 .28 . The relative groove length is equal to 0 .2 and groove subtended angle is 72 . The perfectly aligned case i...

Ngày tải lên: 05/08/2014, 09:19

... LRN 27 4 ENGINEERING TRIBOLOGY Equating flow through the orifice to the total lubricant flow through the bearing (6.19): πd 2 2 p s − p r 2 ( ( 1 /2 C d = p r h 3 η B Rearranging: πd 2 η 2h 3 B p s ... geometries of these bearings are shown in Figure 6 .2. TEAM LRN 26 8 ENGINEERING TRIBOLOGY 1 2 5 10 20  B 0 0 .2 0.4 0.6 0.8 1.0 C/B 0.4 0.5 0.6 0 .7...

Ngày tải lên: 05/08/2014, 09:19

... p max = 3W 2 a 2 = 3 × 5 2 (5 .79 9 × 10 −5 ) 2 = 70 9.9 [MPa] p average = W πa 2 = 5 π(5 .79 9 × 10 −5 ) 2 = 473 .3 [MPa] · Maximum Deflection δ= 1.03 97 W 2 E' 2 R' () 1/3 = 1.03 97 5 2 (2. 308 ... p max = 3W 2 a 2 = 3 × 5 2 (6.88 × 10 −5 ) 2 = 504.4 [MPa] p average = W πa 2 = 5 π(6.88 × 10 −5 ) 2 = 336 .2 [MPa] · Maximum Deflection δ=...

Ngày tải lên: 05/08/2014, 09:19