... d⋅πf 23 5.80 17.17 9.93++ 26 2.9 ==kN/m 2 2 62, 900= N/m 2 Pp101, 325 N/m 2 = ;πp0, assumed.= 26 2,900 0–[]–1= ,460,780 N/m 2 s 1 2. 68 2. 26–15.17 14.19– – 1 0.43– 0.57===αmo1 0.57–()14.19 2. 26–1 ... membrane according to the following reaction:C=O(CH 2 CH 2 NH)nCH 2 CH 2 NH + 2 (CH 2 CH 2 N)nCH 2 CH 2 N – C(CH 2 CH 2 N)nCH 2 CH 2 N –COOCl–4HCIClIsophthaloylchloridePolyethylene ... constants.CH 2 OH 2 CO+→ 175,440++kJ/kgmol2CO O 2 2CO 2 → 393–+ ,790 kJ/kgmol2H 2 O 2 2H 2 O→ 396,650 –+ kJ/kgmolXM kC[]1/n=XM ab C[]1 bC[]+ =TX249_frame_C08.fm Page 393 Friday, June 14, 20 02...