Wave Propagation 2011 Part 2 pot

Wave Propagation 2011 Part 2 pot

Wave Propagation 2011 Part 2 pot

... (57) 12 21 RR0 = = (58) 22 22 jk dcos 12 23 11 j2k dcos 12 23 TTe TT 1R R e θ θ == +    22 22 jk dcos 12 23 22 j2k d cos 12 23 TTe TT 1R R e θ ⊥⊥ ⊥ θ ⊥⊥ == + (59) 12 21 TT0 = = ... (Gennarelli & Riccio, 20 09a), the elements of R and T are: 22 22 j2k dcos 12 23 11 j2k dcos 12 23 RRe RR 1R R e θ θ + == +    22 22 j2k d cos 12 23 2...

Ngày tải lên: 21/06/2014, 23:20

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Wave Propagation 2011 Part 9 potx

Wave Propagation 2011 Part 9 potx

... carbon nanotubes are using as examples. Equation (60) becomes 22 22 4 23 2 1 22 2 2 23 22 12 12 22 11 22 22 4 23 2 1 2 22 2 23 22 12 12 22 11 i( ) 0 0 11 (1) i( ) (1 ) 0 00 i() (1 ) 1 1 0i()(1) p p p p kc krk ... the wave dispersion relation as following υ ω − ++− =−   ∓  22 22 2 22 2 22 11(1) ()()4 (1 ) 2 p k kk RRR crk. (41) Then, the group ve...

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Photodiodes World Activities in 2011 Part 2 pot

Photodiodes World Activities in 2011 Part 2 pot

... to define 0 cos , 1, 2 jj j nk j  , to rewrite Eg. (22 ) as    12 12 2 2 12 1 2 22 2 2 12 12 TE r ii i                     (24 ) The same calculation ...    2 , 2 k zkz z Rz      ( 32) where, the beam propagates to z-direction, 22 2 x y  . On the beam center, 0 , the Eq.( 32) represents a plan wave.  ...

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Wave Propagation 2010 Part 14 pot

Wave Propagation 2010 Part 14 pot

... # 0 20 1 .2 0.1 -3.48 10 .24 0 2# 8 0 1 .2 0.1 -7.83 18.00 0 3# 12 0 1 .2 0.1 -9.35 18.00 0 4 # 20 0 1 .2 0.1 -8.48 17.78 0 5 # 8 12 1 .2 0.1 -11 .21 16.16 1.5 6 # 12 8 1 .2 0.1 -13.36 14 .24 2. 8 ... 12 8 1.5±0.1 -23 .07 12. 16 5 8 # 12 8 2. 2±0.1 -23 .23 12. 8 4.4 9 # 12 8 2. 7±0.1 -19.95 8.16 2. 56 Table 3. Microwave absorption properties of prepared CNTs/T-ZnO/EP compo...

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Wave Propagation 2011 Part 1 docx

Wave Propagation 2011 Part 1 docx

... H Aly 11. Wave Propagation in Elastic Media with Micro/Nano-Structures 20 1 G. L. Huang, C.T. Sun and F. Song 12. Wave Propagation in Carbon Nanotubes 22 5 Lifeng Wang, ... (21 ) In Eq. (21 ), ν 0 is the Poisson ratio obtained from the back ground Lamé constants λ 0 and μ 0 , k L , and k T are the wavenumber of the P and S waves obtained from...

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Wave Propagation 2011 Part 3 pdf

Wave Propagation 2011 Part 3 pdf

... wave equation. Thus we get form (55): () 1 22 21 2 1 22 2 2 2 2 2 1) 2 = 12 , nn nn n ccc ccc tD xxx c tD y ηηη − − −+ ⎛⎞ ∂∂∂ ⎟ ⎜ ⎟ ⎜ Δ+−+ ⎟ ⎜ ⎟ ⎟ ⎜ ∂∂∂ ⎝⎠ ∂ +Δ ∂   (57) () () 11 22 21 2 1 22 2 21 ... KNOutKeτττ τ − −≤ +  Part 1.) The differential equations are given by: 22 2 1 12 222 =() () , (, ) mm anal anal anal uuu Dt Dt t t t txy + ∂∂∂ +∈ ∂∂∂ ( 52)...

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Wave Propagation 2011 Part 4 doc

Wave Propagation 2011 Part 4 doc

... ⎦ FU K FU pp h p h p , (23 ) where () () () () 11 01 01 12 01 01 01 12 01 12 11 12 11 22 21 12 11 22 12 02 11 12 12 01 01 12 12 12 01 12 21 11 22 21 22 21 11 22 12 −− −− ⎡ ⎤ +− −− ⎢ ⎥ = ⎢ ⎥ −−− ⎢ ⎥ ⎣ ⎦ KKKK ... following scheme for the two dimensional wave equation: 22 22 1 ,11,,1, 22 22 ,1 1,,1, 22 2, 1,,1 22 1 22 1 1 ,11,, 1) ( ) ( 2 ) = 2 ( )(1...

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Wave Propagation 2011 Part 13 pdf

Wave Propagation 2011 Part 13 pdf

... 1 21 E mm mc m aJaJa aa ξξ ξ + − ⎡ ⎤ =− ⎢ ⎥ ⎣ ⎦ , () () () () 2 266 66 12 1 2 2 13 2 13 2 13 2 2 22 1 EE EE m m cc aJaikcecmmJa aa ξ ξ ημ ξ ξ + ⎡⎤ =++−+− ⎢⎥ ⎣⎦ , () () () 22 2 44 2 15 2 1 2 2 E mm m aikceJaJa a ημξξξ + ⎡⎤ ⎡⎤ =− ... ξ + − ⎡ ⎤ =− + ⎢ ⎥ ⎣ ⎦ , () () () () 2 266 66 12 1 2 2 13 2 13 2 13 2 2 2 2 1 E E EE m m c c aIaikcecmmIa aa ξ ξημξ ξ + ⎡...

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Wave Propagation 2011 Part 14 ppt

Wave Propagation 2011 Part 14 ppt

... relation (23 ) provides then for the electromagnetic modes 2 22 2 2 , FI 00 22 22 ==1 2 12 . pe x yy th th x th x th kc v v Z v v kv kv ω ωω ωω ⎡ ⎤ ⎛⎞⎛⎞ +++ ⎢ ⎥ ⎜⎟⎜⎟ ⎢ ⎥ ⎝⎠⎝⎠ ⎣ ⎦ ε (24 ) The ... as (16) The wave is approximated to be ω~u n λ /2 κλ D 2 ~10 5 s -1 with k r =2 /λ, u n ~10 2 , κ~10 -2 . Then, we have the wave length λ~10 (2 λ D 2 )~0.1 mm. T...

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Wave Propagation 2011 Part 17 doc

Wave Propagation 2011 Part 17 doc

... % % % SK1 SPT 1 1.00-1.45 0 98 42 22 20 CI 32 98 46 SPT2 2. 00 -2. 45 0 87 27 20 7 CL 32 87 18 UD1 2. 50-3.00 0 85 26 20 6 CL 32 85 16 SPT 3 3.00-3.45 50 21 NPNPNP GM 9 SPT 4 4.50-4.95 59 ... element should be replaced by (using β 2 = εμ − − 2 0 c sin 2 θ and − 2 0 c= ε 0 μ 0 ) ωμ θ ωμ θ μμ −− ⎡ ⎤ ⎡⎤ +− − +− ⎢ ⎥ ⎢⎥ ⎣⎦ ⎣ ⎦ εε 22 22 00 0 22 2 2 00 cc j(...

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