... .cos 2sin 6.sin.cos (2cos 3cos 1) 0x x x x x x⇔ + − − − + = 2 22sin .cos 2sin 6.sin.cos (2cos 3cos 1) 0x x x x x x⇔ + − − − + = 2 1sin 2 (2sin 1)(2cos 3cos 1) 0 cos 11cos 2 xx x x xx=⇔ ... trên.0 ,25 0,50 ,25 Câu Phần Nội dung Điểm II (2, 0) 1(1,0)sin 3 3sin 2 cos 2 3sin 3cos 2 0x x x x x− − + + − = ⇔(sin 3 sin ) 2sin 3sin 2 (cos 2 2 3cos ) 0x x x x x x+ + − − + − = 2 2sin 2 .cos 2sin ... : 2 4 0,AC x y− + =( ) : 3 8 0AB x y− − =, ( ) :3 4 2 0.BC x y+ + =0 ,25 0,50 ,25 2( 1,0)+ 1 2 , ( ), ( )M N d d∈ nên ta giả sử1 1 1 2 2 2 1 2 1 2 1 2 ( ; ; 2 ), ( 1 2 ; ;1 ) ( 2 1; ;2...