Aerodynamics for Engineering ppt

... 3.2 Process Design 56 3.3 Site Selection and Evaluation 63 3.4 Plant Layout and Plot Plan 66 3.5 Civil Engineering Design 75 3.6 Structural Engineering Design 80 3.7 Architectural Design ... been reformatted by Knovel to provide easier navigation. 2.8 Summary - A Fable 42 Appendix 2A Inherent Process Safety Checklist 44 2.9 References 47 3. Plant Design 53 3.1...

Ngày tải lên: 13/12/2013, 03:15

... Data Houghton, E.L. (Edward Lewis) Aerodynamics for engineering students. - 5th ed. 1 Aerodynamics I Title I1 Carpenter, P.W. 629.1’323 - For information on all Butterworth-Heinemann ... 1.3 5d) (1. 35e) (1.35f) Substituting these values in Eqn (1.33), (1.36) 22 Aerodynamics for Engineering Students 1.4.2 Dimensional analysis applied to aerodynamic fo...

Ngày tải lên: 13/02/2014, 09:20

... g(Re) V For dynamic similarity Therefore giving nf = 8 cycles per second 22 Aerodynamics for Engineering Students 1.4.2 Dimensional analysis applied to aerodynamic force In discussing ... Data Houghton, E.L. (Edward Lewis) Aerodynamics for engineering students. - 5th ed. 1 Aerodynamics I Title I1 Carpenter, P.W. 629.1’323 - For information on all...

Ngày tải lên: 05/03/2014, 17:20

... experimental aerodynamics demands its own considered and separate treatment. Aerodynamics for Engineering Students Fifth Edition E.L. Houghton and P.W. Carpenter Professor of Mechanical Engineering, ... represent the names of these units by abbreviations: kg for kilogram m for metre s for second "C for degree Celsius K for Kelvin The degree Celsius...

Ngày tải lên: 27/06/2014, 17:20

... convenient form in which the viscosity of a fluid may be expressed. It is formed I - Fig. 1.3 28 Aerodynamics for Engineering Students L Lift Cross-wind moment Fig. 1.8 The systems of force ... 22 Aerodynamics for Engineering Students 1.4.2 Dimensional analysis applied to aerodynamic force In discussing aerodynamic force it is necessary to know how ... used fo...

Ngày tải lên: 27/06/2014, 17:20

... 95 95 96 97 10 1 10 4 10 4 10 4 10 5 10 6 10 7 10 9 11 0 11 0 11 2 Contents Preface xlll 1 Basic concepts and defdtions Preamble 1. 1 Units and dimensions 1. 1 .1 Fundamental dimensions ... 716 0 = 0 .11 51 kgm-3 P p =-= RT 287.3 x 216 .5 e=($&) 314 = 1. 19 P 1. 44 x kgm-ls-l 17 1 1. 19 = - 1 0-5 = Consider a dimension that,...

Ngày tải lên: 08/08/2014, 11:21

... direction. For three-dimensional flows Eqns (2. 45) and (2. 46) are written in the forms: 1 at ax ay az (ax ay az ap ap ap ap au av aw -+ u-+v-+w-+p -+ - +- =o au av aw -+ - +-= o ax ... therefore be calculated by 1 Po - P = AP = 5 PO4 and therefore 1 2 po -p = - x 1 .22 6 (26 4)' = 426 70NmP2 Now In standard condition...

Ngày tải lên: 08/08/2014, 11:21

... (Fig. 3. 6). Putting the line along the x-axis as $ = 0 128 Aerodynamics for Engineering Students Doublet axis Fig. 3. 20 Streamlines due to a doublet - 2c - -x- Fig. 3. 21 ... Fig. 3. 12 Image systems Equating (3. 53) and (3. 54): Potential flow 137 (3. 55) The rate of change of total pressure His and substituting for Eqn (3. 55): af...

