Cryptography and Network Security Chapter 2 pdf

... m n o p q r s t u v w x y z 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25  then have Caesar cipher as: c ... decryptions/µs 32 2 32 = 4.3 × 10 9 2 31 µs = 35.8 minutes 2. 15 milliseconds 56 2 56 = 7 .2 × 10 16 2 55 µs = 11 42 years 10.01 hours 128 2 128 = 3.4 ×...

Ngày tải lên: 06/03/2014, 16:20

... security detection, security audit trails, security recovery recovery Model for Network Security Model for Network Security Model for Network Security Model for Network Security  using this ... • computer, network, internet security computer, network, internet security  X.800 standard X.800 standard  security attacks, services, mechanisms security atta...

Ngày tải lên: 06/03/2014, 16:20

... noisy channels Output FeedBack (OFB) Output FeedBack (OFB) Cryptography and Cryptography and Network Security Network Security Chapter 6 Chapter 6 Fourth Edition Fourth Edition by William ... = (i + 1) (mod 25 6) i = (i + 1) (mod 25 6) j = (j + S[i]) (mod 25 6) j = (j + S[i]) (mod 25 6) swap(S[i], S[j]) swap(S[i], S[j]) t = (S[i] + S[j]) (mod 25 6) t = (S[i] + S...

Ngày tải lên: 06/03/2014, 16:20

... E Km Km [ [ X X i-1 i-1 ] ] ANSI X9.17 PRG ANSI X9.17 PRG Cryptography and Cryptography and Network Security Network Security Chapter 7 Chapter 7 Fourth Edition Fourth Edition by William ... numbers” create “random numbers”  although are not truly random although are not truly random  can pass many tests of “randomness” can pass many tests of “randomness”  known as...

Ngày tải lên: 06/03/2014, 16:20

... factorizations and using least powers and using least powers  eg. eg. 300 300 =2 =2 1 1 x3 x3 1 1 x5 x5 2 2 18 =2 18 =2 1 1 x3 x3 2 2 hence hence GCD(18,300) =2 GCD(18,300) =2 1 1 x3 x3 1 1 x5 x5 0 0 =6 =6 ... 20 0 is: list of prime number less than 20 0 is: 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61...

Ngày tải lên: 06/03/2014, 16:20

... x a) mod n f = (f x a) mod n return f return f Cryptography and Cryptography and Network Security Network Security Chapter 9 Chapter 9 Fourth Edition Fourth Edition by William ... d < < 160 160 G G d =23 d =23   23 23 x x 7=161= 7=161= 10 10 x x 160+1 160+1 0? 0? 2  2  PU={7,1...

Ngày tải lên: 06/03/2014, 16:20

... Equivalent Security Equivalent Security Symmetric scheme (key size in bits) ECC-based scheme (size of n in bits) RSA/DSA RSA/DSA (modulus size in bits) 56 56 1 12 5 12 80 160 1 024 1 12 224 20 48 128 25 6 ... y A A x x B B mod 353 = mod 353 = 40 40 23 3 23 3 = 160 = 160 (Bob) (Bob) Cryptography and Cryptography and Network Security Network Securi...

Ngày tải lên: 15/03/2014, 17:20

... (DSA) (DSA)  creates a 320 bit signature creates a 320 bit signature  with 5 12- 1 024 bit security with 5 12- 1 024 bit security  smaller and faster than RSA smaller and faster than RSA  a digital ... choose a large prime p = 2 p = 2 L L • where L= 5 12 to 1 024 bits and is a multiple of 64 where L= 5 12 to 1 024 bits and is a multiple of 64 • and q is a prime...

Ngày tải lên: 15/03/2014, 17:20

... 59 27 34 2 42 10 50 18 58 26 33 1 41 9 49 17 57 25 (c) Expansion Permutation (E) 32 1 2 3 45 4 5 6 7 89 8 9 10 11 12 13 12 13 14 15 16 17 16 17 18 19 20 21 20 21 22 23 24 25 24 25 26 27 28 29 28 ... 99e9b 723 0bae3b9e 4 0 526 1d3 824 311a20 0bae3b9e 424 15649 5 3 325 340136002c25 424 15649 18b3fa41 6 123 a2d0d0 426 2a1c 18b3fa41 9616fe23 7 021 f 120 b1c130611...

Ngày tải lên: 07/12/2013, 11:53

... 121 ] For p = 3 and n = 2, the 3 2 = 9 polynomials in the set are 0 x 2x 1 x + 1 2x + 1 2 x + 2 2x + 2 For p = 2 and n = 3, the 2 3 = 8 the polynomials in the set are 0 x + 1 x 2 + x 1 x 2 x 2 ... 4/16/ 128 6 /24 /1 92 8/ 32/ 256 Plaintext block size (words/bytes/bits) 4/16/ 128 4/16/ 128 4/16/ 128 Number of rounds 10 12 14 Round key size (words/bytes/bits) 4/16/ 12...

Ngày tải lên: 18/02/2014, 08:20