Torque Control Part 5 pptx
Torque Control Part 5 pptx
...
0.3 0. 35 0.4 0. 45 0 .5 0 .55 0.6
0
0 .5
1
1 .5
2
Torque (pu)
0.3 0. 35 0.4 0. 45 0 .5 0 .55 0.6
0.7
0.8
0.9
1
1.1
Ti me (s ec)
Rotor Speed (pu)
0.3 0. 35 0. 4 0. 45 0 .5 0. 55 0.6
0
0 .5
1
1 .5
2
Torque (pu)
0.3 ... (pu)
0.3 0. 35 0. 4 0. 45 0 .5 0. 55 0.6
0.7
0.8
0.9
1
1.1
Ti me (s ec)
Rotor Speed (pu)
Te
Te*
T
L
ω
r
*
ω
r
0.3 0. 35 0.4 0. 45 0 .5 0 .55 0.6
0
0 .5...
Torque Control Part 3 pptx
...
Torque Control
36
-1 .5 -1 -0 .5 0 0 .5 1 1 .5
-1 .5
-1
-0 .5
0
0 .5
1
1 .5
Stator f lux
0 0 .5 1 1 .5 2 2 .5 3 3 .5 4 4 .5 5
-50
-40
-30
-20
-10
0
10
20
30
40
50
Time(s )
Stator currents (A)
0 .5 ... time evolution
0 0 .5 1 1 .5 2 2 .5 3 3 .5 4 4 .5 5
0
100
200
300
400
50 0
600
700
800
900
1000
speed (rpm)
time (s)
0 0 .5 1 1 .5 2 2 .5 3 3 .5 4 4 .5...
Torque Control Part 4 pptx
... 10
-3
0.8
0.9
1
1.1
Ti me (sec )
Torque (pu)
0 5 10 15 20
x 10
-3
-1
-0 .5
0
0 .5
1
Ti me (sec )
Current i
a
(pu)
0 5 10 15 20
x 10
-3
-1
-0 .5
0
0 .5
1
Ti me (sec )
Vab (pu)
-1 0 1
-1
-0 .5
0
0 .5
1
Ψ
s
vec t or ... 20
x 10
-3
0.8
0.9
1
1.1
Ti me (s ec )
Torque (pu)
0 5 10 15 20
x 10
-3
-1
-0 .5
0
0 .5
1
Ti me (s ec )
Current i
a
(pu)
0 5 10 15 20
x 10
-3
-1
-0 .5...
Torque Control Part 7 pptx
... rotating coordinate system, we have:
[]
11 12 13 14 15 16
21 22 23 24 25 26
31 32 33 34 35 36
41 42 43 44 45 46
51 52 53 54 55 56
61 62 63 64 65 66
aaaaaa
aaaaaa
aaaaaa
A
aaaaaa
aaaaaa
aaaaaa
⎡
⎤
⎢
⎥
⎢
⎥
⎢
⎥
=
⎢
⎥
⎢
⎥
⎢
⎥
⎢
⎥
⎢
⎥
⎣
⎦
... Arias, Xavier del Toro. (20 05) . Novel direct torque control for
induction motors using schort voltage vectors of matrix converters.
I...
Torque Control Part 12 pptx
... is not controllable in the passive
converter, the voltage of the boost capacitor is changed by the stored magnetic energy
222
Torque Controlo
Torque Control
210
Fig. 11. Average torque ... parallel type front-ends are not controlled. Detailed
characteristics are analyzed in Table 1.
214
Torque Controlo
Torque Control
226
2.1.1 Switching angle control method
In SRM d...
Torque Control Part 14 pptx
...
error as:
cm
eX X=−
(52 )
and
1 cm
eYY
=
− (53 )
Substituting (50 )- (51 ) into (52 ) and (53 ), one can obtain
T
mm
eAeB
θ
φ
=+
(54 a)
and
1
T
m
eCe= (54 b)
By letting
*
mm
BBK= ... (49)
Torque Control
250
(a) Reference torque, total torque and phase currents in linear TSF
(b) Reference torque, total torque and phase currents in cosine TSF
(c...
torque control Part 5 docx
... 0.6
0
0 .5
1
1 .5
2
Torque (pu)
0.3 0. 35 0.4 0. 45 0 .5 0 .55 0.6
0.7
0.8
0.9
1
1.1
Ti me ( sec)
Rotor Speed (pu)
0.3 0. 35 0. 4 0. 45 0 .5 0 .55 0. 6
0
0 .5
1
1 .5
2
Torque (pu)
0.3 0. 35 0. 4 0. 45 0 .5 0 .55 0. 6
0.7
0.8
0.9
1
1.1
Ti ... 0. 35 0. 4 0. 45 0 .5 0. 55 0.6
0
0 .5
1
1 .5
2
Torque (pu)
0.3 0. 35 0. 4 0. 45 0 .5 0. 55 0.6
0.7
0.8
0.9
1
1.1
Ti me (s e...
Tài liệu Complete guide to toeic test part 5 pptx
... “in seconds.”
Reading
Part 5
101. C 111. D 121. A 131. B
102. D 112. B 122. B 132. A
103. B 113. A 123. D 133. C
104. D 114. B 124. D 134. D
1 05. A 1 15. B 1 25. C 1 35. A
106. C 116. D 126. ... ask the company to hire a
Chinese tutor.
53 . _____ What is Tammy’s primary reason for going to
China?
54 . _____ What is Tammy’s biggest problem?
55 . _____ What does the man suggest Tammy...
Tài liệu Master toefl vocabulary part 5 pptx
... against contrary
de from, down delete, descend
dis, di apart disperse, dilate
ex, e out exit, elicit
03_TOEFL Vocab,Ch3,27-60 8/4/06, 12:3034
36 PART III: TOEFL Vocabulary Review
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8. ... excellent.
after the operation...