Metal Machining - Theory and Applications Episode 2 Part 6 pot

... [mm] SVVBN2 525 M 16 VBMM 160 404 53 P10 49 0.10 0.33 5 12 17 35 0.4 MVVNN2 020 M 16 VNMG 160 404 53 P10 45 0 .20 0.48 4 11 17 35 0.4 MVVNN2 020 M 16 VNMG 160 408 53 P10 38 0.40 0.70 4 11 17 35 0.8 Childs Part 3 31:3 :20 00 10:39 ... . (4.5 .2) size: (4 .6) availability Childs Part 3 31:3 :20 00 10:39 am Page 3 02 of tool or workpiece, etc, are measured in-process or out-of-process....

Ngày tải lên: 21/07/2014, 17:20

... stainless 21 24 22 25 23 26 24 27 25 29 austenitic stainless 14–17 15–18 17 21 22 25 26 29 high manganese 14 16 19 21 22 Aluminium pure, 1000 series 20 0 24 0 20 0 23 0 20 0 22 5 190 22 0 – 20 00 to 7000 ... titanium* 22 21 21 21 – α , α – β , β alloys 5.5–8 8– 12 10–17 12. 5 21 15 25 Ti-6Al-4V 6. 6 6. 8 8.5–9.1 10.5– 12. 5 13– 16 16 19 *: high and commercial purit...

Ngày tải lên: 21/07/2014, 17:20

... –0.000015(T–370) 2 a = 0.00 028 , m = 0.00 16 Childs Part 2 28:3 :20 00 3:17 pm Page 24 2 24 6 Applications of finite element analysis Fig. 8. 16 continued Childs Part 2 28:3 :20 00 3:17 pm Page 24 6 Figure 8. 16. A ... (2. 24d) V=100 m/min V =20 0 m/min m µ n* m µ n* Steel P 1.0 2. 31 3.89 1.0 2. 48 3 .22 Steel X 0.99 1 .25 3.05 0. 96 1.43 2. 06 Steel Y 0.97 0. 76...

Ngày tải lên: 21/07/2014, 17:20

... equation (6. 41), using Tables 6. 1 and 6 .2 as appropriate; A uf is determined from tool geometry, feed and depth of cut by equations (6. 46) and (6. 45). Thus, equation (6. 50), with f e , t sh and 194 ... cutting process (Part 1). Trans. ASME J. Eng. Ind. 100, 22 2 22 8. Usui, E. and Hirota, A. (1978) Analytical prediction of three dimensional cutting process (Part 2) ....

Ngày tải lên: 21/07/2014, 17:20

... [W/mK] P01–10 50 16 20 6 8 < 2 69 00 16 .2 1 .2 20 P05 25 49 16 15 8 12 < 2 7000 14 .2 1.8 20 P01–15 48 16 20 5 11 –* 7000 15.7 –* 20 P05 Total carbide: 94 Total metal: 6 –* 61 00 17 .2 1.8 –* P10 ... application to built-up edge formation 22 6 34 chip control (grooved-rake tool) 25 1 2 high manganese steel machining 21 5–17 machining a-brass 20 6 7...

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... (p r / τ max )(p r / τ max )/c Spherical 0. 42 2 .6 6 .2 Cylindrical 0.39 2. 2 5 .6 Conical 0.50 1 .6 3 .2 Wedge-like 0.50 1.0 2. 0 Childs Part 3 31:3 :20 00 10:43 am Page 366 (trailing) the real contact mean normal ... u˘ z d l hD ikj 21 10 + —— [ 121 0 ] 12 1 120 0000 (A2 . 26 ) and 11 1 q*V e 1 qD ikj 1 hT 0 D ikj 1 {F} e = ——— {} – ——— {} – ——— {} (A2 .27 ) 4 1 3 1 3...

Ngày tải lên: 21/07/2014, 17:20

... 3(s xx ′ 2 + s yy ′ 2 + s zz ′ 2 ) + 6( s 2 xy + s 2 yz + s 2 zy ) ≡ (s xx – s yy ) 2 + (s yy – s zz ) 2 + (s zz – s xx ) 2 + 6( s 2 xy + s 2 yz + s 2 zy ) = 6k 2 or 2Y 2 (A1 . 26 b) which is the same ... s r 2 . So s r is also a stress invariant (it is known as the second stress invariant). From equation (A1 .25 ) s r 2 = s 2 xx + s 2 yy + s 2 zz +2(...

Ngày tải lên: 21/07/2014, 17:20

... addition s r ′ 2 = s r 2 –3s m 2 =(s 1 2 + s 2 2 + s 3 2 ) – 3s m 2 (A1.5) After substituting for s m from equation (A1.1), 3s r ′ 2 =(s 1 – s 2 ) 2 +(s 2 – s 3 ) 2 +(s 3 – s 1 ) 2 (A1 .6) The yield ... stresses: 1 s – 2 =— [ (s 1 – s 2 ) 2 +(s 2 – s 3 ) 2 +(s 3 – s 1 ) 2 ] = Y 2 or 3k 2 (A1.7) 2 330 Appendix 1 Fig. A1 .2 Geometrical representati...

Ngày tải lên: 21/07/2014, 17:20

... d R ) 2 – (r w – d e ) 2 = R 2 – (R – d e ) 2 } (9.9a) for a convex survace (r w + d R ) 2 – (r w + d e ) 2 = R 2 – (R – d e ) 2 Hence d e 2r w – d R for a concave surface c r = — = ———— d R 2r w – ... force model of equation (9.2a). 27 6 Process selection, improvement and control Fig. 9 .6 continued (c) Childs Part 3 31:3 :20 00 10:37 am Page 27 6 Maximum operation...

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... V 0 .27 ) } (9.2b) × (VB –0 .66 – 0 .23 V 0 .27 ) (VN 0.03 – 0 .23 V 0 .27 ) F c = 1 862 f 0.94 d 1.11 + 26 77(VS 0 .24 – 0.05ln V) ×(VB 0 .23 – 0.05ln V) (VN 0. 16 – 0.05ln V) where F d , F f , and F c are ... conventional, (b) and (c) type I and II tools, K = 1 .2 Childs Part 2 28:3 :20 00 3:19 pm Page 26 2 where F* t , F* r and F* z are the specific cutting forces i...

Ngày tải lên: 21/07/2014, 17:20