Microsensors Part 3 pptx

Microsensors Part 3 pptx

Microsensors Part 3 pptx

... InP, 211 0. 23 H Ch mV s     ; Magnetic Microsensors 23 MGT2: InP, 211 0. 23 H Ch mV s     ; MGT3: GaAs, 211 0. 43 H Ch mV s     . The geometry influence upon off B is shown ... Fig. 2. 13. The NEMI depending on drain current, for threedevices of different materials. MGT1: Si, 211 0.07 H Ch mV s     MGT2: InP, 211 0. 23 H Ch mV s     ; Magneti...

Ngày tải lên: 19/06/2014, 21:20

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Tài liệu Spoken english elementary handbook part 3 pptx

Tài liệu Spoken english elementary handbook part 3 pptx

... Students 2.9 Connected Sentence Cards 3. Instructions 3. 1 Activity Template (Blank) 3. 2 Sample Lesson Plan 3. 3 Sound Connections Demo 3. 6 Going Further 3. 15 Connected Speech Templates ... Exchanges 6. Instructions 6.1 Activity Template (Blank) 6 .3 Multi-Purpose Texts 7. Instructions 7.1 Reading Race – Lesson Plan 7 .3 Discussion Questions 8. Instruc...

Ngày tải lên: 13/12/2013, 21:15

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Tài liệu Exchange 2007 part 3 pptx

Tài liệu Exchange 2007 part 3 pptx

... Mailbox, nhấn New g. Nhấn Finish h. Kiểm tra lại user Hoang Phung Bao đã có được mailbox 3. Tạo Mail Enable User : a. Exchange 2007 Tài liệu dành cho học viên VSIC Education Corporation ... e. Nhấn Next Exchange 2007 Tài liệu dành cho học viên VSIC Education Corporation Trang 23 e. Trong Mailbox Settings kiểm tra: - Alias - Server - Storage group : First S...

Ngày tải lên: 14/12/2013, 13:15

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Tài liệu Cách Xem Dữ liệu Trong .NET part 3 pptx

Tài liệu Cách Xem Dữ liệu Trong .NET part 3 pptx

... ScrollingDataBinding() { this.AutoScaleBaseSize = new System.Drawing.Size(5, 13) ; this.ClientSize = new System.Drawing.Size(464, 2 53) ; this.Text = "09_ScrollingDataBinding"; this.retrieveButton ... textQuan.Location = new System.Drawing.Point(4, 55); textQuan.Text = ""; textQuan.TabIndex = 3; textQuan.Anchor = AnchorStyles.Top | AnchorStyles.Left | An...

Ngày tải lên: 15/12/2013, 02:16

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Tài liệu Partial Differential Equations part 3 pptx

Tài liệu Partial Differential Equations part 3 pptx

... contrast, ψ n+1 j =(1+iH∆t) −1 ψ n j (19.2 .34 ) These are both first-order accurate in time, as can be seen by expanding equation (19.2 .32 ). However, neither operator in (19.2 .33 ) or (19.2 .34 ) is unitary. 19 .3 Initial Value ... the form i ∂ψ ∂t = Hψ (19.2 .30 ) where the operator H is H = − ∂ 2 ∂x 2 + V (x)(19.2 .31 ) The formal solution of equation (19.2 .30 ) is ψ(x, t)=e −iHt ψ(x,...

Ngày tải lên: 15/12/2013, 04:15

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Tài liệu Evaluation of Functions part 3 pptx

Tài liệu Evaluation of Functions part 3 pptx

... like this: f(x)=b 0 + a 1 b 1 + a 2 b 2 + a 3 b 3 + a 4 b 4 + a 5 b 5 +··· (5.2.1) Printers prefer to write this as f(x)=b 0 + a 1 b 1 + a 2 b 2 + a 3 b 3 + a 4 b 4 + a 5 b 5 + ··· (5.2.2) In either ... 5 .3 Polynomials and Rational Functions 1 73 Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright (C) 1988-1992 ... without choos...

Ngày tải lên: 15/12/2013, 04:15

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Tài liệu Root Finding and Nonlinear Sets of Equations part 3 pptx

Tài liệu Root Finding and Nonlinear Sets of Equations part 3 pptx

... f(x 1 ),f(x 3 ),f(x 2 ), but to the values f(x 1 ),f(x 3 )e Q ,f(x 2 )e 2Q , yielding a new guess for the root, x 4 .The overall updating formula (incorporating the solution 9.2 .3) is x 4 = x 3 +(x 3 −x 1 ) sign[f(x 1 ) ... gives f(x 1 )− 2f(x 3 )e Q + f(x 2 )e 2Q =0 (9.2.2) This is a quadratic equation in e Q , which can be solved to give e Q = f(x 3 )+sign[f(x 2 )]  f(x 3 )...

Ngày tải lên: 15/12/2013, 04:15

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