Metal Machining - Theory and Applications Episode 2 Part 3 pot

... –0.000015(T 37 0) 2 a = 0.00 028 , m = 0.0016Childs Part 2 28 :3 :20 00 3: 17 pm Page 24 2 24 6 Applications of finite element analysisFig. 8.16continuedChilds Part 2 28 :3 :20 00 3: 17 pm Page 24 6Figure ... m/minTable 8 .3 Coefficients of friction in characteristic equation (2. 24d)V=100 m/min V =20 0 m/minmµn* mµn*Steel P 1.0 2. 31 3. 89 1.0 2. 48 3 .22 Steel X 0.99 1 .25 3. 05 0.96 1. 43 2. 06Steel ... formation 23 5Fig. 8.6 Predicted discontinuous chip in β-brass machining: cutting speed of 13 mm/min, f=0 .25 mm, d=1 mm,α=15º and no coolantChilds Part 2 28 :3 :20 00 3: 16 pm Page 23 5Simulation...

20

425

0

Metal Machining - Theory and Applications Episode 2 Part 10 pot

... and steelpure iron* 85 64 50 38 31 0.04–0 .25 C 52 60 48–54 42 45 35 37 29 30 0 .25 –0.8C 51– 52 46–48 39 – 42 33 35 29 30 0.8–1.2C 45–51 42 46 37 39 32 33 27 29 low alloy 25 –49 30 –45 32 40 30 35 27 30 ferritic ... 27 30 ferritic stainless 21 24 22 25 23 26 24 27 25 29 austenitic stainless 14–17 15–18 17 21 22 25 26 29 high manganese 14 16 19 21 22 Aluminiumpure, 1000 series 20 0 24 0 20 0 23 0 20 0 22 5 190 22 0 ... 115– 120 100–110 90–100 – –60/70Cu–40 /30 Zn 25 35 28 35 27 33 25 30 –90/95Cu–10/5Sn 15 25 20 25 23 30 – –60/90Cu–40/10Ni 6–15 8–18 12 22 – –Nickelpure nickel* 21 23 15–17 12 14 12 14 12 1470Ni 30 Cu...

20

347

0

Metal Machining - Theory and Applications Episode 2 Part 6 pot

... [mm]SVVBN2 525 M16 VBMM160404 53 P10 49 0.10 0 .33 5 12 17 35 0.4MVVNN2 020 M16 VNMG160404 53 P10 45 0 .20 0.48 4 11 17 35 0.4MVVNN2 020 M16 VNMG160408 53 P10 38 0.40 0.70 4 11 17 35 0.8Childs Part 3 31 :3 :20 00 ... .(4.5 .2) size:(4.6) availabilityChilds Part 3 31 :3 :20 00 10 :39 am Page 3 02 of tool or workpiece, etc, are measured in-process or out-of-process. In-process monitor-ing that does not require the machining ... functionSF(x, a1, a 2 ), x < a 2 m(x, a1, a 2 , a 3 , a4) = {1 a 2 ≤ x < a 3 (9 .35 a)1 – SF(x, a 3 , a4) a 3 ≤ xas shown in Figure 9 .21 , where the parameters a1, a 2 , a 3 and a4are...

20

281

0

Metal Machining - Theory and Applications Episode 2 Part 1 potx

... background 20 3 Fig. 7 .2 Eulerian and Lagrangian views of a plastic flowChilds Part 2 28 :3 :20 00 3: 14 pm Page 20 3 where D is the area of the element; and similarly for the other strains eyy and gxy. ... cos(η′c+ ψ)πf1/ 2 — – ψ+ sin–1—— – {{rncos(η′c– θ) + f cos(η′c+ ψ)} 2 – f 2 – 2rnf cos(ψ+ θ)} 2 2rnChilds Part 2 28 :3 :20 00 3: 13 pm Page 1 93 l as functions of ... cuttingprocess (Part 1). Trans. ASME J. Eng. Ind. 100, 22 2 22 8.Usui, E. and Hirota, A. (1978) Analytical prediction of three dimensional cutting process (Part 2) .Trans. ASME J. Eng. Ind. 100, 22 9 23 5.Usui,...

20

303

0

Metal Machining - Theory and Applications Episode 1 Part 3 pot

... cut, 38 Chip formation fundamentalsFig. 2. 2 (a and b) Orthogonal, (c) non-orthogonal and (d) semi-orthogonal chip formation.Childs Part 1 28 :3 :20 00 2: 35 pm Page 38 In the case of turning with a 90˚ ... undeformed layerChip formation mechanics 43 Childs Part 1 28 :3 :20 00 2: 35 pm Page 43 than m. The common (m/n) value of 2 (from Figure 2. 10(a)) is consistent with n ≈ 0 .3. Thiswould be expected of a triangular ... fundamentalsFig. 2. 8 (a) The work hardening of 70 /30 brass and (b) friction coefficients and chip thickness ratios measured forsamples pre-strained by amounts A to D as markedChilds Part 1 28 :3 :20 00 2: 36 ...

