SAT II Physics (Gary Graff) Episode 1 Part 5 docx

... SUMMARY Peterson’s SAT II Success: Physics 98 The 250 N boulder shown in the diagram above possesses PE, which can be stated in equation form below. PE = mgh = wt h = ( 250 N) (50 m) = 12 ,50 0 J If the boulder ... rearranging yields: v v = ×       × () ×+× =× − 667 10 610 64 10 3 81 10 59 11 24 65 . . N m kg kg mm 2 2 11 0 6 m/s WEIGHTLESSNESS The strength of the...

Ngày tải lên: 22/07/2014, 10:22

... describe the image. Solution 11 1 fpq =+ Rearrange and substitute: 11 1 1 8 11 12 5 05 1 1 0 75 fpq q q q −= −= −= == cm 20cm cm cm cm 13 .25cm . The image is located 13 . 25 cm from the lens on the ... length of 3.6 cm. Describe the image. Solution 11 1 11 1 36 1 37 1 277 027 fpq fpq q =+ −= −= − rearranges to 1 cm cm cm cm . 1 cm 4cm = == q q 1 0 25. The...

Ngày tải lên: 22/07/2014, 10:22

... of a set of parallel resistors is found in the following manner: 11 11 12 3 RRRR t =++ 11 2 1 5 1 10 1 40 1 5 2 1 0 25 1 8 25 12 1 R R R R t t t t =++ + =+++ = = ΩΩ Ω Ω ΩΩΩ Ω Ω . . The value of ... series). 11 111 1 11 2 1 3 1 4 1 5 1 6 1 5 12 3 45 CCCCCC Cfffff C t t t =++++ =++++ = µµµµµ µ. fffff f Cf t ++++ = . 33 25 2 16 67 14 5 µµµ µ µ C...

Ngày tải lên: 22/07/2014, 10:22

... ) −       − ° ++ = + ° − 26 13 1 25 19 5 19 50 836 8 ((, . ) ,. . . , 26 13 1 25 26 13 1 25 19 50 836 8 19 5 28 0 81 J JJ J C t J C t J ff +=+ ° + ° == ° = °= 856 3 28 0 81 32 8 . , . J C t J J t Ct f f f It ... t J Joules gC gt fo f = =− = ° −° () , . ()( ) ()( 12 50 0 4 18 4 300 20 CC J Joules gC t f ) , . ()( ) () (,       = °             12...

Ngày tải lên: 22/07/2014, 10:22

... coasting. vat v v f f f = = = (. ) . 12 5 17 5 m/s ) (14 s m/s 2 Now we find the displacement while the train coasts, using: s = v t s = (17 .5 m/s) (50 s) s = 8 75 m The equation that best fits the third part of the problem ... the already known F 1 . The calculation of the torques is: TF F T wt wt =+()( ) 11  There are two torque-producing entities. ==•+• =•+• =• ()(. )10...

Ngày tải lên: 22/07/2014, 10:22

... exactly 18 0° opposite the direction the bird must fly. Take the resultant vector and add (or subtract) 18 0° to or from the vector’s direction. 18 0° + 31 = 211 ° The bird must fly 58 3 m @ 211 ° from ... www.petersons.com 63 Rope b extends 35 into the third quadrant . Side y = (side r) (sin 35 ) = (16 N) ( .57 ) = 9.1N Side x = (side r) (cos 35 ) = (16 N) (.82) = 13 .1N Both com...

Ngày tải lên: 22/07/2014, 10:22

... AnsAns AnsAns Ans ww ww w erer erer er ss ss s 1. C 2. B 3. E 4. B 5. B 6. E 7. B 8. E 9. A 10 . A 11 . C 12 . D 13 . C 14 . B 15 . C 16 . D 17 . B 18 . C 19 . D 20. E 21. E 22. D 23. D 24. C 25. B 26. C 27. C 28. C 29. C 30. A 31. B 32. ... D 34. D 35. A 36. A 37. D 38. C 39. C 40. C 41. D 42. C 43. B 44. D 45. D 46. A 47. E 48. B 49. E 50 . B 51 . D 52 . D 5...

Ngày tải lên: 22/07/2014, 10:22

... Prefixes T tera 1 × 10 12 10 12 G giga 1 × 10 9 10 9 M mega 1 × 10 6 10 6 hK hectokilo 1 × 10 5 10 5 ma myria 1 × 10 4 10 4 K kilo 1 × 10 3 10 3 h hecto 1 × 10 2 10 2 d deka 1 × 10 1 10 1 Basic UnitBasic ... Unit 1 meter – 1 gram – 1 liter d deci 1 × 10 1 10 1 c centi 1 × 10 –2 10 –2 m milli 1 × 10 –3 10 –3 dm decim...

Ngày tải lên: 22/07/2014, 10:22

... reciprocals. That is to do the following 11 111 12 34 RRRRR t =+++ yielding the decimal solution 1 05 0 25 016 7 012 4 R t =+ + + . Which is 1 1042 9 6 R t == Ω . 17 .17 . 17 .17 . 17 . The corThe cor The corThe ... power output. II. The PE in equals the KE out. III. The KE in equals the work out. (A) I only (B) II only (C) I and III only (D) II and III only (E) I, II, and...

Ngày tải lên: 22/07/2014, 10:22

... 10 .(.nm × −−− ×× ×× 714 19 14 39 10 26 10 63 8 10 32 1 mHzJ nm Hz ). . / photon Orange 4 00 58 52 10 34 10 5 19 14 19 − − ×× J nm Hz J / / . photon Yellow photon Green 33 5 710 3 810 56 65 10 ... Wavelength Frequency Red 77 7 710 3 910 714 .(. ).nm m H×× − zz nm Hz nm Hz nm Orange Yellow Green 63 48 10 58 52 10 53 57 14 14 × × 11 0 56 65 10...

Ngày tải lên: 22/07/2014, 10:22