Metal Machining - Theory and Applications Episode 2 Part 1 potx

... cuttingprocess (Part 1) . Trans. ASME J. Eng. Ind. 10 0, 22 2 22 8.Usui, E. and Hirota, A. (19 78) Analytical prediction of three dimensional cutting process (Part 2) .Trans. ASME J. Eng. Ind. 10 0, 22 9 23 5.Usui, ... developments 21 1 Fig. 7 .11 Three-dimensional non-steady chip formation by rigid plastic finite element method (Ueda et al., 19 96): (a)initial model and (b) spiral chipsChilds Part 2 28:3 :20 00 3 :14 ... Part 1, 1 5.Hashimoto, F. and Kuise. H. (19 66) The mechanism of three-dimensional cutting operations. J.Japan Soc. Prec. Eng. 32, 22 5 23 2.Hastings, W. F., Mathew, P. and Oxley, P. L. B. (19 80)...

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Metal Machining - Theory and Applications Episode 2 Part 11 ppt

... [W/mK]P 01 10 50 16 20 6 8 < 2 6900 16 .2 1 .2 20P05 25 49 16 15 8 12 < 2 7000 14 .2 1. 8 20 P 01 15 48 16 20 5 11 –* 7000 15 .7 –* 20 P05 Total carbide: 94 Total metal: 6 –* 610 0 17 .2 1. 8 –*P10 ... [10 -6 K -1 ]K 01 10 √* √* √* 325 0 94.5 1 0.9 – – –K20 96 2 2 316 0 15 .7 0.9 – – –K05 20 √* √* 325 0 93 .2 1 0.85 – – –– √* √* √* 3300 93.9 1 1 .1 – – –– 91 0 1 8 320 0 14 .2 0.8K20 90.5 6 3.5 326 0 ... Total metal: 14 –* 7000 15 .7 2. 3 11 P20 Total carbide: 82 Total metal: 18 –* 7000 14 .2 2.5 16 P 01 20 Total carbide: 87 Total metal: 13 2 6600 16 .7 1. 5 25 P10–30 Total carbide: 83 Total metal: 17 2...

Metal Machining - Theory and Applications Episode 2 Part 10 pot

... 46Superalloys** 11 – 12 . 5 11 14 13 16 16 20 20 24 Titaniumpure titanium* 22 21 21 21 –α,α–β,βalloys 5.5–8 8– 12 10 17 12 . 5 21 15 25 Ti-6Al-4V 6.6–6.8 8.5–9 .1 10.5– 12 . 5 13 16 16 19 *: high and commercial ... copper* 11 5– 12 0 10 0 11 0 90 10 0 – –60/70Cu–40/30Zn 25 –35 28 –35 27 –33 25 –30 –90/95Cu 10 /5Sn 15 25 20 25 23 –30 – –60/90Cu–40 /10 Ni 6 15 8 18 12 22 – –Nickelpure nickel* 21 23 15 17 12 14 12 14 12 14 70Ni–30Cu ... 30–45 32 40 30–35 27 –30ferritic stainless 21 24 22 25 23 26 24 27 25 29 austenitic stainless 14 17 15 18 17 21 22 25 26 29 high manganese 14 16 19 21 22 Aluminiumpure, 10 00 series 20 0 24 0 20 0 23 0...

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Metal Machining - Theory and Applications Episode 2 Part 9 doc

... u˘zdlhDikj 21 10 + ——[ 12 1 0] 12 1 12 0 0000 (A2 .26 ) and 11 1 q*Ve 1 qDikj 1 hT0Dikj 1 {F}e= ——— {}– ——— {}– ——— {}(A2 .27 )4 1 3 1 3 1 10 0Global assembly of equations (A2 .20 a), with ... [H]e{T} = {Fe} (A2.30)∂twithrCVe 21 11 [C]e= ———| 12 1 1 | 20 1 12 1 11 12 ([C] is given here for a four-node tetrahedron).Numerical (finite element) methods 3 61 Fig. A2.4 Thermal boundary ... 31: 3 :20 00 10 : 42 am Page 356xk 1 zjxjyj 1 ci=– |xk 1 zk|,di=–|xkyk 1 |xl 1 zlxlyl 1 and 1 1 xiyiziVc= —| 1 xjyjzj|(A2 .22 )6 1 xkykzk 1 xlylzl...

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Metal Machining - Theory and Applications Episode 2 Part 8 pptx

... (A1.48a)where, from equation (A1. 42) 1 – nn n——— ——— ——— 0 0 0 1 – 2n 1 – 2n 1 – 2nn 1 – nn——— ——— ——— 0 0 0E 1 – 2n 1 – 2n 1 – 2n[De] = ———[00 0] 1 + nn n1 – n——— ——— ——— 0 0 0 1 ... 339Fig. A1.8 Metal machining slip-line fields (left) and their velocity diagrams (right), due to (1) Lee and Shaffer (19 51) , (2 4) Kudo (19 65) and (5) Dewhurst (19 78)Childs Part 3 31: 3 :20 00 10 : 41 am ... syy′ 2 + szz′ 2 ) + 6(s 2 xy+ s 2 yz+ s 2 zy) ≡(sxx– syy) 2 + (syy– szz) 2 + (szz– sxx) 2 + 6(s 2 xy+ s 2 yz+ s 2 zy) = 6k 2 or 2Y 2 (A1 .26 b)which is the same as equation (A1. 12 ) ...