20

320

0

Metal Machining - Theory and Applications Episode 2 Part 11 ppt

... √* √* √* 33 00 93. 911.1 – – –– 91 0 1 8 32 0 0 14 .2 0.8K20 90.5 6 3. 5 32 6 0 13. 7 1.0 – – –K05 20 √* √* √* √* 33 00 15.4 0.9 17 28 0 3. 0K01 30 √* √* √* 33 00 15.7 0.8 – – –– 80 6 4 10 32 0 0 15.7 ... Eαecode Si 3 N4Y 2 O 3 Al 2 O 3 Other [kg/m 3 ] [GPa] [GPa] [W/mK] [GPa] [10 -6 K -1 ]K01–10 √* √* √* 32 5 0 94.510.9 – – –K20 96 2 2 31 60 15.7 0.9 – – –K05 20 √* √* 32 5 0 93 .2 10.85 – ... frame 20 2 3 Lagrangian reference frame 20 2 3 node separation at cutting edge 20 3, 20 7–9, 21 8 20 rigid-plastic models 20 1 2, 34 9–50strain-displacement relations 199 20 1stiffness matrix 20 1, 34 8–9temperature...

16

475

0

Metal Machining - Theory and Applications Episode 2 Part 9 doc

... (pr/τmax)(pr/τmax)/cSpherical 0. 42 2.6 6 .2 Cylindrical 0 .39 2. 2 5.6Conical 0.50 1.6 3 .2 Wedge-like 0.50 1.0 2. 0Childs Part 3 31 :3 :20 00 10: 43 am Page 36 6(trailing) the real contact mean ... dldlNumerical (finite element) methods 35 9Childs Part 3 31 :3 :20 00 10: 42 am Page 35 9pr= p 2 + k (A3.10)Slip-line EDBC is an a-line, sop 2 = p1+ 2ky ≡ k(1 + 2y) (A3.11)The angle y is chosen to ... Lond. 188, 627 – 638 . 3 62 Appendix 2 Childs Part 3 31 :3 :20 00 10: 42 am Page 3 62 In the following sections, a view of how sliding friction depends on material properties,contact geometry and intensity...

20

279

0

Metal Machining - Theory and Applications Episode 2 Part 8 pptx

... d(dekl)(deij)0 3( de–0) 2 ∂(dekl)(A1 .34 )Constitutive equations for numerical modelling 34 3Childs Part 3 31 :3 :20 00 10: 42 am Page 34 3A1 .2. 3 Velocity relations in a slip-line fieldAnalogous ... the results, a 34 6 Appendix 1Childs Part 3 31 :3 :20 00 10: 42 am Page 34 6pA+ 2kfA= pB+ 2kfB;pC+ 2kfC= pD+ 2kfD(A1.19)pA+ 2kfA= pD– 2kfD;pB – 2kfB= pC+ 2kfC}Geometry ... 3( sxx′ 2 + syy′ 2 + szz′ 2 ) + 6(s 2 xy+ s 2 yz+ s 2 zy) ≡(sxx– syy) 2 + (syy– szz) 2 + (szz– sxx) 2 + 6(s 2 xy+ s 2 yz+ s 2 zy) = 6k 2 or 2Y 2 (A1 .26 b)which is the same...

20

409

0

Metal Machining - Theory and Applications Episode 2 Part 7 ppt

... ′:sm=(s1+ s 2 + s 3 ) /3 s1′ = s1– sm≡ 2s1 /3 – (s 2 + s 3 ) /3 s 2 ′ = s 2 – sm≡ 2s 2 /3 – (s 3 + s1) /3 }(A1.1)s 3 ′ = s 3 – sm≡ 2s 3 /3 – (s1+ s 2 ) /3 Hydrostatic stress plays no part ... sm 3. OP is sr′. By vector additionsr′ 2 = sr 2 –3sm 2 =(s1 2 + s 2 2+ s 3 2 ) – 3sm 2 (A1.5)After substituting for smfrom equation (A1.1),3sr′ 2 =(s1– s 2 ) 2 +(s 2 – s 3 ) 2 +(s 3 – ... s 3 ) 2 +(s 3 – s1) 2 (A1.6)The yield criterion may be restated in terms of the principal stresses:1s– 2 =— [(s1– s 2 ) 2 +(s 2 – s 3 ) 2 +(s 3 – s1) 2 ]= Y 2 or 3k 2 (A1.7) 2 33 0 Appendix...

20

341

0

Metal Machining - Theory and Applications Episode 2 Part 5 ppsx

... gic+(9 .32 a)gi c+– gic–0 gic+< gi(x)Optimization of machining conditions 29 1Childs Part 3 31 :3 :20 00 10 :38 am Page 29 1Even if the pre-machined corner has the same radius ( 12. 7 mm) ... theOptimization of machining conditions 28 3 Childs Part 3 31 :3 :20 00 10 :38 am Page 28 3 tmachtmachttotal= tload+ ——— + tct———fmachT}(9.16d)pDLda1 V1/n1f1/n 2 d1/n 3 = tload+ ... methods. 29 0 Process selection, improvement and controlChilds Part 3 31 :3 :20 00 10 :38 am Page 29 0FYwith a helical end mill is always positive, irrespective of up- or down-milling, exceptfor up-milling...

20

411

0