Mesoscopic Non-Equilibrium Thermodynamics Part 1 ppt
... Olivier Baudouin Part 2 Chapter 10 Chapter 11 Chapter 12 Chapter 13 Chapter 14 Chapter 15 Chapter 16 Chapter 17 Chapter 18 Chapter 19 Chapter 20 18 Thermodynamics 10 .3 Exponential entropic form This ... (35) p i =(Z q ) 1 [ 1 − (1 −q) β i ] 1/ (1 q) Z q = ∑ i [ 1 − (1 −q) β i ] 1/ (1 q) . (72) 19 New Microscopic Connections of Thermodynamics
Ngày tải lên: 21/06/2014, 05:20
... transverse relaxation rates ( R1 = 1/ T1 and R2 = 1/ T2, respectively) were determined for the free protein and the complexes with ligands. Amide 15 N and 1 H- 15 N resonance assignments in ... Luisana Astudillo Chapter 12 Some Applications of Thermodynamics for Ecological Systems 319 Eugene A. Silow, Andrey V. Mokry and Sven E. Jørgensen Chapter 13 Statistical Thermodynam...
Ngày tải lên: 19/06/2014, 08:20
Mesoscopic Non-Equilibrium Thermodynamics Part 3 ppt
... classical thermodynamics and chemical reaction processes. In particular, we developed a nonlinear compartmental 70 Thermodynamics 12 Thermodynamics It follows from Definition 3 .1 and (14 )– (17 ) that ... system G, T i ∂ S(E) ∂E i 1 , i = 1, ,q,(9) 58 Thermodynamics Heat Flow, Work Energy, Chemical Reactions, and Thermodynamics: A Dynamical Systems Perspective 11 It foll...
Ngày tải lên: 21/06/2014, 05:20
Mesoscopic Non-Equilibrium Thermodynamics Part 7 pptx
... 12 12 1 2 ˆˆ () () ()Jt J t J t , aD D D D =+ (14 ) where a is a dimensionality factor, or equivalently 12 21 ˆˆ () () (), Jt aDJ t aDJ t=+ (15 ) according to Eq. (13 ) we obtain 12 2 1 () ... − ⎡ ⎤ ⎣ ⎦ (16 ) Term-by-term comparison of Eqs. (15 ) and (16 ) leads to the identification of the currents 11 1 ˆ () ( ,) Jt D pt ρ = (17 ) and 222 ˆ () ( ,) Jt D pt ρ =− (18 )...
Ngày tải lên: 21/06/2014, 05:20
Mesoscopic Non-Equilibrium Thermodynamics Part 9 pptx
... Butterworth-Heinemman, Ltd, 19 84. [9] Marcus R. A. J. Phys. Chem. 19 94, 98: 717 0. [10 ] Johnson M. D., Miller J. R., Green N. S., Closs G. L. J. Phys. Chem. 19 89, 93: 11 73. [11 ] Formasinho S. J., ... 0, ρ ∂v i ∂t + ∂p ∂x i + 2ρΩv j W 1ji = 0, ∂T ∂t + 1 ρc V ∂q j ∂x j = 0, ∂q i ∂t + ζ ∂T ∂x i + 2Ω − 1 2 B κL R q j W 1ji = 1 2 κL R [(B −B ) ( −q i + q 1 δ i1 )...
Ngày tải lên: 21/06/2014, 05:20
Tài liệu Spoken english elementary handbook part 1 ppt
... the IPA 19 .16 Translate Slang Phrases (Nouns) into the IPA – Answers 19 .17 IPA Test 1 19 .18 IPA Test 1 – Answers 19 .19 IPA Test 2 19 .20 IPA Test 2 – Answers 19 . 21 IPA Test 3 19 .22 IPA ... p .11 .1) • how to identify and use sentence stress (from p .12 .1) • how to identify word stress (from p .13 .1) • how to identify prefixes (from p .14 .1) • how to identify su...
Ngày tải lên: 13/12/2013, 21:15
Tài liệu Preparetaiton course for the toefl ibt reading part 1 ppt
Ngày tải lên: 14/12/2013, 10:15