... (+)N(3)N(1)N(1,1)N'1BI1BI2BI3BI1BI2BI3BI1BI2BI3If88,80 9 0 0 87,5660 0 88, 19 10 0I00 0 0 27 ,9 0 0 28,11 9 0 0I1 + I288,80 9 0 0 59, 6660 0 78,3580 0X = 0,01126 + 0,105 = 0,1163 ... I0(BI1) 295 ,1 191 91,8 891 2,76152,43)1 19, 28()372, 29) .(2321(438, 59) .2321(jjjIf(BI1) - I0(BI1) = - 43,152 – j 76 ,91 2 + 28,1 19 = 78,358/-101Theo quy -íc vÒ dÊu ... 1 19, 2801177,017,017,0.066,30)(.)(010OHTHCHCXXXXXIBIIDßng ®iÖn pha sù cè ch¹y qua BI1:If(BI1) = a2I1(BI1) + a.I2(BI1) + I0(BI1) 295 ,1 191 91,8 891 2,76152,43)1 19, 28()372, 29) .(2321(438, 59) .2321(jjjIf(BI1)...