Ngày tải lên: 14/12/2013, 13:15
... endmodule 4 .2. 3 Port Connection Rules One can visualize a port as consisting of two units, one unit that is internal to the module and another that is external to the module. The internal and external ... b, and c_in and produces an output on ports sum and c_out. Thus, module fulladd4 performs an addition for its environment. The module Top is a top-level module in the simula...
Ngày tải lên: 15/12/2013, 03:15
Tài liệu Timing and Delay part 2 ppt
... endspecify and a1(e, a, b); and a2(f, c, d); and a3(out, e, f); endmodule The full connection is particularly useful for specifying a delay between each bit of an input vector and every ... //a[31:0] is a 32- bit vector and out[15:0] is a 16-bit vector //Delay of 9 between each bit of a and every bit of out specify ( a *> out) = 9; // you would need 32 X 16 = 3 5...
Ngày tải lên: 15/12/2013, 03:15
Tài liệu Project Planning and Control Part 2 pptx
... nodes in band 1 would be numbered 101, 1 02, 103, etc., while the nodes in band 2 are numbered 20 1, 20 2, 20 3, etc. Figure 21 .1 would lend itself to this type of numbering. Coordinates This method ... and one at the end (Figure 11.1). Thus events 1 and 2 in the figure show the start and finish of activity A. The arrow head indicates that 1 comes before 2, i.e. the operation...
Ngày tải lên: 26/01/2014, 11:20
Sustainable Energy Harvesting Technologies Past Present and Future Part 2 ppt
... – Past, Present and Future 18 Will-be-set-by-IN-TECH DEHAR minimum DD minimum Time (h) % of full charge DD DEHAR 0 48 96 144 1 92 240 28 8 336 384 4 32 480 528 576 624 6 72 720 91 92 93 94 95 96 97 98 99 100 Fig. ... f DEHAR (t) and f DD (t), then the curve in this figure is characterised by f DEHAR (t) − f DD (t). Time (h) Power (μW) 0 24 48 72 96 120 144 168 1 92 216 24 0 0 0....
Ngày tải lên: 19/06/2014, 08:20
Tài liệu PRIVATE ENTREPRENEURS IN CHINA AND VIETNAM PART 2-1 ppt
... % 8 -20 12 17.9 13 21 .7 20 41.7 21 -50 16 23 .9 19 31.7 14 29 .2 51-100 16 23 .9 16 26 .7 4 8.3 101 -20 0 13 19.4 6 10.0 5 10.4 20 1-500 7 10.4 4 6.7 4 8.3 501-1.000 2 3.0 2 3.3 1 2. 1 1.001 -2. 000 ... < 20 35 39.3 10 31.3 55 67.9 21 -50 23 25 .8 10 31.3 13 16.1 51-100 16 18.0 6 18.7 7 8.6 101 -20 0 6 6.7 3 9.4 3 3.7 20 1-500 2 2.3 1 3.1 1 1 .2 501-1.000...
Ngày tải lên: 15/12/2013, 06:15
Tài liệu RESEARCH AND WRITING SKILLS SUCCESS PART 2 ppt
... in just 20 short lessons of 20 minutes a day by using basic research and writing tools that you can practice at home. Each lesson is carefully designed to make researching any topic and writing ... Bibliography 95 LESSON 20 Writing an Annotated Bibliography, a Historiography, and an Abstract 99 POST-TEST 105 APPENDIX A A List of Research Topics 119 APPENDIX B Additional Resources 12...
Ngày tải lên: 24/12/2013, 14:16
Tài liệu Teaching and learning english part 2 ppt
... 40,0% ( 12) 23 ,3% (7) 36,7% (11) 11 Interview ( interviewing for a job, etc) 23 ,3% (7) 16,7% (5) 60,0% (18) 12 Performing a dialogue 66,6% (20 ) 26 ,7% (8) 6,6% (2) 13 Playing games 40,0% ( 12) 46,7% ... the question orally 73,4% (22 ) 13,3% (4) 13,3% (4) 4 Expressing opinion orally 50,0% (15) 26 ,7% (8) 23 ,3% (7) 5 Seeking and giving information 40,0% ( 12) 36,7% (11) 23 ,3% (7...
Ngày tải lên: 21/01/2014, 22:20
Tài liệu Drugs and Poisons in Humans - A Handbook of Practical Analysis (Part 2) pptx
... hair (parietal region) 0–0 .2 0 .2 1.0 1.0 2. 0 2. 0–3.0 10.8 1.38 2. 19 0.68 Pubic hair 0–0 .2 0 .2 2. 0 2. 0–5.0 25 .2 0.76 0.08 Finger nail (left thumb) 0–0.5 0.5–1.0 1.0–1.5 1.5 2. 0 0.83 0.76 0.38 0.08 Toe ... pp 21 1 -22 2. 9) Moriya F, Miyaishi S, Ishizu H (19 92) Presumption of a history of methamphetamine abuse by postmortem analyses of hair and nails: a case report. Jpn...
Ngày tải lên: 22/01/2014, 00:20
SIEMENS - simatic standard software for S7-300 and S7-400 standard functions part 2 ppt
... FALSE OUT_VAL [2, 15] DBX61.7 = FALSE S_MASK [2, 0] DBX 92. 0 = FALSE S_MASK [2, 1] DBX 92. 1 = TRUE S_MASK [2, 2] DBX 92. 2 = TRUE S_MASK [2, 3] DBX 92. 3 = TRUE S_MASK [2, 4] DBX 92. 4 = TRUE S_MASK [2, 5] DBX 92. 5 = ... be between 27 648 and 27 648, therefore, K1 = 27 648.0 and K2 = +27 648.0 • UNIPOLAR: The input integer value is assumed to be between 0 and 27 648, therefore,...
Ngày tải lên: 29/03/2014, 12:20