gmat quant topic 9 - miscellaneous solutions

gmat quant topic 9 - miscellaneous solutions

gmat quant topic 9 - miscellaneous solutions

... be, x-1, x-2, x-3, x-4, x-5 So, 38+x+x-1+x-2+x-3+x-4+x-5 =90 6x=67 x=67/6>11 32. Let attend fee be x, number of person be y: Form 1, (x-0.75)(y+100)=xy 100x-0.75y-75=0 From 2, (x+1.5)(y-100)=xy ... 20(y-x). For 1, we knew that 20(2y-x)=2400, insufficient to find y-x For 2, we knew that 20(y+2-x)=440, we can get 20(y-x)=400. It's sufficient. Answer is B 29. For 1, country A can s...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 2 statistics solutions

gmat quant topic 2 statistics solutions

... differences: 10 2 + 9 2 + 8 2 + 7 2 + 6 2 + 5 2 + 4 2 + 3 2 + 2 2 + 1 2 + 0 2 + (-1 ) 2 + (-2 ) 2 (-3 ) 2 + (-4 ) 2 + (-5 ) 2 + (-6 ) 2 (-7 ) 2 + (-8 ) 2 + ( -9 ) 2 + (-1 0) 2 = 770. Average ... answer is D. 18. Range before transaction: 11 2-4 5=67 Range after transaction: (94 +24 )-( 5 6-2 0)=11 8-3 6=82 The difference is: 8 2-6 7=15 A...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 4 - numbers solutions

gmat quant topic 4 - numbers solutions

... integer, then 9 b will always have a units digit of 1 or 9. We can show this by listing the first few powers of 9: 9 1 = 9 9 2 = 81 9 3 = 7 29 9 4 = 6561 The units digit of the powers of 9 alternates ... 7 9 3 1 7 9 7, 9, 3, 1, repeat 9 9 1 9 1 9 1 9, 1, repeat The patterns repeat at least every fourth term, so let's find the units digit of (4) (2 x + 1) (3...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 5 - geometry solutions

gmat quant topic 5 - geometry solutions

... question: What is BC? (1) INSUFFICIENT: If angle ABD = 60°, ΔABD must be a 3 0-6 0 -9 0 triangle. Since the proportions of a 3 0-6 0 -9 0 triangle are x: x : 2x (shorter leg: longer leg: hypotenuse), and AD ... can solve for CD by recognizing that ΔACD must be a 3 0-6 0 -9 0 triangle (since it is a right triangle and two of its sides fit the 3 0- 60 -9 0 ratio), or by using th...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 8 - probability solutions

gmat quant topic 8 - probability solutions

... 2-by-2 grids available in any x- by -x grid. Testing this out with several different values for x should enable you to see that there are possible 2-by- 2 grids available in any x- by- x ... .90 × .90 = .81 = 81%. On the other hand if there are 7 questions on the exam, Patty's probability of answering all the questions correctly is equal to .90 × .90 × .90 × .90 × .90 × .90 ... h...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 1 (general arithmetic) solutions

gmat quant topic 1 (general arithmetic) solutions

... have a queen-sized bed, while 25 have a king-sized bed. Of the non-smoking rooms (let's call this unknown n), 60% or .6n have queen-sized beds. 10 rooms are non-smoking with king-sized beds. Let's ... right-handed, then three of them must be left-handed. Add that to the three left-handed girls, and we know that a total of 6 students are left-handed. GIRLS BOYS TOTALS LEFT-HANDED 3...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 3 (inequalities + absolute value) solutions

gmat quant topic 3 (inequalities + absolute value) solutions

... correct answer is D. 25. X-2Y < -6 => -X + 2Y > 6 Combined X - Y > -2 , we know Y > 4 X - Y > -2 => -2 X + 2Y < 4 Combined X - 2Y < -6 , we know -X < -2 => X > 2 Therefore, ... 0-1 0 1 0-2 0 2 0-3 0 3 0-4 0 4 0-5 0 5 0-6 0 60+ speed And since Missile 2's rate doubles every 10 minutes, Missile 2 will be travelin...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 6 co-ordinate geometry solutions

gmat quant topic 6 co-ordinate geometry solutions

... – 9) ÷ (5 – 4) = -1 /1 = -1 . (B) (-1 – (-2 )) ÷ (3 – 4) = 1/ (-1 ) = -1 . (C) (6 – 9) ÷ (-1 – (-4 )) = -3 /3 = -1 . (D) (5 – 2) ÷ (2 – (-3 )) = 3/5. (E) (1 – 2) ÷ (7 – 6) = -1 /1 = -1 . The only pair ... the y-coordinate. (A) (-1 4, 10) y = -5 /7 (-1 4) + 5 = 15; this does not match the given y-coordinate. (B) (-7 , 5) y = -5 /7 (-7 ) + 5...

Ngày tải lên: 14/05/2014, 16:55

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gmat quant topic 7 - p and c sol

gmat quant topic 7 - p and c sol

... victory circles: Albert-GOLD, Cami-GOLD, Bob-GOLD. Bob-GOLD, Albert-GOLD, Cami-GOLD. Bob-GOLD, Cami-GOLD, Albert-GOLD. Cami- GOLD, Albert-GOLD, Bob-GOLD. Cami-GOLD, Bob-GOLD, Albert-GOLD. Each unique ... GOLD-SILVER-BRONZE victory circles. (Combination 2) 12 unique GOLD- GOLD-SILVER victory circles. (Combination 3) 12 unique GOLD-SILVER-SILVER victory circles. (Combination 4) 4 unique GOLD-...

Ngày tải lên: 14/05/2014, 16:55

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Instructor Notes Module 9: Designing - Solutions with Microsoft Technologies

Instructor Notes Module 9: Designing - Solutions with Microsoft Technologies

... PowerPoint ® file P 09_ 1608a.ppt ! Module 9, “Designing Solutions with Microsoft Technologies” ! Activity 9. 1, “Identify Operating System Requirements” ! Activity 9. 2, “Identifying System ... options for connecting solutions to existing (legacy) data and systems. Presentation: 195 Minutes Activity: 150 Minutes 2 Instructor Notes Module 9: Designing Solutions wit...

Ngày tải lên: 18/10/2013, 18:15

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