... equilibrium points. Hence, the control law is chosen in following form: 2 11 1 ab ukxkx , 2 222 ac ukxkx (2 .14 ) Hence, the system (2 .13 ) with set control (2 .14 ) is: 2 1 11 1 1 2 2 22 ... kx , (3 .10 ) and obtaining new control system 12 213 22 34 2 41 11 111 1 , , , . u xx kk xxx mm xx kk xx xkx mmm ...
Ngày tải lên: 19/06/2014, 08:20
... ⎣⎦ ⎣⎦⎣⎦ (20) From (18 ), (19 ) and (20) and by using the separation lemma (Shi & al, 19 92)), we finally obtain: 1 2 2 0 0 D T M T ⎡ ⎤ ≤ ⎢ ⎥ ⎣ ⎦ ( 21) Where: 11 1 1 11 111 11 11 1 1 tttt tt ij ... B −−Δ ⎡ ⎤ ⎢ ⎥ Σ= −−Δ ⎢ ⎥ ⎣ ⎦ , 11 11 2 11 11 0 0 ttt i j i iij XAXKB AX BK X ⎡⎤ Δ+ Δ ⎢⎥ Σ= Δ+Δ ⎢⎥ ⎣⎦ and 1 3 2 0 0 Δ ⎡ ⎤ Σ= ⎢ ⎥ Δ ⎣ ⎦ Let 1 11 1 11 2 , XPXP − ==....
Ngày tải lên: 19/06/2014, 08:20
RECENT ADVANCES IN ROBUST CONTROL – NOVEL APPROACHES AND DESIGN METHODSE Part 3 pot
... - 0.70i 11 111 11 () aa bb AHE BHEK−++ -2.58 +0 .10 i -2.58- 0 .10 i -2.58 + 0 .10 i -2.58 - 0 .10 i 2222222 () aa bb AHE BHEK−++ -3.09 +0.54i -3.09-0.54i -3.09 + 0.54i -3.09 - 0.54i 11 1 11 1bb AGCHEK+− ... Control – Novel Approaches and Design Methods 52 () 2 12 2 22 11 2 212 2 1 2 2 1 11 () cos( ())- () 1 () 1( ) 1( ) 1 () 1 sin( ()) -1. 5 ()-3 () 1( ) cos (...
Ngày tải lên: 19/06/2014, 08:20
RECENT ADVANCES IN ROBUST CONTROL – NOVEL APPROACHES AND DESIGN METHODSE Part 6 potx
... [1, 3] , b ∈ [0.05, 0 .1] , d ∈ [0.3, 1] 0 3 (1 0.05 ) () (1 0.35) s Ps s − = + 2 .WΔ< 1 1.8 () 2.80 s Ws s + = and 32 2 32 2(0.0074 0.333 1. 5 51 1) (.000 01 1) () 3(0.0049 0.246 1. 157 1) sss ... where η is a strictly positive constant. The control discontinuity can be found from the above inequality: 11 1 11 1 11 1 () (1) ()()sgn() () (1) () () () ( 1) ( ) es...
Ngày tải lên: 19/06/2014, 08:20
RECENT ADVANCES IN ROBUST CONTROL – NOVEL APPROACHES AND DESIGN METHODSE Part 4 ppt
... following 3 rd order reduced model: -0.6 910 1. 3088 -3.8578 -0.76 21 ( ) -1. 3088 -0.6 910 -1. 5 719 ( ) -0 .11 18 ( ) 0 0 -0.3697 0.4466 xt xt ut ⎡⎤⎡⎤ ⎢⎥⎢⎥ =+ ⎢⎥⎢⎥ ⎢⎥⎢⎥ ⎣⎦⎣⎦ 0.00 61 0.02 61 0. 011 1 ... pp. 13 13 -13 19, 19 68. [15 ] S. Haykin, Neural Networks: A Comprehensive Foundation, Macmillan Publishing Company, New York, 19 94. [16 ] W. H. Hayt, J. E. Kemmerly, a...
Ngày tải lên: 19/06/2014, 08:20
RECENT ADVANCES IN ROBUST CONTROL – NOVEL APPROACHES AND DESIGN METHODSE Part 5 pdf
... Processing, Vol. 36, No. 7, pp. 11 41- 115 1. Recent Advances in Robust Control – Novel Approaches and Design Methods 12 2 Fig. 3. Two-layer product WNN structure. 4 .1 Input layer 11 11 1 1 ; ... Fig. 17 . Bode plot of the PID controller. 10 3 10 4 10 5 10 6 -10 0 -50 0 50 magnitude [db] 10 3 10 4 10 5 10 6 -250 -200 -15 0 -10 0 -50 0 frequency [...
Ngày tải lên: 19/06/2014, 08:20
RECENT ADVANCES IN ROBUST CONTROL – NOVEL APPROACHES AND DESIGN METHODSE Part 9 docx
... ⎝⎠ ⎦ 1 , 1 ˆ 1 n n n n α + + + ⎡ ⎤ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎛⎞ ⎢ ⎥ ⎜⎟ ⎣ ⎝⎠⎦ (28) where 1 1 2 2 12 1 1 1 1 . 10 .00 ˆ 1. 00 ˆ ˆ ˆ ˆ .1 . ˆˆ .10 ˆ ˆ 12 11 ˆˆˆ .1 11 nn n n nn n k k nn nn k nn nn α χ χ αα χ ααα −− + + − = − −− − − ⎡⎤ ⎢⎥ ⎛⎞ ⎢⎥ ⎜⎟ ⎢⎥ ⎝⎠ ⎡ ⎤ ⎡⎤ ⎢⎥ ⎢ ⎥ ⎢⎥ ⎢⎥ ⎢ ⎥ ⎢⎥ ⎢⎥ ⎢ ⎥ ⎢⎥ ⎛⎞ ... or (22), are given by using the affine transformatio...
Ngày tải lên: 19/06/2014, 08:20
Integrating short stories and poems in developing the reading skills for 2nd year students in haiphong university part 1
Ngày tải lên: 07/11/2012, 14:21
Tài liệu Project Planning and Control Part 1 pptx
... 11 5.76 is to divide it by 1. 05 × 1. 05 × 1. 05 or 1. 157, for 11 5.76 1. 05 × 1. 05 × 1. 05 = 11 5.76 1. 157 = 10 0. If instead of dividing the 11 5.76 by 1. 157, it is multiplied by the inverse of 1. 157, ... were invested in a bank earning an interest of 5% The value in 1 year would be 10 0 × 1. 05 = 10 5 The value in 2 years would be 10 0 × 1. 05 × 1. 05 = 11 0.25...
Ngày tải lên: 26/01/2014, 11:20