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Metal Machining - Theory and Applications Episode 2 Part 7 ppt

... additionsr′ 2 = sr 2 –3sm 2 =(s 1 2 + s 2 2+ s3 2 ) – 3sm 2 (A1.5)After substituting for smfrom equation (A1 .1) ,3sr′ 2 =(s 1 – s 2 ) 2 +(s 2 – s3) 2 +(s3– s 1 ) 2 (A1.6)The yield ... stresses: 1 s– 2 =— [(s 1 – s 2 ) 2 +(s 2 – s3) 2 +(s3– s 1 ) 2 ]= Y 2 or 3k 2 (A1.7) 2 330 Appendix 1 Fig. A1 .2 Geometrical representations of principal stresses and yieldingChilds Part 3 31: 3 :20 00 ... on Auto. Cont. 19 , 716 – 722 .ASM (19 90) Classification and designation of carbon and low-alloy steels. In ASM Handbook 10 thedn. Vol. 1, 14 0 19 4. Ohio: American Society of Metals. 324 Process selection,...

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Metal Machining - Theory and Applications Episode 2 Part 6 pot

... VBMM160404 53 P10 49 0 .10 0.33 5 12 17 35 0.4MVVNN2 020 M16 VNMG160404 53 P10 45 0 .20 0.48 4 11 17 35 0.4MVVNN2 020 M16 VNMG160408 53 P10 38 0.40 0.70 4 11 17 35 0.8Childs Part 3 31: 3 :20 00 10 :39 ... drill 19 .5)5: (SHAPE through-hole 11 .7 ∇) 2: (TOOL reamer 20 .0)4: (TOOL drill 19 .5)6: (TOOL drill 11 .7)7: (SHAPE centre hole 2. 0) 2: (TOOL reamer 20 .0)4: (TOOL drill 19 .5)6: (TOOL drill 11 .7)8: ... manner:SF(d, 0.76, 1 .27 ), d < 1 .27 m(T 1 |d) = { 1 1 .27 ≤ d < 1. 78 (9.36a) 1 – SF(d, 1. 78, 2. 29) 1. 78 ≤ dwhere the coefficients’ values reflect a strength constraint.Optimization of machining...

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Metal Machining - Theory and Applications Episode 2 Part 5 ppsx

... 3 31: 3 :20 00 10 :38 am Page 28 2fmach (1 – n 1 )n 1 1 Cctct+ Ctn 1 Copt= Cctload+ pDLda(——————)(—————)fopt(n 1 –n 2 )/n 2 dopt(n 1 –n3)/n3CcC ′n 1 (9 .28 d)By replacing ... of f in equation (9 .29 a), which is negative,may satisfy the relationn3(n 1 – n 2 )1 – n 1 /n 2 m 1 |—–———|= ———— < —— < 1 (9 .29 b)n 2 (n3– n 1 )1 – n 1 /n3m 2 Thus, even if the ... Cp(x) 29 2 Process selection, improvement and controlFig. 9. 12 Fuzzy optimization of cutting conditions; only three constraints 1, 4 and 10 are consideredChilds Part 3 31: 3 :20 00 10 :38 am Page 29 2design,...

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Metal Machining - Theory and Applications Episode 2 Part 4 pptx

... 0.007ln V)Ff= 629 f0.30d0. 720 + 11 99(VS3.58– 0. 023 V0 .27 )}(9.2b)× (VB–0.66– 0 .23 V0 .27 ) (VN0.03– 0 .23 V0 .27 )Fc= 18 62f0.94d 1. 11 + 26 77(VS0 .24 – 0.05ln V)×(VB0 .23 – 0.05ln ... mmChilds Part 2 28:3 :20 00 3 :18 pm Page 25 5Vyas, A. and Shaw, M. C. (19 99) Mechanics of saw-tooth chip formation in metal cutting. TransASME J. Manuf. Sci. and Engng. 12 1 , 16 3 1 72. Williams, ... speed machining. Int. J. Machining Sci. and Tech. 2, 343–353.Shaw, M. C., Usui, E. and Smith, P. A. (19 61) Free machining steel (part III). Trans ASME J. Eng.Ind. 82, 18 1 1 92. Shinozuka, J. (19 98)...

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Metal Machining - Theory and Applications Episode 2 Part 3 pot

... 0. 028 5 + 0.000 014 TN = 0 .18 e –0.0005T+ 0.1e –0.000 015 (T–430) 2 a = 0.00 020 , m = 0.00 52 Steel Y A = 920 e –0.0 011 T+ 12 0 e –0.00003(T 16 0) 2 + 11 0e –0.00004(T–340) 2 + 12 0 e –0.00 01( T–650) 2 M ... 0.0 315 + 0.000 016 TN = 0 .19 e –0.0005T+ 0.085e –0.000 015 (T–430) 2 a = 0.000 32, m = 0.0 018 Steel L A = 910 e –0.0 011 T+ 19 0e –0.00 011 (T 13 5) 2 + 15 0e –0.000 02( T–330) 2 + 10 0e –0.00 01( T–650) 2 M ... 0.0 323 + 0.000 014 TN = 0 .18 5e –0.0007T+ 0.055e –0.000 015 (T–370) 2 a = 0.00 024 , m = 0.0 019 Steel X A = 880e –0.0 011 T+ 12 0 e –0.00009(T 15 0) 2 + 15 0e –0.000 02( T–350) 2 + 90e –0.00 01( T–650) 2 M...

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