gmat quant topic 9 - miscellaneous solutions
gmat quant topic 9 - miscellaneous solutions
...
be, x-1, x-2, x-3, x-4, x-5
So, 38+x+x-1+x-2+x-3+x-4+x-5 =90
6x=67
x=67/6>11
32.
Let attend fee be x, number of person be y:
Form 1, (x-0.75)(y+100)=xy 100x-0.75y-75=0
From 2, (x+1.5)(y-100)=xy ... 20(y-x).
For 1, we knew that 20(2y-x)=2400, insufficient to find y-x
For 2, we knew that 20(y+2-x)=440, we can get 20(y-x)=400. It's sufficient.
Answer is B
29.
For 1, country A can s...
gmat quant topic 2 statistics solutions
... differences: 10
2
+ 9
2
+ 8
2
+ 7
2
+ 6
2
+ 5
2
+ 4
2
+ 3
2
+ 2
2
+ 1
2
+ 0
2
+ (-1 )
2
+ (-2 )
2
(-3 )
2
+ (-4 )
2
+ (-5 )
2
+ (-6 )
2
(-7 )
2
+ (-8 )
2
+ ( -9 )
2
+ (-1 0)
2
= 770.
Average ... answer is D.
18.
Range before transaction:
11 2-4 5=67
Range after transaction:
(94 +24 )-( 5 6-2 0)=11 8-3 6=82
The difference is: 8 2-6 7=15
A...
gmat quant topic 4 - numbers solutions
... integer, then 9
b
will always have a units digit of 1 or 9. We can show this by listing the first
few powers of 9:
9
1
= 9
9
2
= 81
9
3
= 7 29
9
4
= 6561
The units digit of the powers of 9 alternates ... 7 9 3 1 7 9 7, 9, 3, 1, repeat
9 9 1 9 1 9 1 9, 1, repeat
The patterns repeat at least every fourth term, so let's find the units digit of (4)
(2
x
+ 1)
(3...
gmat quant topic 5 - geometry solutions
... question:
What is BC?
(1) INSUFFICIENT: If angle ABD = 60°, ΔABD must be a 3 0-6 0 -9 0 triangle. Since the
proportions of a 3 0-6 0 -9 0 triangle are x: x : 2x (shorter leg: longer leg: hypotenuse), and AD ... can solve for CD by recognizing
that ΔACD must be a 3 0-6 0 -9 0 triangle (since it is a right triangle and two of its sides fit the 3 0-
60 -9 0 ratio), or by using th...
gmat quant topic 8 - probability solutions
... 2-by-2 grids available in any
x-
by
-x
grid. Testing this out with several different values for
x
should enable you to see that there are possible 2-by-
2 grids available in any
x-
by-
x
... .90 × .90 = .81 = 81%. On the other hand if there are 7 questions on the exam,
Patty's probability of answering all the questions correctly is equal to .90 × .90 × .90 × .90 × .90 × .90 ... h...
gmat quant topic 1 (general arithmetic) solutions
... have a queen-sized bed, while 25 have a king-sized bed.
Of the non-smoking rooms (let's call this unknown n), 60% or .6n have queen-sized beds.
10 rooms are non-smoking with king-sized beds.
Let's ... right-handed, then three of them must be left-handed. Add that to the three left-handed
girls, and we know that a total of 6 students are left-handed.
GIRLS BOYS TOTALS
LEFT-HANDED 3...
gmat quant topic 3 (inequalities + absolute value) solutions
... correct answer is D.
25.
X-2Y < -6 => -X + 2Y > 6
Combined X - Y > -2 , we know Y > 4
X - Y > -2 => -2 X + 2Y < 4
Combined X - 2Y < -6 , we know -X < -2 => X > 2
Therefore, ... 0-1 0 1 0-2 0 2 0-3 0 3 0-4 0 4 0-5 0 5 0-6 0 60+
speed
And since Missile 2's rate doubles every 10 minutes, Missile 2 will be travelin...
gmat quant topic 6 co-ordinate geometry solutions
... – 9) ÷ (5 – 4) = -1 /1 = -1 .
(B) (-1 – (-2 )) ÷ (3 – 4) = 1/ (-1 ) = -1 .
(C) (6 – 9) ÷ (-1 – (-4 )) = -3 /3 = -1 .
(D) (5 – 2) ÷ (2 – (-3 )) = 3/5.
(E) (1 – 2) ÷ (7 – 6) = -1 /1 = -1 .
The only pair ... the y-coordinate.
(A) (-1 4, 10)
y = -5 /7 (-1 4) + 5 = 15; this does not match the given y-coordinate.
(B) (-7 , 5)
y = -5 /7 (-7 ) + 5...
gmat quant topic 7 - p and c sol
... victory circles: Albert-GOLD, Cami-GOLD,
Bob-GOLD. Bob-GOLD, Albert-GOLD, Cami-GOLD. Bob-GOLD, Cami-GOLD, Albert-GOLD. Cami-
GOLD, Albert-GOLD, Bob-GOLD. Cami-GOLD, Bob-GOLD, Albert-GOLD. Each unique ... GOLD-SILVER-BRONZE victory circles. (Combination 2) 12 unique GOLD-
GOLD-SILVER victory circles. (Combination 3) 12 unique GOLD-SILVER-SILVER victory circles.
(Combination 4) 4 unique GOLD-...
Instructor Notes Module 9: Designing - Solutions with Microsoft Technologies
... PowerPoint
®
file P 09_ 1608a.ppt
!
Module 9, “Designing Solutions with Microsoft Technologies”
!
Activity 9. 1, “Identify Operating System Requirements”
!
Activity 9. 2, “Identifying System ... options for connecting solutions to existing (legacy)
data and systems.
Presentation:
195 Minutes
Activity:
150 Minutes
2 Instructor Notes Module 9: Designing Solutions wit...