Ngày tải lên: 08/08/2014, 11:21

... C C c x/ =-( i -cose) (i-cos~) =-( cos~-cose) 2 2 2 and k from Eqn (4. 51): +,( (1 -; ) COS4Il - (1 where ’t (4. 54) Fig. 4. 16 176 Aerodynamics for Engineering Students and ... per unit span MLE = -lCp dx Changing the sign Therefore for unit span 7i- - - Comparing Eqns (4. 31) and (4. 32) shows that CL CMLB = 4 (4....

Ngày tải lên: 08/08/2014, 11:21

... (2)m=a =5. 5[1 +- 5 55 ~~’8 (31 = 5. 5[1 - 0. 054 55 cos B] ao =5. 5 [ 1 5* 55T: 5 (31 = 5. 5[1 + 0.363 64 cos e] 238 Aerodynamics for Engineering Students I 44 J. J ti444 tJ4J ... - - At any section z from the centre-line [B from the wing-tip] [ 3.048 - 1 .52 4 (;)I chord c = 3.048 1 - = 3.048[1 + OSCOSB] 3.048 (2)...

Ngày tải lên: 08/08/2014, 11:21

... (Eqn (6. 17)): which gives the differential equation Equation (6. 66) may now be integrated. Thus or From Eqn (6. 65) (6. 65) (6. 66) (6. 67) Compressible flow 339 i.e. when Mk(y - l)u'/U, ... 2+ ( 7- 1)M; For air 6. 4.5 Temperature rise across the normal shock Directly from the equation of state and Eqns (6. 43) and (6. 45): For air (6. 45) (6...

Ngày tải lên: 08/08/2014, 11:21

... 0.0 0 .7 -0 .08 0.8 -0 .12 0.9 -0 .16 1.0 -0 .20 e 11.31" 9.09" 6.84" 4. 57& quot; 0.0 -4 . 57& quot; -6 .84" -9 .09" -1 1.31" ne 0" 2.22" 4. 47& quot; ... 0.104 0.0008 -0 .0831 -0 .1166 -0 .1 474 -0 . 175 4 WP)li7l 0.228 0.183 0.138 0.092 0 -0 .098 -0 .138 -0 .183 -0 .228 Wings o...

Ngày tải lên: 08/08/2014, 11:21

... [35.5p5f8 x 16 480 + 55 .8 x lo5 - 55 .8 x I05pj4f5 55 .8 x 105 i.e. 55 .8 465 5f4 - 55 .8 x lo5 = (35.6 - 55 .8) 105 ( 0.1 488 ) 5 .84 - 55 .8 x 1oSp = or 55 .8~ - 5 .84 ~~1~ ... Aerodynamics for Engineering Students Pi 0.9 0 .8 0.7 - 0.6 0.5 - 0.4 - 0.3 - - - U - 0 0.1 0.2 0.3 0.4...

Ngày tải lên: 08/08/2014, 11:21

... - 2e - 2d - f b = 2 - d - 2e - f c=l-e Substituting these in Eqn (9. 15) gives T= c~ 4-2 -2 d-f 2-d-2e-f I-e d e f n p VKV = CpnZD4f [(z)d(L)e (-3 f] D2n pD2n2 (9. 16) ... [(L)"(T)-b(ML-3)c(L2T-1)d(ML-'T-2)e(LT-1~] Separating this into the three fundamental equations gives (M) I=c+e (L) 1 =a-3c+2d-e+f (T) 2=b+d+2e+f...

Ngày tải lên: 08/08/2014, 11:21

... back for y in terms of Mo, my and t gives 1 m 1 m G = T [(Mo - &)(l - ~{Mo - lizt))]; =-[ M(l -1 nM) -Mo(l -1 nMo)l where M = MO - mt. Thus finally 1 G = [(M - ... of (v - V - ;ST/?. The total forward momentum is then 1 2 Now, by the conservation of momentum of a closed system: H2 = (M - rizbt)( V + SV)...

Ngày tải lên: 08/08/2014, 11:21