Biosensors Emerging Materials and Applications Part 1 doc

Ngày tải lên: 14/12/2013, 13:15

... qbar, set, and reset. The root module instantiates m1, which is a module of type SR_latch. The module m1 instantiates nand gates n1 and n2. Q, Qbar, S, and R are port signals in instance m1. Hierarchical ... endmodule stimulus.qbar stimulus.set stimulus.reset stimulus.m1 stimulus.m1.Q stimulus.m1.Qbar stimulus.m1.S stimulus.m1.R stimulus.n1 stimulus.n2 Each identifier in the...

Ngày tải lên: 15/12/2013, 03:15

... y0 w1 h1" alt=""

Ngày tải lên: 26/01/2014, 00:20

... Netherlands 19 90 19 92 19 94 19 96 19 98 2000 2002 2004 2006 1. 50 1. 75 Austria 19 90 19 92 19 94 19 96 19 98 2000 2002 2004 2006 1. 70 1. 90 Poland 19 90 19 92 19 94 19 96 19 98 2000 2002 2004 2006 2.06 2 .14 2.22 Portugal 19 9 019 9 219 9 419 9 619 982000200220042006 1. 6 1. 9 2.2 Slovenia 19 90 ... 2006 3.4 3.8 4.2 Greece 19 90 19 92 19 94 19 96 19 98 2000 20...

Ngày tải lên: 19/06/2014, 08:20

... 538 Chapter 13 . Fourier and Spectral Applications Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8-5) Copyright (C) 19 88 -19 92 by Cambridge University ... copied into channel j − 1; and so on for both positive and negative values of k in r k . Figure 13 .1. 2 illustrates the situation. Example: a response function with r 0 = 1and a...

Ngày tải lên: 21/01/2014, 18:20

... is thicker and longer than that for lumbar puncture ( > Figure 1. 2); it is about 16 cm long and its internal diameter is about 1 mm; it is useful for cardiac, urinary bladder and suboccipital ... quanti cation and linearity, and the selectivity and precision of the assay in their own hands. Inter- nal standardization is always the preferred approach, although use of ex...

Ngày tải lên: 22/01/2014, 00:20

... form, c 0 = (1+ √ 10 +  5+2 √ 10 ) /16 √ 2 c 1 =(5+ √ 10 + 3  5+2 √ 10 ) /16 √ 2 c 2 = (10 −2 √ 10 + 2  5+2 √ 10 ) /16 √ 2 c 3 = (10 −2 √ 10 − 2  5+2 √ 10 ) /16 √ 2 c 4 =(5+ √ 10 −3  5+2 √ 10 ) /16 √ 2 c 5 = (1+ √ 10 ... = -1. 0; static float c4[5]={0.0,0.482962 913 14453 41, 0.836 516 3037378079, 0.22 414 3868042 013 4,-0 .12 94095225 512 604}; static float c12 [13 ]...

Ngày tải lên: 26/01/2014, 14:20

... representation (13 .11 .3) into (13 .11 .6) and performing the resulting elementary contour integrals, we obtain w(z) ≈ 1 πi ∞  n=−∞ he −t 2 n 1 − ( 1) n e −πi(α−z)/h t n − z (13 .11 .7) 606 Chapter 13 . Fourier and ... moderate values of N. For example, |e(t)| < 5 × 10 −5 for h =1/ 2and N =7;|e(t)|<2 10 10 for h =1/ 3and N =15 ; and |e(t)| < 7 × 10 18 for h...

Ngày tải lên: 26/01/2014, 14:20

... w 2 0 (1 + w 0 ) 2 + w 2 0 c 2 = 1+ w 2 0 (1 + w 0 ) 2 + w 2 0 d 1 =2 1  2 w 2 0 −w 2 0 (1 + w 0 ) 2 + w 2 0 d 2 = − (1 − w 0 ) 2 + w 2 0 (1 + w 0 ) 2 + w 2 0 (13 .5 .15 ) Figure 13 .5 .1 shows ... )= M  k=0 c k e −2πik(f∆) 1 − N  j =1 d j e −2πij(f∆) (13 .5.2) 560 Chapter 13 . Fourier and Spectral Applications Sample page from NUMERICAL RECIPES IN C: THE ART...

Ngày tải lên: 26/01/2014, 14:20