Petri Nets Applications 1 docx

... networks). 2 Petri Nets: Applications Edited by Pawel Pawlewski In-Tech intechweb.org Petri Nets: Applications1 8 ∃ f ile1, f ile2, x owner ( f ile1) = x ∧ owner( f ile2) = x ∧ ln( f ile2, file1) ∧ execute( ... Categories AIFSN CW min CW max TXOP Limit AC_BK 7 15 10 23 1 frame AC_BE 3 15 10 23 1 frame AC_VI 2 7 15 3 ms AC_VO 2 3 7 1. 5 ms Table 1. Parameters for t...

Ngày tải lên: 21/06/2014, 11:20

... 243 V 4 =(0 ,1, 1,0 ,1, 0,0) (0,0 ,1, 0 ,1, 0 ,1) = V 8 V 2 =(0 ,1, 1,0,0, 1, 0) (0 ,1, 0 ,1, 1,0,0)= V 3 V 6 =(0,0,0 ,1, 1, 0 ,1) (0,0 ,1, 0,0 ,1, 1)= V 7 (1, 0 ,1, 0,0 ,1, 0) (0 ,1, 0 ,1, 0 ,1, 0) (1, 0,0 ,1, 1,0,0) V 1 = (1, 0,0 ,1, 0, 1, 0) ... {V 1 , . . . , V 8 }, with V 1 = (1, 0, 0, 1, 0, 1, 0), V 2 = (0, 1, 1, 0, 0, 1, 0), V 3 = ( 0, 1, 1, 0, 1, 0, 0) , V 4 = ( 0, 1...

Ngày tải lên: 21/06/2014, 11:20

... , 1 1 Z ,0) | 1 1 Z |=| 1 2 Z | =1 1 M (0, 1 1 Z , 2 1 1 1 ZZ + ) | 1 1 Z |=| 1 2 Z | =1 2 M 2 1 1 1 , ZZt + | 1 1 Z | =1 | 2 1 Z | =1 ( 1 1 Z ,0,0) | 1 1 Z |=2 3 M (0,0, 1 1 Z ) | 1 1 Z |=2 4 M 1 1 , ... |=2 4 M 1 1 , Zt ( 2 1 1 1 ZZ + , 1 1 Z ,0) | 1 1 Z |=| 1 2 Z | =1 1 M (0, 1 1 Z , 2 1 1 1 ZZ + ) | 1 1 Z |=| 1 2 Z | =1 2 M...

Ngày tải lên: 21/06/2014, 11:20

... controller) t1- 21= -b1-3 t1 -10 0=b1-3,-b1-4 t1- 71= b1-4, -b1-5 t1 -10 1=b1-5, -b1-6 t1- 81= b1-6, -b1-7 t1- 31= b1-7 t1- 41= -b1 -13 t1 -10 2=b1 -13 ,-b1 -14 t1- 91= b1 -14 , -b1 -15 t1 -10 3=b1 -15 , -b1 -16 t1- 51= b1 -16 (MC ... A0 A1 A2 A3 A4 A5 A 11 A12 A 21 A22 A23 A24 A 31 A32 A 41 A42 A43 A44 A45 A 51 A52 A 111 A 112 A2 21 A222 A2 41 A242 A3 21 A322...

Ngày tải lên: 21/06/2014, 11:20

... a in .b in a 12 b 21 b 12 a 21 c 22 a 12 b 21 c 12 c 21 b 22 a 22 b 22 a 22 c 22 c 22 c 11 a 11 b 11 c 11 b 11 a 11 b 11 a 11 c 11 t 1 t 2 a 21 b 12 c 21 c 12 t 3 ... a in .b in a 12 b 21 b 12 a 21 c 22 a 12 b 21 c 12 c 21 b 22 a 22 b 22 a 22 c 22 c 22 c 11 a 11 b 11 c 11 b 11 a 11 b 1...

Ngày tải lên: 21/06/2014, 11:20

...  T =( 1 ,  2 ,  3 ) with  1  1,  2  1,  3  1 and  1 +  2 +  3 > 1. a 11 0 0 0 0 a 21 0 0 0 0 0 b 11 0 0 0 0 b 12 0 0 0 0 0 b 13 ... reprogrammable components. o 1 o 2 o 12 o 3 o 13 o 11 o 14 o 18 o 17 o 8 o 15 o 6 o 19 o 16 o 7 o 10 o 9 o 4 o 5 Systolic...

Ngày tải lên: 21/06/2014, 11:20

... controller) t1- 21= -b1-3 t1 -10 0=b1-3,-b1-4 t1- 71= b1-4, -b1-5 t1 -10 1=b1-5, -b1-6 t1- 81= b1-6, -b1-7 t1- 31= b1-7 t1- 41= -b1 -13 t1 -10 2=b1 -13 ,-b1 -14 t1- 91= b1 -14 , -b1 -15 t1 -10 3=b1 -15 , -b1 -16 t1- 51= b1 -16 (MC ... as follows. G1: t0 -1, t3 -13 G2: t0-2, t1- 21, t2-22, t3-23 G3: t1- 71, t3-73 G4: t1- 81, t2-82 G5: t0-3, t1- 31, t2-32 G6: t0-4, t1- 41, t2-42, t3-43 G...

Ngày tải lên: 21/06/2014, 11:20

... Computational results for the CCS in Fig. 13 r m r m 01 f m T m 11 2 f m T m 21 21 11 r a T a 21 f a r a T a 11 f a 20 10 and S F = {(20), (10 ), (00)}. For each failure state ... all i. One may define: 1 i, p p.p p p.p π ;1 1- ii 211 0 i1-i12 01 i0  (15 ) And noting ( ) [ ] ∑ ∞. - i 1 i1+iii =πp+π , the following theorem is true (Schri...

Ngày tải lên: 21/06/2014, 11:20

...                                                  0 0 0 0 0 1 - 0 0 1 - 0 0 0 0 0 Tf N N E M M M M  ;                 1 0 1 00 11 11 00 11 11 C        10 01 ( 41) which is showed in the figure 15 . In this error ...                                       ...

Ngày tải lên: 21/06/2014, 11:20

... |p i (x)| Petri Nets: Applications6 18 Step Red Blue Mixed 1 188 238 2072 2 447 646 14 05 3 670 8 01 1027 4 862 10 13 623 5 952 10 66 480 6 10 63 11 32 303 7 11 10 12 38 15 0 8 11 31 1273 94 9 11 49 13 04 45 10 11 69 ... Blue Mixed Total 1 7 5 38 50 2 27 29 32 88 3 48 46 26 12 0 4 64 63 19 14 6 5 72 75 18 16 5 6 87 81 15 18 3 7 95 92 11 19 8 8 10 2 98 9 209 9...

Ngày tải lên: 21/06/2014, 11:20