Engineering Tribology Episode 1 Part 7 pptx
Engineering Tribology Episode 1 Part 7 pptx
... 12 6 ENGINEERING TRIBOLOGY
p
max
p
z
x
h
0
h
1
B
2
B
B
1
ZONE 2 ZONE 1
U
FIGURE 4 .11 Geometry of the Rayleigh step bearing.
dp
dx
()
1
ZONE 1 = −
p
max
B
1
(4. 71 )
=
p
max
B
2
dp
dx
()
2
ZONE ... ‘U’ is negative):
q
1
= −
h
1
3
12 η
−
Uh
1
2
dp
dx
()
1
substituting for pressure gradient (eq. 4. 71 ) gives flow into the bearing:
q
1
=
12 η
−
Uh
1...
Engineering Tribology Episode 1 Part 6 pptx
...
2h
0
h
1
h
1
+ h
0
C =
1
h
1
+ h
0
(4.43)
The maximum film thickness ‘h
1
’, can also be expressed in terms of the convergence ratio ‘K’:
K
=
h
1
- h
0
h
0
Thus:
h
1
= h
0
(K + 1)
(4.44)
Substituting ... 2h
0
(K + 1)
h
¯
(K + 2)
C =
1
h
0
(K + 2)
(4.45)
Substituting into (4. 41) gives:
p = −
Kh
0
1
h6UηB
h
0
h
2
+
(K + 1)
(K + 2)
+
1
h
0
(K + 2)
or:
TEAM LRN...
Engineering Tribology Episode 1 Part 8 pptx
... check accuracy.
1
2
5
30
20
10
0 .1 0.2 0.5 1 2 5 10 20
1. 0
0.9
0.8
0 .7
0.6
0.5
0.4
0.3
0.2
0 .1
0
ε
5° 10 °
20°
30°
40°
60°
90°
12 0°
15 0°
18 0°
Groove extent β
f
1
f
2
FIGURE ... 0.6 0 .7 0.8 0.9 1. 0
0. 01
0.02
0.03
0.04
0.05
0.06
0.08
0 .1
0.2
0.3
0.4
0.5
0.6
0.8
1
2
3
4
5
6
8
10
20
30
40
50
60
80
10 0
L
D
= ∞
= 1
1
2
=
1
4
=
1
8
=
0....
Engineering Mechanics - Statics Episode 1 Part 7 pptx
... couple
moment.
Given:
F
1
35 N=
θ
60 deg=
F
2
25 N=
r
1
175 mm=
r
2
17 5 mm=
Solution:
M
F
1
− 2 r
1
0
0
⎛
⎜
⎜
⎜
⎝
⎞
⎟
⎟
⎟
⎠
F
2
− 2r
2
cos
θ
()
F
2
− 2 r
2
sin
θ
()
0
⎛
⎜
⎜
⎜
⎝
⎞
⎟
⎟
⎟
⎠
+= M
16 .63−
7. 58−
0
⎛
⎜
⎜
⎝
⎞
⎟
⎟
⎠
Nm⋅= ... moment.
Given:
M
1
40 lb ft⋅=
M
2
30 lb ft⋅=
θ
1
20 deg=
θ
2
15 deg=
θ
3
30 deg=
Solution:
M
1
M
1
cos
θ
1
()
sin
θ
2
()
M
1
cos
θ
1...
Engineering Statistics Handbook Episode 1 Part 7 pptx
... uniform order statistic medians are defined as:
m(i) = 1 - m(n) for i = 1
m(i) = (i - 0. 3 17 5)/(n + 0.365) for i = 2, 3, , n -1
m(i) = 0.5** (1/ n) for i = n
In addition, a straight line can be fit ... uniform order statistic medians are defined as:
m(i) = 1 - m(n) for i = 1
m(i) = (i - 0. 3 17 5)/(n + 0.365) for i = 2, 3, , n -1
m(i) = 0.5
(1/ n)
for i = n
In addition, a straig...
Coatings Technology Handbook Episode 1 Part 7 pptx
...
-1
27
Electroless Plating
27 .1 Introduction
27-
1
27. 2 Plating Systems
27-
2
27. 3 Electroless Plating Solutions
27-
3
27. 4 Practical Applications
27-
4
27. 5
27. 6 ... of Plating Solutions
27-
7
27. 7 Electroless Plating
27-
7
27. 8 Properties of Chemically Deposited Metal Coatings
27-
10
References
27-
11...
Longman Toeic Intermediate Episode 1 Part 7 pptx
... (Questions 10 -12 )
10 . When will the library be closed? ๏ CD CD CD
(A) In
15
minutes.
(B) Tomorrow. า
(C) During the holiday season.
(D) Janua^ 7th.
13 2 LISTENING COMPREHENSION
k
17 . How ... assistant.
(C) Telephone operator.
(D) Mail carrier.
27. What is Mr. Roberts' extension number?
(A) 57.
(B) 15 7.
(C) 5 07.
(D) 15 07.
TALK 10 (Questions 28-30)
28. Wh...
15 Actual TOEIC Listening Tests-Answer Keys Episode 1 Part 7 pptx
... y0 w0 h1" alt=""
SAT II History Episode 1 Part 7 pptx
... between 17 90 and 18 98. Consider that a number of the
questions will deal with the years from 18 45 to 18 77 and the people
and events that brought about the Civil War and its resolution.
SECTION 1. ... Territory.
Review Strategy
See pp. 17 6 17 7 for the
Roosevelt Corollary to the
Monroe Doctrine.
• With the exception of Cuba and Puerto Rico, between 18 10 and
18 24, the Spanish...
Engineering Tribology Episode 1 Part 1 pot
... equation 11 3
· Pressure distribution 11 3
· Load capacity 11 3
· Friction force 11 4
· Coefficient of friction 11 5
· Lubricant flow 11 5
Summary 11 5
4.3 Pad bearings 11 6
Infinite linear pad bearing 11 6
· ... 277
Friction torque 277
Power loss 278
6.6 Hybrid bearings 278
6 .7 Stability of hydrostatic and aerostatic bearings 278
6.8 Summary 279
References 279
7 ELASTOHYDR...
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