... =2,p =(p 1 ,p 2 ): f(x, a, b) ·p + r(x, a, b)=(m 1 − c 1 bx 2 )p 1 +(m 2 − c 2 ax 1 )p 2 + (1 a)x 1 − (1 −b)x 2 = m 1 p 1 + m 2 p 2 + x 1 − x 2 + a(−x 1 − c 2 x 1 p 2 )+b(x 2 − c 1 x 2 p 1 ). Since ... 1) 2 +(x 2 ) 2 (t))=2(x 1 (t) 1) ˙x 1 (t)+2x 2 (t)˙x 2 (t) =2(x 1 (t) 1) x 2 (t)+2x 2 (t)(−x 1 (t) +1) =0. Consequently, the motion satisfies (x 1 (t) − 1)...
Ngày tải lên: 24/03/2014, 12:20