Supply Chain Management 2011 Part 2 docx

Supply Chain Management 2011 Part 2 docx

Supply Chain Management 2011 Part 2 docx

... Paradigms in Supply Chain Management (LARG_SCM) 35 3. Deployment of LARG_SCM 3.1 Supply chain management practices and attributes According to Morash (20 01) supply chain management paradigms ... of the different supply chain paradigms. Supply chain attributes are key aspects of the supply chain strategies and determine the entire supply chain behavio...

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Supply Chain Management 2011 Part 1 docx

Supply Chain Management 2011 Part 1 docx

... − C +2 2, − C +2 B 1 − 1, − C +2 B 1 , − C +2 μ 1 μ 2 μ 1 μ 1 μ 1 μ 1 μ 1 μ 1 μ 1 μ 1 μ 2 μ 2 μ 2 λ λ λ λ λ λ λ λ λ λ λ λ μ 2 μ 2 μ 2 μ 2 μ 2 μ 2 μ 2 μ 2 ... figure 5. 0, B 2 1, B 2 2, B 2 B 1 − 1, B 2 B 1 , B 2 1, B 2 − 1 2, B 2 − 1 B 1 − 1,B 2 − 1 B 1 , B 2 − 1 1, − C+1 2, − C+1...

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Supply Chain Management 2011 Part 3 docx

Supply Chain Management 2011 Part 3 docx

... province, South Africa; African Journal of Business Management, (December 20 08), Vol .2 ( 12) , pp. 23 0 -24 2. Mkhize, Z. (20 04). Supply Chain Management Conference: Transforming Government Procurement ... Zacharia, Z. G. (20 01). "Defining Supply Chain Management. " Journal of Business Logistics, Vol 22 , No 2, pp.1 -25 . McAdam, R., Hazlett, S.A. & Ca...

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Supply Chain Management 2011 Part 11 docx

Supply Chain Management 2011 Part 11 docx

... Table 2. T p =1 − << + − 2 21 1 ii w ii TT T TT , < <01 i T > + 2 21 i w i T T T , > 1 i T T p =2 −− − − + −− + − + << −− −− 22 22 (3 9 2 1) (3 9 2 1) 2( 1) 2( 1) iiii ... 1.618 i T −− − − + > −− 2 2 (3 9 2 1) 2( 1) iiii w ii TTTT T TT > 1.618 i T T a =1 ,2 T p =3 −− +− − − ++ << +−−+ 22 34 32 (4 2 3 8 4 16 1 16 ) 2...

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Supply Chain Management 2011 Part 15 doc

Supply Chain Management 2011 Part 15 doc

... 21 140,000P = , 21 0.83g = , 21 2h = , 21 300S = , 21 50A = , 21 8B = , 21 0.001C = ; 22 0 χ = , 22 50,000D = , 22 150,000P = , 22 0.81g = , 22 2. 1h = , 22 310S = , 22 45A = , 22 7B ... 3 2( 300)(378,036.84 20 3,400) $18,677.85TC ∗ =+= per year, (28 9,050 100,000)(3)(0.0 321 2) 20 3,400(0.0 321 2) 120 0 20 3 32 2 2 2 3(0.0 321 2) 0.0 321 2 24 9 $31 ,...

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Supply Chain Management 2011 Part 16 ppt

Supply Chain Management 2011 Part 16 ppt

... 21 140,000P = , 21 0.83g = , 21 2h = , 21 300S = , 21 50A = , 21 8B = , 21 0.001C = ; 22 0 χ = , 22 50,000D = , 22 150,000P = , 22 0.81g = , 22 2. 1h = , 22 310S = , 22 45A = , 22 7B ... 3 2( 300)(378,036.84 20 3,400) $18,677.85TC ∗ =+= per year, (28 9,050 100,000)(3)(0.0 321 2) 20 3,400(0.0 321 2) 120 0 20 3 32 2 2 2 3(0.0 321 2) 0.0 321 2 24 9 $31 ,...

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Supply Chain Management 2011 Part 4 ppt

Supply Chain Management 2011 Part 4 ppt

... correlation with performance” (Akyuz & Erkan 20 09: 12) . Supply Chain Management 136 Source DF AdjSS AdjMS F P Main Effects 5 39,65 7,93 20 , 32 0,001 2- Way interactions 10 39,46 3,94 10,11 0,005 ... www.supplychainmaturity.nl Supply Chain Management Based on Modeling & Simulation: State of the Art and Application Examples in Inventory and Warehouse Managemen...

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Supply Chain Management 2011 Part 5 doc

Supply Chain Management 2011 Part 5 doc

... 520 ,00 5809,39 1st Tier A 1108,64 20 02, 55 3111,19 1st Tier B 21 17 ,27 8 02, 55 29 19, 82 1st Tier C 6411, 82 2153,00 8564, 82 Supply chain 14 927 , 12 5478,10 20 405 ,22 Table 5. Scenario (1) costs for ... 2 3 4 5 1 - - 84 159 535 2 - - 51 731 670 3 57 23 5 27 6 55 622 4 - 76 22 7 24 8 134 5 69 100 196 355 395 6 27 85 101 6 46 7 659 570 743 10 72 122 1 8 1...

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Supply Chain Management 2011 Part 6 pdf

Supply Chain Management 2011 Part 6 pdf

... Supply Chain Management 22 2 Features |Attacks Weights Skimming Eavesdropping MIM Physical attack Features 70.0% 19 .2 19.4 24 .2 30.3 Time 30.0% 0.9 2. 0 2. 6 3.5 Sum 100.0% 20 .0 21 .4 ... 42. 82% 22 .50% 41.74% IPSEC 10.01% 21 .40% 23 .35% 32. 87% 15.86% Overall Consistency of Hierarchy 5.64% Table 25 . SA Criteria’s and Techniques for Testing Cost Using A...

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Supply Chain Management 2011 Part 7 doc

Supply Chain Management 2011 Part 7 doc

... as max p 1 ,d 1  ∞ 0 e −rt  C ν 1 x + 1 2 K ν 1 p 2 1 − 1 2 C h 1 d 2 1 −C u 1 (1 −d 1 ) √ x − E n ζτ  dt (22 ) max p 2 ,d 2  ∞ 0 e −rt  C ν 2 (1 − x)+ 1 2 K ν 2 p 2 2 − 1 2 C h 2 d 2 2 −C u 2 (1 −d 2 ) √ 1 − x − E n ζτ  dt Subject ... + 1 2 K ν 1 p 2 1 , (15) ν 2 (x, p 1 )=C ν 2 (1 −x)+ 1 2 K ν 2 p 2 2 , (16) h 1 (d 1 )= 1 2 C h 1 d 2 1 ,...

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