... by substitution into the differential equation and, as expected, are found to be -2 and respectively. Thenx(t) = -2 + + + + and the constants and are determined by the three initial conditions.The ... 1)(3.1)where A and B are constants. Hence, using Table 2.1, it follows that = A + Be-’(3.2)Therefore, if A and B were known, we would have the solution. The conditions onA and B are that ... in the denominator may be factored, and expanded in partial fractionsx(s) = + 9s 8 A B + + 1) = s-2 (3.7)To find A, multiply both sides of Eq. (3.7) by and then set = 0; the result isA=-8(-2)(1)(2)(-l)...