Basic Mathematics for Economists - Rosser - Chapter 8 doc

... 10 288 00 1600 160 8 81 1 273 78 1 78 1 78 9 80 .1 0.1 27217. 98 17. 98 179 .8 10 80 .01 0.01 27201.79 98 1.79 98 179. 98 11 80 .001 0.001 27200. 18 0.1799 98 179.9 98 12 80 .0001 0.0001 27200.0 18 0.017999 98 179.99 98 13 ... 4x 2−1 = 8x When x = 8, then slope = 8( 8) = 64. © 1993, 2003 Mike Rosser 0 0 D MR TR 80 0 80 q 4020 £ q p Figure 8. 3 We know that by defi...

Ngày tải lên: 06/07/2014, 07:20

... 2     23 710      = 8[ 5(−16) − 2(−40) + 4( 18) ]+2[10(−40) −5(−12) + 4(−1)] − 3[10( 18) − 5(5) + 2(−1)] = 8[ 80 + 80 + 72]+2[−400 + 60 − 4]−3[ 180 − 25 − 2] = 8( 72) + 2(−344) − 3(153) = 576 − 688 − 459 =−571 © ... =  23 81  and B =  752 481  Solution Using the method explained above, the product matrix will be AB =  23 81  752 481  =  2 ×7 + 3 × 42× 5 +3 82 × 2...

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... 18 when x = 6 then y = 54 −36 = 18 This is because the function y = 9x − x 2 is not monotonic. This can be established by calculating y for a few selected values of x: x 1234567 y 81 4 182 020 181 4 These ... so TR = PQ If we substitute the demand function P = 80 − 0.2Q for P in this TR function then TR = (80 − 0.2Q)Q = 80 Q − 0.2Q 2 © 1993, 2003 Mike Rosser This means that the val...

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... equilibrium value of Y for any given level of I. For example whenI=200thenY =80 +2(200) =80 +400= 480 (checkwithExample5.7) when I = 300 then Y = 80 + 2(300) = 80 + 600 = 680 From the reduced form equation ... = 1 48 (3) 3. Solve for A, B and C when 32A + 14B + 82 C = 664 (1) 11.5A + 8B + 52C = 349 (2) 18A + 26.2B − 62C = 560.4 (3) 4. Find the values of x,y and z when 4.5x + 7y + 3...

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... 27 -6 37 38 -1 42 15 5.5 -2 07 16.5 -6 58 27.5 -6 25 38. 5 -1 08 16 6 -2 38 17 -6 67 28 -6 12 39 -7 3 17 6.5 -2 68 17.5 -6 75 28. 5 -5 98 39.5 -3 7 18 7 -2 97 18 -6 82 29 -5 83 40 0 19 7.5 -3 25 18. 5 -6 88 29.5 ... 24.5 -6 82 35.5 -2 97 10 3 -3 7 14 -5 98 25 -6 75 36 -2 68 11 3.5 -7 3 14.5...

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... 0 .81 62 98 0.79 383 2 0.772 183 0 .88 8996 0 .86 383 8 0 .83 9619 0 .81 62 98 0.79 383 2 0.772 183 4 0 .85 480 4 0 .82 2702 0.792094 0.76 289 5 0.73503 0.7 084 25 0 .85 480 4 0 .82 2702 0.792094 0.76 289 5 0.73503 0.7 084 25 5 0 .82 1927 ... 0.9615 38 0.952 381 0.943396 0.934579 0.925926 0.917431 2 0.924556 0.907029 0 .88 9996 0 .87 3439 0 .85 7339 0 .84 1 68 0.924556 0.907029 0 .88 999...

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... is Q q = 200,000 q As each order made costs 80 and each unit stored for a year costs 8 then TC = order +stock-holding costs = 200,000 (80 ) q + 8q 2 = 16,000,000q −1 + 4q For a stationary point dTC dq =−16,000,000q −2 + ... Therefore, second-order condition for a maximum is satisfied and TR is a maximum when q is 18. (Note that in this example the second-order derivative −1.2q<0 for...

Ngày tải lên: 06/07/2014, 07:20