... tedious2λ2µ2λ2µ2λ2µ 1 λ 1 µ2λ2µ2λ2µ2λ2µ 1 λ 1 µ 1 λ 1 µ 1 λ 1 µ2λ2µ2λ2µ2λ2µ02 12 1 λ 1 µ 01 11 21 1λ 1 λ 1 µ 1 µ00 10 20 30 1 λ 1 λ 1 µ 1 µ03 13 22 31 12 1 2{( , ) :( 1) ( 1) }Ennn ... Thus N 1 (t) and N2(t) independent: Letting t→∞, the joint stationary distribution 1 11 1 1 1( ) (1 ) , 0 ,1, npn nρρ=− =222 2 2 2() (1 ) , 0 ,1, npn nρρ=− = 11 2 2 11 2 211 2 2{() ... (DBE) Proof: GBE with S ={0 ,1, …,n} give:0 1 n+1n2,1nnP+ 1, nnP+,nnP,1nnP− 1, nnP− 01 P 10 P00PSSc ,1 1 1, ππ 0 ,1, nnn n n nPPn+++== ,1 1 1, 01 01 ππππnnjji iij nnn n n njin...