Mathematical Methods 1 for Engineers and Scientists 1 pps
... Thus e =10 1 2.3026 =1. 77828 1. 33352 × 1. 074607 1. 036633 × 1. 018 152 × 1. 009035 1. 0 011 249 × 1. 0002 811 17 × 1. 00 014 0548 × (1 + 2.3026 × 0.000026535) = 2. 718 26. Since 1 2.3026 is only accurate to 5 significant ... we have N n 1 = 1. 2 1. 15478 =1. 03 915 9 = n 2 n 3 ··· . The number smaller than and closest to 1. 03 915 9 is 1. 036633. So we choose n 2 =1. 03...
Ngày tải lên: 05/07/2014, 05:20
... row 1 yields [i -1/ 4 -1/ 41 1/4"] 35 -2 51 25/Rz/35 -25 12 51 25 J (1. 104) Scaling row 2 to give a22 = 1 gives -1/ 4 -1/ 411 /4"]R 1- ( -1/ 4)R2 1 -5/ 715 /7 / -25 12 51 25 ] R 3 (-25)R 2 (1. 105) Applying ... Eq. (1. 79)] 80 -20 -20 [20 1 -20 40 -20 12 0 -20 -20 13 0 12 0 R1/80 (1. 102) Scaling row 1 to give all = 1 gives 1 1/4 1/ 411 / 41 -20 40 -...
Ngày tải lên: 02/04/2014, 15:44
... system is based on the number 2 instead of 10 . Only the digits 0 and 1 are needed. For example, the binary number 10 111 0 = 1 · 2 5 + 0 · 2 4 + 1 · 2 3 + 1 · 2 2 + 0 · 2 0 = 46 in decimal notation. A ... e n = (0, 0, , 1) is the standard basis of V = R n . Bayes formula Suppose A and B 1 , , B n are events for which the probability P (A) is not 0, n i =1 P(B i ) = 1...
Ngày tải lên: 10/12/2013, 12:15
HANDBOOK OF MATHEMATICS FOR ENGINEERS AND SCIENTISTS pptx
... 1) 2 ; n k=0 (2k + 1) 2 = 1 3 (n + 1) (2n + 1) (2n + 3); n k=0 ( 1) k (2k + 1) 2 = 2( 1) n (n + 1) 2 – 1 2 1 +( 1) n ; n k =1 (k + a)(k + b)= 1 6 n(n + 1) (2n + 1 + 3a + 3b)+nab. A large number of formulas ... =( 1) n n – 1 2 ,[m] is the integer part of m; n k=0 (2k + 1) =(n + 1) 2 ; n k=0 ( 1) k (2k + 1) =( 1) n (n + 1) ; n k =1 k 2 =...
Ngày tải lên: 08/03/2014, 12:20
c++ for engineers and scientists
... of n Examples: 1 10 10 2 2 - = (that is, 1 01 100 . = ) 1 10 10 2 2 = - (that is, 1 100 01= . ) 1 10 10 3 3 - = (that is, 1 0 01 1000 . = ) 1 10 10 4 4 = - (that is, 1 10 000 00 01 , .= ) Notice ... 10 4-6- 312 d. 10 10 10 374 ×× 10 10 -6 -5 5. (Practice) Compute the following: a. 2.8 10 4 1. 6 10 -6 ×3.2 10 -3 b. 1 4.5 10 1. 8 10 6.7 10 4-6-...
Ngày tải lên: 19/03/2014, 14:07
gasification technologies a primer for engineers and scientists
... 27.0 35.4 34.4 14 .5 12 .7 61. 9 CO 39.5 35.6 45.0 35 .1 23.5 15 .3 26.2 CH 4 1. 5 0 .1 0.0 0.3 1. 3 3.4 6.9 CO 2 9.3 12 .6 17 .1 30.0 5.6 11 .1 2.8 N 2 +Air 2.3 6.8 2 .1 0.2 49.3 46.0 1. 8 H 2 O 22.7 18 .7 0.4 — 5.7 11 .5 ... 80.4 1. 1 1. 1 8.5 Low-volatile bituminous 14 ,350 5.0 4.7 81. 7 9.4 1. 2 6.0 High-volatile bituminous A 13 ,800 9.3 5.3 75.9 1. 5 1. 5 6....
Ngày tải lên: 02/04/2014, 15:12
crc press - dictionary of applied math for engineers and scientists - d. clark
... , e n = (0, 0, , 1) is the standard basis of V = R n . Bayes formula Suppose A and B 1 , , B n are events for whichtheprobabilityP (A) is not 0, n i =1 P(B i ) = 1, and P (B and B j ) = 0if i ... charge e = 1. 602 17 7 33(49) 10 19 C. See electric charge. elementary forces The four elementary forces in nature are gravitation, electromag- netism, weak nuclear force, and s...
Ngày tải lên: 04/04/2014, 21:43
smith, s. w. (2003) digital signal processing - a practical guide for engineers and scientists
... -2.2 -2 .1 -2.0 -1. 9 -1. 8 -1. 7 -1. 6 -1. 5 -1. 4 -1. 3 -1. 2 -1. 1 -1. 0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0 .1 0.0 - X .0003 .0005 .0007 .0 010 .0 013 .0 019 .0026 ... IIIIIII 0 16 32 48 64 80 96 11 2 12 7 Time (or other variable) 2 I I I L 1 I 1 (b.q 1 11 IIIIIII 11 11 IIIIIII IIIIIII IIIIIII IIIIjII -2 I...
Ngày tải lên: 18/04/2014, 12:32