sat virtual reality ii explanations phần 2 doc
sat virtual reality ii explanations phần 2 doc
... first,
5
ᎏ
4
5
ᎏ
3
5
ᎏ
3
10
ᎏ
6
1
ᎏ
6
1
ᎏ
6
1
ᎏ
6
1
ᎏ
6
60
ᎏ
360
1
ᎏ
2
c + d
ᎏ
2
a + b
ᎏ
2
c + d + 1
ᎏᎏ
2
a + b
ᎏ
2
c + d
ᎏ
2
a + b
ᎏ
2
SAT
Virtual Reality II
20
section three
Section 3 (Math)
1. B In the QC section ... correct.
1
ᎏ
10
1
ᎏ
8
1
ᎏ
8
1
ᎏ
4
1
ᎏ
4
3
ᎏ
4
3
ᎏ
4
1
ᎏ
4
1
ᎏ
4
3
ᎏ
4
3
ᎏ
4
1
ᎏ
8
17
ᎏ
9
1
ᎏ
9
1
ᎏ
9
1
ᎏ
b
c
ᎏ
b
17
ᎏ
9
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2...
sat virtual reality ii explanations phần 4 doc
... × 3 × 3 × 4 × 4 × 4
= 2 × 3 × 4 × 2 × 3 × 4 × 2 × 3 × 4
= (2 × 3 × 4)
3
2 × 3 × 4 is 24 , so 24
3
= r
3
and r = 24 , choice (D).
3. E Here we’ve got 2 equations, one with 2 variables and one with ... only 1 variable. If 2a = 10, then dividing both sides by 2
gives us a = 5. If a = 5, then a
2
– 16 = b
2
can be written 5
2
– 16 = b
2
, or 25 – 16 =
b
2
, or 9 = b...
sat virtual reality ii explanations phần 3 doc
... get:
Area of
∆
ACE = 3(BC)(BD) = 3(7) = 21
7
2
1
2
7
2
Area of
∆
ACE =
1
2
(AC)(EF ) =
1
2
(3BC)(2BD) = 3(BC)(BD)
1
2
1
2
section four
SAT
Virtual Reality II
34
23 . 4.80
You only have to find the ... relationships between the columns, the answer is (D).
5x
2
+ 1= 46
5x
2
= 45
x
2
= 9
section four
SAT
Virtual Reality II
28
section five
SAT
Virtual...
sat virtual reality iii explanations phần 2 pps
... 3x
ᎏ
3
r + (r + x) + (r + 2x)
ᎏᎏᎏ
3
r + s + t
ᎏ
3
r + s + t
ᎏ
3
section two
SAT
Virtual Reality III
16
SAT
Virtual Reality III
22
section three
correct. (A) is too specific—the author’s not comparing ... answer is (B).
section two
SAT
Virtual Reality III
13
W
D
P
M
6
29
25 25
W
D
P
M
6
29
25 25
19
10
section three
SAT
Virtual Reality III
17
Section 3 (Verbal)...
sat virtual reality ii explanations phần 1 pot
... BCD is around × 7 × 7, or × 49, or
24 , which is closest to 24 , choice (C).
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
–5.1
5.1
–5.15.1
5.1
x
1
ᎏ
2
SAT
Virtual Reality II
10
section one
17. B The only ... so
choice (C) must be correct.
1
ᎏ
4
1
ᎏ
3
1
ᎏ
2
1
ᎏ
2
3
ᎏ
10
6
ᎏ
20
SAT
Virtual Reality II
7
section one
a
– 1
a
– 2
a
–
b
a
+
b
a
a
+ 1
a
+ 2
bb...
sat virtual reality iii explanations phần 4 pps
... + 2) (6)
48 = (x + x + 2) (6)
8 = (x + x + 2)
8 = 2x + 2
6 = 2x
x = 3
1
2
$5.00 + 40($0 .25 ) + 50($0.10) =
$5.00 + $10.00 + $5.00 = $20 .00
section five
SAT
Virtual Reality III
35
(
c
,
d
)
(
a
, ... answer choice (B).
1
ᎏ
5
20
ᎏ
100
1 P
2 R
3
4
5
S 6
1
2 R
3 P
4 S
5
6
1
2 R
3
4
5
6
section seven
SAT
Virtual Reality III
43
4(18) + 2( 25 – 18) = 72 + 14 = 86
It...
sat virtual reality iii explanations phần 3 pptx
... the 2 bases. Suppose b
B
= 3 and b
A
= 2. Then you have:
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
1
ᎏ
2
2
ᎏ
10
1
ᎏ
10
2
ᎏ
10
7
ᎏ
10
2
ᎏ
10
section four
SAT
Virtual Reality III
24
section four
SAT
Virtual Reality III
29
19. ... ($1.75) = $1 .25 ,
so put 1 .25 in the grid.
5
7
7N
ᎏ
5
2N
ᎏ
5
2
N
ᎏ
5
87.5
ᎏ
100
350
ᎏ
400
PART
ᎏ
WHOLE
section four
SAT
Virtual Reality III
28
secti...
sat virtual reality iii explanations phần 1 pdf
... have
noticed that 2x
2
– 8x looks very similar to x
2
– 4x. In fact, 2x
2
– 8x = 2( x
2
– 4x).
So, if x
2
– 4x – 12 = 0, then x
2
– 4x = 12, and 2x
2
– 8x = 2( x
2
– 4x) = 2( 12) or 24 ,
answer choice ... given the
expression x
2
+ 2xy + y
2
. Since x is 1 and y is –1, this expression becomes
x
2
+ 2xy + y
2
= (1)
2
+ 2( 1)(–1) + (–1)
2
= 1 + (2) (–1) + 1
= 1...
Tài liệu Điện công nghiệp - Máy điện II (phần 2) docx
... ta tính đợc.
tm
2
2
)(1
tm
2
).(1
0
tm
2
2
ttm1
B
2
2
sin
4
).cos.d
2
(B
.
2
.
4
dcosB
4
dcosB
2
B =+==
Vậy với máy cực ẩn:
2
2
sin
.
4
B
B
k
tm
tm1
t
==
2- 10
Thờng
= ... k.k
.l.
4.m.f.
I
E
x
==
2- 19
uq
2
dq
2
q
0
q
uq
uq
k
p
.kW
k.k
.l.
4.m.f.
I
E
x
==
2- 20
Thờng: x
d
= 0,5 - 1,5; x
q
= 0,3 - 0,9
Máy điện 2
9
2. Máy...
Tài liệu Bộ đề trắc nghiệm Tiếng Anh lớp 8 (học kỳ II) UNIT 16(phần 2) docx
... long.
III. 16b 17c 18a 19c 20 c
IV. 21 a 22 b 23 c 24 a 25 b 26 d
V. 27 d 28 d 29 c 30a 31c
TEST 3
I. 1d 2c 3d 4a 5b
II. 6b 7a 8a 9c 10a 11b 12b 13b 14a 15b
III. 16b 17b 18a 19c 20 d
IV. 21 a 22 d 23 a ... 22 d 23 a 24 a 25 a 26 d 27 c 28 b
V. 29 c 30b 31d 32d 33b
TEST 4
I. 1a 2d 3a 4b 5a
II. 6a 7a 8a 9a 10a 11a 12a 13b 14a 15a
III. 16c 17a 18a 19d 20 d...