Tài liệu Basic Troubleshooting Process 1 ppt

... 1- 5 Semester 8 Internetwork Troubleshooting v1.0 - Lab 1. 2.9 .1 Copyright  20 01, Cisco Systems, Inc. Lab 1. 2.9 .1: Basic Troubleshooting Process 1 WAN Network 2 19 2 .16 8.0.96 /30 WAN ... Network 1 192 .16 8.0 .10 0 /30 SanJose1 Objective In this lab you work with applying the basic troubleshooting model to a simple and common network problem. The model steps...

Ngày tải lên: 24/01/2014, 19:20

... 1- 4 Semester 8 Internetwork Troubleshooting v1.0 - Lab 1. 2.9.3 Copyright  20 01, Cisco Systems, Inc. Lab 1. 2.9.3: Basic Troubleshooting Process 3 WAN Network 2 19 2 .16 8.0.96 /30 WAN ... Command) window of the workstation, ping SanJose1’s Ethernet interface (19 2 .16 8.0.33) and one of the WAN interfaces (19 2 .16 8.0.97 or 19 2 .16 8.0 .10 1). Both commands should wor...

Ngày tải lên: 24/01/2014, 19:20

... o'clock. So at 5 o'clock we 7. I'm going to write letters from 10 until 11 . So at 10 .30 I 8. From 11 till 6 I'm going to prepare for my exam. So at 2 o'clock I 226 II. ... the same height) 10 . Is Athens as noisy as Cairo? (Are they equally noisy?) 11 . Italy is not as (so) hot as Iraq. 12 . The exam was not as (so) difficult as 1 thought. Irregular 1....

Ngày tải lên: 24/01/2014, 07:20

... 1- 4 Semester 8 Internetwork Troubleshooting v1.0 - Lab 1. 2.9.2 Copyright  20 01, Cisco Systems, Inc. Lab 1. 2.9.2: Basic Troubleshooting Process 2 WAN Network 2 19 2 .16 8.0.96 /30 WAN ... Troubleshooting Process 2 WAN Network 2 19 2 .16 8.0.96 /30 WAN Network 1 192 .16 8.0 .10 0 /30 SanJose1 Objective Apply the basic troubleshooting model from the last l...

Ngày tải lên: 24/01/2014, 19:20

... 1- 4 Semester 8 Internetwork Troubleshooting - Lab 1. 2.9.4 Copyright  20 01, Cisco Systems, Inc. Lab 1. 2.9.4: Basic Troubleshooting Process 4 WAN Network 2 19 2 .16 8.0.96 /30 WAN Network 1 192 .16 8.0 .10 0 ... Ethernet interface on any router: IP address: 19 2 .16 8.0.34 (or any valid host in subnet 19 2 .16 8.0.32 /27) Subnet mask: 255.255.255.224 Default Gateway:...

Ngày tải lên: 24/01/2014, 19:20

... Builder19 10 Using the Quick Tour Introduction to Oracle: SQL and PL/SQL Using Procedure Builder19Ć8 Procedure Builder Components Procedure Builder Components Basics of Procedure Builder 19 11 Procedure ... Procedure Builder19 14 4 The Object Navigator 1 5 2 4 4 5 3 Navigator drop down list1 Subobject indicator2 Type icon3 Object name 4 Find field5 Basics of Procedure Builder 19 15 Th...

Ngày tải lên: 10/12/2013, 17:15

... 64, H: 12 8, I: 256, J: 512 , K: 10 24, L: 2048, M: 4096, N: 819 2, O: 16 384, P: 32768, Q: 65536, R: 13 1072, S: 26 214 4, T: 524288, U: 10 48576, V: 209 715 2, W: 419 4304, X: 8388608, Y: 16 777 216 , Z: ... Hận Đời Không Đối Thủ 14 - 01- 2006, 01: 40 PM 1. Giới thiệu về Registry: Registry là một cơ sở dữ liệu dùng để lưu trữ thông số kỹ thuật của Windows. Nó ghi ... "...

Ngày tải lên: 11/12/2013, 17:15

... 1 D4H 51 (12 VD) 52* 28 ** 17 (7VD) 14 8 2 D5H 13 13 3 D10H 20 20 4 D11H 23 23 D8E 02 02 5 D9E 33 33 6 D12E 5 22 13 40 7 D13E 10 14 24 8 D14E 5 5 9 D16E 3 3 10 D18E 16 16 11 D19E 10 ... 14 600 216 00 280 kN 25500 355,2 kN 18 Sức kéo dài hạn (kG) 12 000 11 700 16 050 18 8 kN 19 000 224 kN 19 Tốc ñộ cấu tạo (km/h) 11 4 80 96 10 0 10 5 12 0 20 Tốc ñộ dài...

Ngày tải lên: 11/12/2013, 21:15

... tụ. 10 . Lập luận sau sai vì sao? 1 − 1 2 + 1 3 − 1 4 + 1 5 − 1 6 + ··· =1+ ( 1 2 − 1) + 1 3 +( 1 4 − 1 2 )+ 1 5 +( 1 6 − 1 3 )+··· = (1+ 1 2 + 1 3 + 1 4 + ···) − 1 − 1 2 − 1 3 − 1 4 −··· = (1+ 1 2 + 1 3 + 1 4 + ... ··· c) 1 1.3 + 1 4.6 + 1 7.9 + 1 10 .12 + 1 13 .15 + ··· d) 1 2 − 1 4 + 1 8 − 1 16 + 1 32 + ··· e) ∞  k=0 2...

Ngày tải lên: 12/12/2013, 22:15

Ngày tải lên: 13/12/2013, 05:15