Communication Systems Engineering Second Edition John G Proakis Masoud pot

... |H(f)| 2 = sgn 2 (f) a) The energy spectral density of the output signal is G Y (f) =G X (f)sgn 2 (f)=  G X (f) f =0 0 f =0 Since G X (f) does not contain any impulses at the origin E Y = E X = 1 2α 27 where ... = A 2 2 + A 2 2 + 4A 2 2 + 4A 2 2 =5A 2 42 b) Arguing as in the previous question G Y (f) =G X (f)sgn 2 (f)=  Π(f) f =0 0 f =0 Since Π(f) does not contain any impulses a...

Ngày tải lên: 27/06/2014, 23:20

... [cos(2π2f c t + θ) + cos(θ)] 44 SOLUTIONS MANUAL Communication Systems Engineering Second Edition John G. Proakis Masoud Salehi Prepared by Evangelos Zervas Upper Saddle River, New Jersey 07458 The ... O’Brien Managing Editor: David A. George Production Editor: Barbara A. Till Composition: PreT E X, Inc. Supplement Cover Manager: Paul Gourhan Supplement Cover Design: PM Works...

Ngày tải lên: 27/06/2014, 17:20

... |H(f)| 2 = sgn 2 (f) a) The energy spectral density of the output signal is G Y (f) =G X (f)sgn 2 (f)=  G X (f) f =0 0 f =0 Since G X (f) does not contain any impulses at the origin E Y = E X = 1 2α 27 5) ... sinc(6t)=⇒ H(f )= 1 6 Π( f 6 ) The energy spectral density of the output signal is G Y (f)= G X (f)|H(f)| 2 and with G X (f)= 1 α 2 +4π 2 f 2 we obtain G Y (f)= 1 α 2 +4...

Ngày tải lên: 27/06/2014, 17:20

... 3.3 The following figure shows the modulated signals for A = 1 and f 0 = 10. As it is observed both signals have the same envelope but there is a phase reversal at t = 1 for the second signal Am 2 (t) ... θ) Problem 2.53 Taking the Fourier transform of  e j2πf 0 t we obtain F[  e j2πf 0 t ]=−jsgn(f )δ(f −f 0 )=−jsgn(f 0 )δ(f − f 0 ) Thus,  e j2πf 0 t = F −1 [−jsgn(f 0 )δ(f − f 0 )] = −jsg...

Ngày tải lên: 27/06/2014, 17:20

... + 1 4π 2 t 2 (cos πt − 1)  38 SOLUTIONS MANUAL Communication Systems Engineering Second Edition John G. Proakis Masoud Salehi Prepared by Evangelos Zervas Upper Saddle River, New Jersey 07458 3) ... |H(f)| 2 = sgn 2 (f) a) The energy spectral density of the output signal is G Y (f) =G X (f)sgn 2 (f)=  G X (f) f =0 0 f =0 Since G X (f) does not contain any impulses a...

Ngày tải lên: 05/03/2014, 19:20

... write ∞  n=−∞ |x n | 2 = −M  n=−∞ |x n | 2 + M  n=−M |x n | 2 + ∞  n=M |x n | 2 7 SOLUTIONS MANUAL Communication Systems Engineering Second Edition John G. Proakis Masoud Salehi Prepared by Evangelos Zervas Upper Saddle River, New Jersey 07458 With ... The angle modulated signal can be interpreted both as a PM and an FM signal. It is a PM signal with phase deviation const...

Ngày tải lên: 28/03/2014, 17:20

... MANUAL Communication Systems Engineering Second Edition John G. Proakis Masoud Salehi Prepared by Evangelos Zervas Upper Saddle River, New Jersey 07458 Chapter 3 Problem 3.1 The modulated signal ... Managing Editor: Vince O’Brien Managing Editor: David A. George Production Editor: Barbara A. Till Composition: PreT E X, Inc. Supplement Cover Manager: Paul Gourhan Supplement Co...

Ngày tải lên: 27/06/2014, 08:20

... structure, and grain size. b Sublimates before melting. c Glass transition temperature given for polymers. An Introduction to Microelectromechanical Systems Engineering Second Edition Nadim Maluf Kirt ... 40 Etching 44 Advanced Process Tools 55 Anodic Bonding 55 Silicon Direct Bonding 56 Grinding, Polishing, and Chemical-Mechanical Polishing 57 Sol-Gel Deposition Methods 58 Electropla...

Ngày tải lên: 13/02/2014, 14:20

... communication system designs, the statistical characteristics of the channel Proakis- 50210 proa-fm August 9, 2001 14:2 COMMUNICATION SYSTEMS ENGINEERING John G. Proakis Masoud Salehi 2nd Ed. Upper ... efficient and highly reliable underwater acoustic communication systems for transmitting digital signals over large distances. Storage Channels. Information storage and retri...

Ngày tải lên: 08/06/2014, 17:49

... gap between the image spectra equal to 2000 − 500 − W = 1000 29 Publisher: Tom Robbins Editorial Assistant: Jody McDonnell Executive Managing Editor: Vince O’Brien Managing Editor: David A. George Production ... sinc(6t)=⇒ H(f )= 1 6 Π( f 6 ) The energy spectral density of the output signal is G Y (f)= G X (f)|H(f)| 2 and with G X (f)= 1 α 2 +4π 2 f 2 we obtain G Y (f)= 1 α 2 +4π 2 f...

Ngày tải lên: 27/06/2014, 05:20