... Approximate value (x′) = 0 .33 3Therefore, Absolute Error, 1 0 .33 3 0 .33 333 3 0 .33 3 0.00 033 3 3 a Exx′=− =− = − =Relative Error, E r= 0.00 033 30.0009990 .33 333 3 a E x== andPercentage Error, E p= ... seconddecimal places.Example 4. If 0 .33 3 is the approximate value of 1 3 , then find its absolute, relative and percentageerrors.Sol. Given that True value () 1 3 x=, and its Approximate ... ==0.50.00588.6r E .Example 7. Three approximate values of number 1 3 are given as 0 .30 , 0 .33 and 0 .34 . Which of these three is the best approximation?Sol. The number, which has least absolute error, gives...