gmat quant topic 5 - geometry solutions
gmat quant topic 5 - geometry solutions
... hypotenuse = 4 /5.
For
ABD
, the ratio of the longer leg to the hypotenuse = 5/
AB
.
Thus, 4 /5 = 5/
AB
, or
AB
= 25/ 4 = 6. 25
(2) SUFFICIENT: If
DE
= 4, then
BDE
is a 3-4 -5 right triangle. ... angles = (n - 2) * 180 = 360
From 1: sum of the remaining angles are 360 - 2*90 = 180
From 2: either x + 2x = 180 => x = 60
Or x = 90/2 = 45 and y = 180 - 45 = 1 35...
gmat quant topic 2 statistics solutions
... y
DATA SET MEDIAN
1 6 1, 1, 5, 6, 6, 7 5. 5
2 5 1, 2, 5, 5, 6, 7 5
3 4 1, 3, 4, 5, 6, 7 4 .5
4 3 1, 3, 4, 5, 6, 7 4 .5
5 2 1, 2, 5, 5, 6, 7 5
6 1 1, 1, 5, 6, 6, 7 5. 5
Regardless of the values of ... 7, t could be 5.
According to 1, s=0.
Combining 1 and 2, s=t=0
Answer is C
21. First, we arrange the 10 ,5, -2 ,-1 , -5 and 15 at sequence: -5 , -2 , -1 , 5, 1...
gmat quant topic 4 - numbers solutions
... b
2
( 15 + 1)
2
2 25 2( 15) 1 =30 1
2
( 15 + 2)
2
2 25 2( 15) 2 =60 2
2
( 15 + 3)
2
2 25 2( 15) 3 =90 3
2
.
.
.
.
.
.
.
.
.
.
.
.
( 15 + 15)
2
2 25 2( 15) 15 = 450 15
2
TOTALS = 15( 2 25) =33 75 (30+ 450 )/2 × 15 = ... mean of these 50 integers = (201 + 250 ) / 2 = 2 25. 5
Therefore, the sum of these 50 integers = 50 x 2 25. 5 = 11,2 75, which falls between 11,000 and 12...
gmat quant topic 8 - probability solutions
... 41 /50
39. 1/221
40. 1/1770
41. 2/9
42. 1/216
43. 3/ 25
44. $3.6
45. 7/8
46. 9/10
47. 143/ 152
48. 13/14
49. 13/18
50 . 0
51 . 1 /5
52. 271/1000
53 . 7/216
54 . 2/ 25
55. ½
56 . 8/ 25
57. 1/24
58 . B
59 . ... Beat Bill Total Combinations
2 1 35 1 × 35 = 35
3 2 33 2 × 33 = 66
4 3 30 3 × 30 = 90
5 4 26 4 × 26 = 104
6 5 21 5 × 21 = 1 05
7 6 15 6 × 15 = 90
8 5 10 5 ×...
gmat quant topic 9 - miscellaneous solutions
...
be, x-1, x-2, x-3, x-4, x -5
So, 38+x+x-1+x-2+x-3+x-4+x -5 = 90
6x=67
x=67/6>11
32.
Let attend fee be x, number of person be y:
Form 1, (x-0. 75) (y+100)=xy 100x-0.75y- 75= 0
From 2, (x+1 .5) (y-100)=xy ... must include a 2, a 5, and a 7 (because 2 x 5 x 7 = 70). But this fact by itself
does not tell us the order of the ratios. In other words, is it 2 - 5 - 7 or 7 -...
gmat quant topic 6 co-ordinate geometry solutions
... of -1 .
(A) (8 – 9) ÷ (5 – 4) = -1 /1 = -1 .
(B) (-1 – (-2 )) ÷ (3 – 4) = 1/ (-1 ) = -1 .
(C) (6 – 9) ÷ (-1 – (-4 )) = -3 /3 = -1 .
(D) (5 – 2) ÷ (2 – (-3 )) = 3 /5.
(E) (1 – 2) ÷ (7 – 6) = -1 /1 = -1 .
The ... (12, -4 )
y = -5 / 7(12) + 5 = -6 0/7 + 5, which will not equal an integer; this does not match the
given y-coordinate.
(D) (-1 4...
gmat quant topic 1 (general arithmetic) solutions
... 60 0 80
Short-
stemmed
5 15 20 40
TOTAL 25 75 20 120
Now we can answer the question. 20 of the 80 long-stemmed roses are red, or 20/80 = 25% .
The correct answer is B.
5
10
0 –
p
=
15
p
12.
The ... proportion:
5p = 150 0 – 15p
p = 75
This means that there are a total of 75 pink roses and 25 red roses. Now we can
fill out the rest of the double-set matrix:
Red Pink White TOTAL
Lo...
gmat quant topic 3 (inequalities + absolute value) solutions
... correct answer is D.
25.
X-2Y < -6 => -X + 2Y > 6
Combined X - Y > -2 , we know Y > 4
X - Y > -2 => -2 X + 2Y < 4
Combined X - 2Y < -6 , we know -X < -2 => X > 2
Therefore, ... base.
0.04 = 1/ 25 = 5
-2
We can rewrite the question in the following way: "Is 5
n
< 5
-2
?"
The only way 5
n
could b...
gmat quant topic 7 - p and c sol
... victory circles: Albert-GOLD, Cami-GOLD,
Bob-GOLD. Bob-GOLD, Albert-GOLD, Cami-GOLD. Bob-GOLD, Cami-GOLD, Albert-GOLD. Cami-
GOLD, Albert-GOLD, Bob-GOLD. Cami-GOLD, Bob-GOLD, Albert-GOLD. Each unique ... × 5
22.
5
C
3
×
4
C
3
23. 5 ! × 2 !
24.
5
C
3
+
5
C
4
25.
3
C
2
× 1 ×
3
C
2
26. 3 ! × 2 ! × 2 ! × 2 !
27. TTTHHH, HTTTHH, HHTTTH, HHHTTT; total 4
28. The only combination of...
