... set could be 2, 3, 5, x. This would maximize x. Now solve:2 1 31 51 x 5 21 10 1 x 5 21 10 2 10 1 x 5 21 2 10 x 5 11 , also prime. 11 must be the answer.Section 8As you might expect, answers ... fivey-intercepts and add them up.Line 1: at (0, 2)Line 2: at (0, 1) Lines 3 and 4: at (0, 0)Line 5: at (0, 21) Adding up these five y-values gives you: 2 1 1 1 0 1 0 2 1 5 2 13 . The problem says that the ... thenumbers in the sum must be less than 21. Here’s a Rogue’s Gallery List of allthe less prime numbers: 2, 3, 5, 7, 11 , 13 , 17 , and 19 . To find the greatestpossible integer in the set, first...