Pro Entity Framework 4 0 - Apress 8 ppt

... ',@16=N'M ',@17=1,@ 18= 129,@19=' 200 9 -0 9 -0 7  12 :07 :26. 04 3 9 48 2',@ 20= &apos ;00 000 000 -0 0 0 0- 000 0 -0 0 0 0- 000 000 000 000 ',@21=' 200 9 -0 9 -0 7  12 :07 :26. 04 3 9 48 2' The relationship ... Kayaba',@1=N'IKAYA-R 209 ', @2=1,@3=1, @4= N'Red',@5=2 50, @6=2 50, @7=2 500 .00 00, @8= 3 900 .00...

Ngày tải lên: 18/06/2014, 16:20

... Microsoft.Data .Entity. Ctp assemblies in your UI project (CodeOnlyUI) are located here: C:\Program Files(x86)\Reference Assemblies\Microsoft \Framework\ .NetFramework\v4 .0\  Profile\Client The client profile ... and select the CodeOnlyData project, shown in Figure 1 0- 3. Click OK. CHAPTER 10 ■ CODE-ONLY DEVELOPMENT 1 68 • Code-only programming model used with the En...

Ngày tải lên: 18/06/2014, 16:20

... names would not gain anything. Figure 12 -4 . EntityType and EntitySet properties We can also verify that the navigation properties were set properly as well, based on the previous pluralization ... open the Properties window. Or, right-click anywhere on the Designer window and select Properties from the context menu. In the Properties window of the EDM, shown in Figure 1 2- 10,...

Ngày tải lên: 18/06/2014, 16:20

... the EF40Entities data model from the EF40Data project. The second variable defines the ProductModel entity to which you add a record. Last is CHAPTER 13 ■ DATABINDING WITH THE ENTITY FRAMEWORK ... (nameTextBox.Text.Length > 0) { productModelBindingSource.EndEdit(); prodMods = new EF40Data.ProductModel(); prodMods.Name = nameTextBox.Text; context.ProductModels.AddObject...

Ngày tải lên: 18/06/2014, 16:20

... AdventureWorks 200 8Entities1): try { CHAPTER 5 ■ WORKING WITH ENTITIES 88 using (var context = new AdventureWorks 200 8Entities1()) { ProductModel prodModel = new ProductModel(); prodModel.Name ... ([BusinessEntityID] = @2) ',N' @0 nvarchar (8) ,@1 datetime2(7),@2 int', @0= N'Mr.',@1=' 200 9 -0 9 -0 7 11 :41 :25.1656711',@2=2 28 On...

Ngày tải lên: 20/06/2014, 08:20

... ',@12 =45 . 20, @13=5,@ 14= N'S ',@15=N'M ',@16=N'M ',@17=1,@ 18= 129,@19=' 200 9 -0 9 -0 7  12 :07 :26. 04 3 9 48 2',@ 20= &apos ;00 000 000 -0 0 0 0- 000 0 -0 0 0 0- 000 000 000 000 ',@21=' 200 9 -0 9 -0 7  ... datetime2(7)', @0= N'Inverted Kayaba',@1=N'IKAYA-R 209 ', @2=1,@3=1, @4= N'Red&apos...

Ngày tải lên: 20/06/2014, 08:20

... EF40Data.EF40Entities context; EF40Data.ProductModel prodMods; bool isNew; The next step is to implement the isNew variable, which must be placed in the AddingNew event of the productModelBindingSource. ... (nameTextBox.Text.Length > 0) { productModelBindingSource.EndEdit(); prodMods = new EF40Data.ProductModel(); prodMods.Name = nameTextBox.Text; context.ProductModels....

Ngày tải lên: 20/06/2014, 08:20

... field, 116 Product class, 90 Product Model Binding Navigator, 244 Product Model ID, 244 Production.Product table, 87 Production.ProductModel table, 87 ProductModel class, 88 , 236, 244 ProductModel ... 239, 242 – 243 ProductModelID column, 90, 244 ProductModelID property, 236 ProductModelID value, 90 91 ProductModelName column, 241 Products class, 2 38 239, 244 Products enti...

Ngày tải lên: 20/06/2014, 08:20

... 3- 14. Association properties CHAPTER 3 ■ THE ENTITY DATA MODEL INSIDE AND OUT 44 Figure 3-1 2. Entity with complex type property Even though you have added a complex property to the entity, ... a new AdventureWorks 200 8Entities object. /// </summary> public AdventureWorks 200 8Entities(EntityConnection connection) : base(connection, "AdventureWorks 200 8E...

Ngày tải lên: 18/06/2014, 16:20

... AdventureWorks 200 8Entities1): try { CHAPTER 5 ■ WORKING WITH ENTITIES 88 using (var context = new AdventureWorks 200 8Entities1()) { ProductModel prodModel = new ProductModel(); prodModel.Name ... ([BusinessEntityID] = @2) ',N' @0 nvarchar (8) ,@1 datetime2(7),@2 int', @0= N'Mr.',@1=' 200 9 -0 9 -0 7 11 :41 :25.1656711',@2=2 28 On...

Ngày tải lên: 18/06/2014, 16:20