... median.x yDATA SET MEDIAN1 6 1, 1, 5, 6, 6, 7 5.52 5 1, 2, 5, 5, 6, 7 53 4 1, 3, 4, 5, 6, 7 4.54 3 1, 3, 4, 5, 6, 7 4.55 2 1, 2, 5, 5, 6, 7 5 6 1 1, 1, 5, 6, 6, 7 5.5Regardless of the values ... – 4y + xy + 2y) 6 = y + 3 (3x + xy) 6 = y + 3 x (y + 3) 6 = y + 3 x (y + 3) = 6 (y + 3)x = 6. Given that y > 6 and substituting x = 6, the terms of the set ... 6 – 4y, 6, y, y + 6, 2y, 6 y. The median of a set of six terms is the mean of the third and fourth terms (the two middle terms). The mean of the terms y and y + 6 is (2y + 6) ...