Tài liệu Random Numbers part 5 pptx
... Watson) (1, 0) (51 , 6, 3, 1, 0) (2, 1, 0) (52 , 3, 0) (3, 1, 0) (53 , 6, 2, 1, 0) (4, 1, 0) (54 , 6, 5, 4, 3, 2, 0) (5, 2, 0) (55 , 6, 2, 1, 0) (6, 1, 0) (56 , 7, 4, 2, 0) (7, 1, 0) (57 , 5, 3, 2, 0) (8, ... 1, 0) ( 15, 1, 0) ( 65, 4, 3, 1, 0) (16, 5, 3, 2, 0) (66, 8, 6, 5, 3, 2, 0) (17, 3, 0) (67, 5, 2, 1, 0) (18, 5, 2, 1, 0) (68, 7, 5, 1, 0) (19, 5, 2, 1, 0) (69, 6, 5, 2, 0) (20,...
Ngày tải lên: 26/01/2014, 15:20
... == 0.0); return -log(dum); } 288 Chapter 7. Random Numbers Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0 -52 1-43108 -5) Copyright (C) 1988-1992 by Cambridge University ... e −y dy (7.2 .5) which is distributed exponentially. This exponential distribution occurs frequently in real problems, usually as the distribution of waiting times between independe...
Ngày tải lên: 26/01/2014, 15:20
... c2[NITER]={ 0x4b0f3b58L, 0xe874f0c3L, 0x6 955 c5a6L, 0x55a7ca46L}; for (i=0;i<NITER;i++) { Perform niter iterations of DES logic, using a simpler (non-cryptographic) nonlinear func- tion instead of DES’s. 7 .5 Random ... North America). random floating-point number. They are not very random for that purpose; see Knuth [1] . Examples of acceptable uses of these random bits are: (i)...
Ngày tải lên: 26/01/2014, 15:20
Tài liệu Random Numbers part 7 pptx
... = e 5z dz so that s = 1 5 e 5z ,z= 1 5 ln(5s)(7.6.7) Then ρdz = ds, and the limits −1 <z<1become .001 35 <s<29.682.The program fragment now looks like this 308 Chapter 7. Random Numbers Sample ... PC –1 1 1 604D1DCE 50 9C0C23 0.2 758 98 0.219120 99 1 99 D97F 857 1 A66CB41A 0.208204 0.849246 –99 99 1 7822309D 64300984 0.034307 0.3 752 90 99 99 99 D7F376F0 59 BA89EB 0.838...
Ngày tải lên: 26/01/2014, 15:20
Tài liệu Database Systems - Part 5 pptx
... (Day 5) Page 1 Mark Llewellyn COP 4710: Database Systems Spring 2004 Introduction to Data Modeling – Part 2 BÀI 5, 1 ngày COP 4710: Database Systems Spring 2004 Introduction to Data Modeling – Part ... entity. Partial generalization/specialization: Some higher-level entities may not belong to any lower-level entity set. – Partial generalization is the default case. (Recall that total...
Ngày tải lên: 24/12/2013, 12:16
Tài liệu SQL Basic part 5 pptx
... INTO table_name VALUES (value1, value2, ) Hoặc cũng có thể chỉ rõ cột mà mình muốn insert dữ liệu : Trích: INSERT INTO table_name (column1, column2, ) VALUES (value1, value2, ) Insert
Ngày tải lên: 26/01/2014, 13:20
Tài liệu Random Numbers part 1 ppt
... America). Chapter 7. Random Numbers 7.0 Introduction It may seem perverse to use a computer, that most precise and deterministic of all machines conceived by the human mind, to produce random numbers. ... Knuth [1] §3 .5 for discussion and references). One sometimes hears computer-generated sequences termed pseudo -random, while the word random is reserved for the outputof an intrinsi...
Ngày tải lên: 26/01/2014, 15:20
Tài liệu Random Numbers part 2 doc
... 2731 14000 154 1 2 957 21870 1291 4621 31104 6 25 657 1 139968 2 05 2 957 3 2 25 29282 1 255 6173 81000 421 17117 134 456 281 28411 2 26 overflow at im ia ic 86436 1093 18 257 12 150 0 1021 256 73 259 200 421 54 773 2 27 117128 ... 24749 12 150 0 2041 256 73 31 250 0 741 66037 2 28 1 458 00 3661 30809 1 750 00 2661 36979 233280 1861 49297 244944 159 7 51 749 2 29 139968 3877 2 957 3 2...
Ngày tải lên: 26/01/2014, 15:20
Tài liệu Random Numbers part 4 ppt
... 290 Chapter 7. Random Numbers Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0 -52 1-43108 -5) Copyright (C) 1988-1992 by Cambridge University ... produce the following routine: 294 Chapter 7. Random Numbers Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0 -52 1-43108 -5) Copyright (C) 1988-1992 by Cambridge University...
Ngày tải lên: 26/01/2014, 15:20