Verilog Programming part 5 ppt
Verilog Programming part 5 ppt
... port_id is 5 bits wide integer matrix[4:0][0: 255 ]; // Two dimensional array of integers reg [63:0] array_4d [ 15: 0][7:0][7:0][ 255 :0]; //Four dimensional array wire [7:0] w_array2 [5: 0]; // ... value) of port_id array. matrix[1][0] = 3 355 9; // Set value of element indexed by [1][0] to 3 355 9 array_4d[0][0][0][0][ 15: 0] = 0; //Clear bits 15: 0 of the register //access...
Ngày tải lên: 01/07/2014, 21:20
Tài liệu Logic Synthesis With Verilog HDL part 5 pptx
... nickel x5 = 2'b01, dime x10 = 2'b10. • output: 1-bit, newspaper—release door when newspaper = 1'b1 • states: 4 states—s0 = 0 cents; s5 = 5 cents; s10 = 10 cents; s 15 = 15 cents ... x5/0 means transition to the state pointed to by the arc, when input is x5 (2'b01), and set the output to 0. Figure 14-10. Finite State Machine for Newspaper Vending Machine 14.7.4...
Ngày tải lên: 24/12/2013, 11:17
Verilog Programming part 8 ppt
... connections. However, a warning is typically issued that the widths do not match. Unconnected ports Verilog allows ports to remain unconnected. For example, certain output ports might be simply for ... of that module. Each declared port provides the complete information about the port. Example 4 -5 shows this alternate syntax. This syntax avoids the duplication of naming the ports in...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 1 ppt
... LiB ] [ Team LiB ] 1 .5 Popularity of Verilog HDL Verilog HDL has evolved as a standard hardware description language. Verilog HDL offers many useful features • Verilog HDL is a general-purpose ... easy to use. It is similar in syntax to the C programming language. Designers with C programming experience will find it easy to learn Verilog HDL. • Verilog HDL allows d...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 3 pptx
... clk is 10 units; the reset signal stays up from time 0 to 15 and then goes up again from time 1 95 to 2 05. Output q counts from 0 to 15. Figure 2-8. Stimulus and Output Waveforms 2.4 Instances ... 3 50 Output q = 4 60 Output q = 5 70 Output q = 6 80 Output q = 7 90 Output q = 8 100 Output q = 9 110 Output q = 10 120 Output q = 11 130 Output q = 12 140 Output q = 13...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 25 ppt
... reg [ 15: 0] cd_xor, ef_xor; //variables in module top reg [ 15: 0] c, d, e, f; //variables in module top - task automatic bitwise_xor; output [ 15: 0] ab_xor; //output from the task input [ 15: 0] ... called concurrently from two locations in the code. Example 8 -5 shows how an automatic task is defined and used. Example 8 -5 Re-entrant (Automatic) Tasks // Module that contains an...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 20 ppt
... four types of looping statements in Verilog: while, for, repeat, and forever. The syntax of these loops is very similar to the syntax of loops in the C programming language. All looping statements ... data_buffer(data_start, data, clock); parameter cycles = 8; input data_start; input [ 15: 0] data; input clock; reg [ 15: 0] buffer [0:7]; integer i; always @(posedge clock) be...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 21 ppt
... simulation time 0 #5 y = 1'b1; //completes at simulation time 5 #10 z = {x, y}; //completes at simulation time 15 #20 w = {y, x}; //completes at simulation time 35 end Parallel blocks ... #5 y = 1'b1; #10 z = {x, y}; join #20 w = {y, x}; end N amed blocks Blocks can be given names. • Local variables can be declared for the named block. • Named blocks are a...
Ngày tải lên: 01/07/2014, 21:20
Verilog Programming part 30 ppt
... inside a stimulus module. Force the sum output to a & b & c_in for the time between 15 and 35 units. 3: A 1-bit full adder FA is defined with gates and with delay parameters as shown ... stimulus shown in Example 5- 9 on page 77. Explain the effect of the full adder delays on the times when outputs of the adder appear. (Use delays of 20 instead of 5 used in this stimulus.)...
Ngày tải lên: 01/07/2014, 21:20
Programming HandBook part 5 ppt
... ; float b [ 3 ] [ 4 ] ; char c [5 ] [6 ] ; => a [ 0 ] [0 ] a [ 0 ] [ 1 ] a [ 1 ] [ 0 ] a [ 1 ] [ 1] a [ 2 ] [ 0 ] a [ 2 ] [ 1 ] Ví dụ 2 : #define Hang 5 # define Cot 6 int a [ Hang ] ... đến một int */ pnum = & num ; /* pnum chứa địa chỉ biến int num*/ giả sử : num = 5 ; => * pnum = 5 /* do * là toán tử nội dung */ Hai câu lệnh sau đây là tương đương Num = 100 ; (...
Ngày tải lên: 03/07/2014, 09:20