Mechanism Design - Enumeration of Kinema Episode 2 Part 1 docx

... topology of a kinematic chain up to structural isomorphism. For example, the link-to-link adjacency matrix of the spur-gear set shown in Figure 3 .2 is given by A =     011 1 10 10 11 01 1 010     . ... Freudenstein, F., 19 84, The Development of an Atlas of the Kinematic Structures of Mechanisms, in Proceedings of the ASME Mechanisms Conference, Cambridge, MA, Pape...

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... engineering series. TJ175 .T78 20 00 6 21 .8 11 dc 21 0 0-0 56 415 The Author Lung-Wen Tsai is a Presidential Chair Professor in the Department of Mechanical Engineering at the University of California ... Polynomial 4 .10 .3 Optimum Code 4 .10 .4 Degree Code 4 .11 Partially Locked Kinematic Chains 4. 12 Summary References Exercises 5 Enumeration of Graphs of...

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... number of three-dof joints. For example, type 20 1 limb has two one-dof, zero two-dof, and one three-dof joints, whereas type 12 0 limb consists of one one-dof, two two-dof, and zero three-dof joints. ... Angeles, J., 19 89, The Optimum Kinematic Design of a Spher- ical Three-Degree -of- Freedom Parallel Manipulator, ASME Journal of Mech- anisms, Transmissions, and Automation in...

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... (8. 12 ) into Equation (2. 32) and the resulting expression into Equation (2. 33) yields C =     11 0 010 1000 011 0 010 100 010 1 010 010 10 011 000 01     . (8 .14 ) From Equation (8 .14 ), we observe that ... =           11 110 00000 10 0 010 0000 010 0 011 000 00 010 00 011 0 010 00 010 0 000 010 10 01 0000 010 110           . (8.9) © 20 01 by CRC...

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... 3 357 13 469 80 2 14 4 0 25 6 0 368 3 4 7 10 50 3 15 5 0 26 7 0 379 0 4 8 11 8 7.7 .1 One-dof Epicyclic Gear Trains For one-dof epicyclic gear trains, there are 1 single-loop, 2 two-loop, 6 three-loop, and ... of Non-fractionated Two-Degree- of- Freedom Epicyclic Gear Trains, ASME Journal of Mechanisms, Transmis- sions, and Automation in Design, 11 1, 4, 524 – 529 . © 2...

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... Representation a 1 (1, 2, 3) → (1, 2, 3) (1) (2) (3) a 2 (1, 2, 3) → (1, 3, 2) (1) (23 ) a 3 (1, 2, 3) → (2, 1, 3)( 12 ) (3) a 4 (1, 2, 3) → (2, 3, 1) ( 12 3 ) a 5 (1, 2, 3) → (3, 1, 2) (1 32) a 6 (1, 2, 3) → (3, 2, 1) (13 ) (2) © ... to b 1 + 2b 2 = 5 , (4 .25 ) b 0 + b 1 + b 2 = 5 . (4 .26 ) Solving Equation (4 .25 ) for nonnegative integers of b 1 and b...

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Ngày tải lên: 21/07/2014, 17:20

... element of A n is nonzero. For example, for the graph shown in Figure 2. 10 A 2 =       313 01 13 12 2 313 01 020 22 12 1 23       and A 3 =       27 267 74 725 27 267 626 02 75 724       . ... Figure 2. 13 , U =     10 1 11 0 011 0 01     . (2. 34) Substituting Equation (2. 34) into Equation (2. 33) yields C =   11 0 010 0 011 0 01...

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... G.9 Type 80 02 transmission mechanism. © 20 01 by CRC Press LLC FIGURE G. 12 Transmission mechanism consisting of type- 420 0 and type-6503 gear trains: version 1. © 20 01 by CRC Press LLC FIGURE G .15 Transmission ... G .15 Transmission mechanism consisting of type- 420 0 and type- 620 6 gear trains: version 2. © 20 01 by CRC Press LLC FIGURE G .2 Type 620 6 transmi...

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... LLC Table F .2 One-dof Epicyclic Gear Trains: Three Independent Loops — Part 1. © 20 01 by CRC Press LLC Table F .1 One-dof Epicyclic Gear Trains: One and Two Independent Loops. © 20 01 by CRC Press ... LLC Table F.5 One-dof Epicyclic Gear Trains: Four Independent Loops — Part 1. © 20 01 by CRC Press LLC Table F.8 One-dof Epicyclic Gear Trains: Four Independent Loops — Part...

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