Electric Machinery Fundamentals Power & Energy 2 potx

Electric Machinery Fundamentals Power & Energy_2 potx

Electric Machinery Fundamentals Power & Energy_2 potx

... plot(amps,abs(VS(1,:)/1000),'b-','LineWidth' ,2. 0); hold on; plot(amps,abs(VS (2, :)/1000),'k ','LineWidth' ,2. 0); plot(amps,abs(VS(3,:)/1000),'r ','LineWidth' ,2. 0); ... ','LineWidth' ,2. 0); title ('\bfSecondary Voltage Versus Load'); xlabel ('\bfLoad (A)'); ylabel ('\bfSecondary Vo...

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Electric Machinery Fundamentals Power & Energy_3 docx

Electric Machinery Fundamentals Power & Energy_3 docx

... plot(amps,VR(1,:),'b-','LineWidth' ,2. 0); hold on; plot(amps,VR (2, :),'k ','LineWidth' ,2. 0); plot(amps,VR(3,:),'r ','LineWidth' ,2. 0); title ('\bfVoltage ... plot(amps,abs(VSP(1,:)),'b-','LineWidth' ,2. 0); hold on; plot(amps,abs(VSP (2, :)),'k ','LineWidth' ,2. 0); plot(amps...

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Electric Machinery Fundamentals Power & Energy_4 pptx

Electric Machinery Fundamentals Power & Energy_4 pptx

... part of the autotransformer 72 1 22 2 1 M V B RC ω = + and 2 222 1 M RC V B RC ω ω − = + Therefore, the forced solution to the equation is () , 22 2 22 2 sin cos 11 MM Cf VRCV vt ... the beginning of the half- cycle: () 0 22 2 22 2 0 sin 0 cos 00 11 MM RC C VRCV vAe RC RC ω ωω − =+ − = ++ 22 2 0 1 M RC V A RC ω ω −= + 22 2 1 M RC V A RC ω ω = +...

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Electric Machinery Fundamentals Power & Energy_5 docx

Electric Machinery Fundamentals Power & Energy_5 docx

... plot(t,vb,'r:','Linewidth' ,2. 0); plot(t,vc,'k ','Linewidth' ,2. 0); title('\bfPhase Voltages'); xlabel('\bfTime (s)'); ylabel('\bfVoltage (V)'); grid ... ylabel('\bfVoltage (V)'); grid on; legend('Phase a','Phase b','Phase c'); hold off; 86 1 22 2 1 M V B RC ω = +...

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Electric Machinery Fundamentals Power & Energy_6 doc

Electric Machinery Fundamentals Power & Energy_6 doc

... plot(Pload,PB,'k ','LineWidth' ,2. 0); plot(Pload,PC,'r ','LineWidth' ,2. 0); plot([0 10],[3 3],'k','LineWidth',1.0); plot([0 10],[0 0],'k:'); ... plot(I,abs(VT_unity),'k ','LineWidth' ,2. 0); plot(I,abs(VT_lead),'r ','LineWidth' ,2. 0); title ('\bfTerminal Voltage Versus...

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Electric Machinery Fundamentals Power & Energy_8 ppt

Electric Machinery Fundamentals Power & Energy_8 ppt

... plot(If,abs(Ia_nl),'k-','Linewidth' ,2. 0); hold on; plot(If,abs(Ia_half),'b ','Linewidth' ,2. 0); plot(If,abs(Ia_full),'r:','Linewidth' ,2. 0); xlabel('\bfField ... A jX X=+ +EE I 1 52 The resulting plot is shown below 350 400 450 500 550 600 650 700 20 0 21 0 22 0 23 0 24 0 25 0 26 0 E A (V) I A (A) Synchr...

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Electric Machinery Fundamentals Power & Energy_9 doc

Electric Machinery Fundamentals Power & Energy_9 doc

... . ()( ) () 22 22 20 SL S L L SL RR X X VVR RR +++ − += ()( ) () 22 2 SL S L LSL RR X X RRR +++ = + () 2 22 2 22 2 SSLLSL SLL RRRRXX RRR++++=+ () 2 22 2 2 SL SL L RR ... MMM M RX X X XX X RXX ++ = ++ . If 1M XR>> and 1M XX>> then 22 2 111MMM XX R X X X>> + and () 2 22 11 MM XX X R+≈>> , so 2 1 TH 1 2 M M XX...

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Electric Machinery Fundamentals Power & Energy_11 ppt

Electric Machinery Fundamentals Power & Energy_11 ppt

... (8-56). 23 0 figure(1); plot(t_ind,n,'b-','LineWidth' ,2. 0); hold on; xlabel('\bf\tau_{ind} (N-m)'); ylabel('\bf\itn_{m} \rm\bf(r/min)'); title ('\bfSeries ... these conditions is () 22 4.8 V 900 r/min 803 r/min 25 2 V A o Ao E nn E == = The power converted from electrical to mechanical form is ()() conv 22 4.8 V 101.3 A 2...

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Electric Machinery Fundamentals Power & Energy_12 pptx

Electric Machinery Fundamentals Power & Energy_12 pptx

... (['Vt = ' num2str(Vt(ii)) ' V']); disp (['If = ' num2str(i_f(ii)) ' A']); % Plot the curves figure(1); plot(i_f,Ea,'b-','LineWidth' ,2. 0); ... current'); axis ([0 5 0 150]); set(gca,'YTick',[0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150]') set(gca,'XTick',[0 0.5 1.0 1.5 2. 0 2. 5 3....

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Electric Machinery Fundamentals Power & Energy_13 pptx

Electric Machinery Fundamentals Power & Energy_13 pptx

... ()() 22 22 / / M F M Rs jX jX Z R s jX jX + = ++ ()() 100 2. 40 60 2. 96 2. 46 10 02. 4060 F jj Zj jj + ==+Ω ++ () () () 22 22 /2 /2 M B M R s jX jX Z R s jX jX = −+ + ()() 1 .28 2 2. 40 ... disp (['Ea = ' num2str(Ea(ii)) ' V']); disp (['Vt = ' num2str(Vt(ii)) ' V']); disp (['If = ' num2str(i_f(ii)) ' A&a...

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