Basic Mathematics for Economists - Rosser - Chapter 6 pps

Basic Mathematics for Economists - Rosser - Chapter 6 pps

Basic Mathematics for Economists - Rosser - Chapter 6 pps

... 26. 5 -6 48 37.5 -1 75 14 5 -1 75 16 -6 48 27 -6 37 38 -1 42 15 5.5 -2 07 16. 5 -6 58 27.5 -6 25 38.5 -1 08 16 6 -2 38 17 -6 67 28 -6 12 39 -7 3 17 6. 5 -2 68 17.5 -6 75 28.5 -5 98 39.5 -3 7 18 7 -2 97 18 -6 82 ... -5 67 24 -6 88 35 -3 25 9 2.5 0 13.5 -5 83 24.5 -6 82 35.5 -2 97 10 3 -3 7 14 -5 98 25 -6 7...

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Basic Mathematics for Economists - Rosser - Chapter 5 ppsx

Basic Mathematics for Economists - Rosser - Chapter 5 ppsx

... check that the price of £12. 16 for the first 60 units corresponds to point A on the demand schedule in Figure 5 .6 since p = 16 − 0. 064 q = 16 −0. 064 (60 ) = 16 −3.84 = £12. 16 If the firm wishes to sell ... 120) q = 6MC − 260 q + 260 6 = MC (1) Since p = 580 −0.3q MR = 580 − 0.6q (2) To maximize profits MC = MR and so equating (1) and (2) q + 260 6 = 580 − 0.6q q + 260 = 3,480...

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59 1,2K 2
Basic Mathematics for Economists - Rosser - Chapter 7 pps

Basic Mathematics for Economists - Rosser - Chapter 7 pps

... 0.7 462 15 0.704 961 0 .66 6342 0 .63 017 0.5 962 67 7 0.759918 0.71 068 1 0 .66 5057 0 .62 275 0.58349 0.547034 0.759918 0.71 068 1 0 .66 5057 0 .62 275 0.58349 0.547034 8 0.73 069 0 .67 6839 0 .62 7412 0.582009 0.540 269 ... 0.009908 1 .60 0.8 265 62 0 .68 3204 0. 564 711 0.385813 0.0221 56 0.008584 1 .65 0.82 169 6 0 .67 5185 0.554797 0.374590 0.01 968 9 0.007375 1.70 0.8 168 61 0 .66 7 2...

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Basic Mathematics for Economists - Rosser - Chapter 11 pps

Basic Mathematics for Economists - Rosser - Chapter 11 pps

... 40 − 22.5(275, 567 .6) K −2.5 = 0 (3) 40 = 22.5(275, 567 .6) K 2.5 K 2.5 = 22.5(275, 567 .6) 40 = 155,0 06. 78 K = 119. 162 68 Substituting this value into (1) gives L = 275, 567 .6 (119. 162 8) 1.5 = 211.84478 This ... 4K 0 .6 (1. 562 5K) 0.5 = 0 200 = 4K 0 .6 (1. 562 5) 0.5 K 0.5 200 4(1. 562 5) 0.5 = K 1.1 40 = K 1.1 K = 1.1 √ 40 = 28 .60 3434 Substituting this value into (4) 1. 562 5...

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30 1,5K 10
Basic Mathematics for Economists - Rosser - Chapter 12 ppsx

Basic Mathematics for Economists - Rosser - Chapter 12 ppsx

... (2) d 2 Q dK 2 = ( 160 − 8K) 0 .6 K 0 .6 (− 76. 8) − ( 768 − 76. 8K) 96 − 9.6K K 0.4 ( 160 − 8K) 0.4 ( 160 − 8K) 1.2 K 1.2 = ( 160 − 8K)K(− 76. 8) − 76. 8(10 − K)9 .6( 10 − K) ( 160 − 8K) 1 .6 K 1 .6 At the stationary ... 4.8K −0 .6 and dv dK = 0.4( 160 − 8K) −0 .6 (−8) =−3.2( 160 −8K) −0 .6 Therefore, dQ dK = 12K 0.4 (−3.2)( 160 −8K) −0 .6 + ( 160 − 8K) 0.4 4.8K −0 .6 = −38.4K +(...

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Basic Mathematics for Economists - Rosser - Chapter 14 pps

Basic Mathematics for Economists - Rosser - Chapter 14 pps

... 1.75 years, r = 2.5%= 0.025, A = 56 (e billion). Therefore, the final value of GNP will be y = Ae rt = 56e 0.025(1.75) = 56e 0.04375 = 58.504384 Thus the forecast for GNP is e58,504,384,000. So far ... example, when t = 3 then y 3 = 22.5e 6( 3) − 4.5 = 22.5e 18 − 4.5 = 22.5 (65 ,65 9, 969 ) − 4.5 = 1,477,349,303 Before we investigate the usefulness of this method for the analysis of dyna...

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Basic Mathematics for Economists - Rosser - Chapter 4 potx

Basic Mathematics for Economists - Rosser - Chapter 4 potx

... 3 1 3 MR 1 (1)Q 2 = 60 − 6 2 3 MR 2 (2) © 1993, 2003 Mike Rosser 0 K Q 1 Q 2 Q 3 L Figure 4.21 Table 4.7 KLK 0.5 L 0.5 Q 64 4 8 2 320 16 16 4 4 320 464 2 8320 2 56 1 16 1 320 1 2 56 1 16 320 Assume that ... decrease of £400, since 60 0 = 1.5 × £400. Therefore the fall in C is 1.5 ×£240 = £ 360 . C (£) 0(£) C = 200 + 0.6Y Y 900 1,00 060 0 66 0 300 Figure 4.7 © 1993, 2003 Mike R...

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